JAMB Mathematics 1989 past questions and answers

50 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Fractions, Decimals and Approximation

Which of the following is in descending order?

  1. A.9/10, 4/5, 3/4, 17/10
  2. B.4/5, 9/10, 3/4, 17/20
  3. C.9/10, 17/20, 4/5, 3/4
  4. D.4/5, 9/10, 17/10, 3/4
Show the answer and explanation

Answer: C (9/10, 17/20, 4/5, 3/4)

Explanation

As decimals, 9/10 = 0.9, 17/20 = 0.85, 4/5 = 0.8 and 3/4 = 0.75. Only option C goes from largest to smallest.

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Question 2

Fractions, Decimals and Approximation

Evaluate 2700 000 × 0.03 ÷ 18 000

  1. A.4.5 × 100
  2. B.4.5 × 101
  3. C.4.5 × 102
  4. D.4.5 × 103
Show the answer and explanation

Answer: A (4.5 × 100)

Explanation

2,700,000 × 0.03 = 81,000, and 81,000 ÷ 18,000 = 4.5 = 4.5 × 100.

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Question 3

Fractions, Decimals and Approximation

The prime factors of 2520 are

  1. A.2, 9, 5
  2. B.2, 9, 7
  3. C.2, 3, 5, 7
  4. D.2, 3, 7, 9
Show the answer and explanation

Answer: C (2, 3, 5, 7)

Explanation

2520 = 2³ × 3² × 5 × 7, so its prime factors are 2, 3, 5 and 7 (9 is not prime).

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Question 4

Number Bases

If 12e = X7, find X where e = 12

  1. A.20
  2. B.15
  3. C.14
  4. D.12
Show the answer and explanation

Answer: A (20)

Explanation

12 in base 12 is 1 × 12 + 2 = 14 in base 10. In base 7, 14 = 2 × 7 + 0, which is 207.

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Question 5

Indices

Simplify ∛((64r−6)½)

  1. A.r/2
  2. B.2r
  3. C.1/(2r)
  4. D.2/r
Show the answer and explanation

Answer: D (2/r)

Explanation

The square root then cube root is the 1/6 power: (64r−6)1/6 = 2r−1 = 2/r.

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Question 6

Fractions, Decimals and Approximation

What is the difference between 0.007685 correct to three significant figures and 0.007685 correct to four places of decimal?

  1. A.10−5
  2. B.7 × 10−4
  3. C.8 × 10−5
  4. D.10−6
Show the answer and explanation

Answer: A (10−5)

Explanation

To 3 s.f. it is 0.00769; to 4 d.p. it is 0.0077. The difference is 0.0077 − 0.00769 = 0.00001 = 10−5.

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Question 7

Ratio, Percentages and Rates

If a : b = 5 : 8, x : y = 25 : 16, evaluate a/x : b/y

  1. A.125 : 128
  2. B.3 : 5
  3. C.3 : 4
  4. D.2 : 5
Show the answer and explanation

Answer: D (2 : 5)

Explanation

(a/x) ÷ (b/y) = (a/b) × (y/x) = 5/8 × 16/25 = 2/5. So the ratio is 2 : 5.

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Question 8

Commercial Arithmetic

Oke deposited N800.00 in the bank at the rate of 12½% simple interest. After some time the total amount was one and half times the principal. For how many years was the money left in the bank?

  1. A.2
  2. B.4
  3. C.5⅓
  4. D.8
Show the answer and explanation

Answer: B (4)

Explanation

The amount is 1.5 × 800 = N1,200, so the interest is N400. Each year earns 12½% of 800 = N100, so it took 4 years.

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Question 9

Mensuration of Solids

If the surface area of a sphere is increased by 44%, find the percentage increase in its diameter.

  1. A.44
  2. B.30
  3. C.22
  4. D.20
Show the answer and explanation

Answer: D (20)

Explanation

Surface area is proportional to the diameter squared. The area is multiplied by 1.44, so the diameter is multiplied by √1.44 = 1.2, a 20% increase.

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Question 10

Surds

Simplify 4 − 1/(2 − √3)

  1. A.2√3
  2. B.2 − √3
  3. C.−2 + √3
  4. D.2 − √3
Show the answer and explanation

Answer: D (2 − √3)

Explanation

Rationalise: 1/(2 − √3) = (2 + √3)/(4 − 3) = 2 + √3. Then 4 − (2 + √3) = 2 − √3.

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Question 11

Logarithms

Find p in terms of q if log3p + 3log3q = 3.

  1. A.(3/q)3
  2. B.(q/3)1/3
  3. C.(q/3)3
  4. D.(3/q)1/3
Show the answer and explanation

Answer: A ((3/q)3)

Explanation

log3(pq³) = 3, so pq³ = 27. Then p = 27/q³ = (3/q)³.

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Question 12

Indices

What are the values of y which satisfy the equation 9y − 4 × 3y + 3 = 0?

  1. A.−1 and 0
  2. B.−1 and 1
  3. C.1 and 3
  4. D.0 and 1.
Show the answer and explanation

Answer: D (0 and 1.)

Explanation

Let x = 3y: x² − 4x + 3 = 0, so x = 1 or 3. Then 3y = 1 gives y = 0 and 3y = 3 gives y = 1.

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Question 13

Algebraic Expressions

Make R the subject of the formula S = √((2R + T)/2RT)

  1. A.R = T/(TS2 − 1)
  2. B.R = T/(2(TS2 − 1))
  3. C.R = T/(TS2 + 1)
  4. D.R = T/(2(TS2 + 1))
Show the answer and explanation

Answer: B (R = T/(2(TS2 − 1)))

Explanation

Square both sides: 2RTS² = 2R + T. Collect R: R(2S²T − 2) = T, so R = T/(2(TS² − 1)).

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Question 14

Algebraic Expressions

Find the value of the expression (32/81)x3 − (64/27)x2 − (81/16)x−3 when x = −3/4

  1. A.10½
  2. B.10⅙
  3. C.3⅜
  4. D.−13½.
Show the answer and explanation

Answer: A (10½)

Explanation

x³ = −27/64, x² = 9/16 and x−3 = −64/27. The terms are −1/6, −4/3 and +12, which add up to 10½.

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Question 15

Variation

The cost of a dinner for a group of students is partly constant and partly varies directly as the number of students. If the cost is N74.00 when the number of students is 20, and N96.00 when the number is 30, find the cost when they are 15 students.

  1. A.N68.50
  2. B.N63.00
  3. C.N60.00
  4. D.N52.00
Show the answer and explanation

Answer: B (N63.00)

Explanation

C = a + ks. From 74 = a + 20k and 96 = a + 30k, k = 2.2 and a = 30. For 15 students C = 30 + 2.2 × 15 = N63.

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Question 16

Algebraic Expressions

If f(x) = 2x2 − 5x + 3, find f(x + 1)

  1. A.2x2 − x
  2. B.2x2 − x + 10
  3. C.4x2 + 3x + 2
  4. D.4x2 + 3x + 12
Show the answer and explanation

Answer: A (2x2 − x)

Explanation

f(x + 1) = 2(x + 1)² − 5(x + 1) + 3 = 2x² + 4x + 2 − 5x − 5 + 3 = 2x² − x.

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Question 17

Indices

Solve for a positive number x such that 2(x³ − x² − 2x) = 1

  1. A.4
  2. B.3
  3. C.2
  4. D.1
Show the answer and explanation

Answer: C (2)

Explanation

2 to a power equals 1 only when the power is 0: x³ − x² − 2x = x(x − 2)(x + 1) = 0. The positive solution is x = 2.

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Question 18

Algebraic Expressions

Simplify (324 − 4x2)/(2x + 18)

  1. A.2(x − 9)
  2. B.2(9 + x)
  3. C.81 − x2
  4. D.−2(x − 9)
Show the answer and explanation

Answer: D (−2(x − 9))

Explanation

324 − 4x² = (18 − 2x)(18 + 2x). Cancelling 2x + 18 leaves 18 − 2x = −2(x − 9).

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Question 19

Algebraic Expressions

Factorize completely y3 − 4xy + xy3 − 4y

  1. A.(y + xy)(y + 2)(y − 2)
  2. B.(y − xy)(y + 2)(y − 2)
  3. C.y(1 + x)(y + 2)(y − 2)
  4. D.y(1 − x)(y + 2)(y − 2)
Show the answer and explanation

Answer: C (y(1 + x)(y + 2)(y − 2))

Explanation

Group: y³(1 + x) − 4y(1 + x) = (1 + x)(y³ − 4y) = y(1 + x)(y + 2)(y − 2).

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Question 20

Algebraic Expressions

If one factor of x3 − 8−1 is x − 2−1 the other factor is

  1. A.x2 + 2−1x − 4−1
  2. B.x2 − 2−1x − 4−1
  3. C.x2 + 4−1x + 2−1
  4. D.x2 + 2−1x + 4−1
Show the answer and explanation

Answer: D (x2 + 2−1x + 4−1)

Explanation

This is a difference of cubes: x³ − (½)³ = (x − ½)(x² + ½x + ¼).

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Question 21

Algebraic Expressions

Factorize 4a2 − 12ab − c2 + 9b2

  1. A.4a(a − 3b) + (3b − c)2
  2. B.(2a + 3b − c)(2a + 3b + c)
  3. C.(2a − 3b − c)(2a − 3b + c)
  4. D.4a(a − 3b) + (3b + c)2.
Show the answer and explanation

Answer: C ((2a − 3b − c)(2a − 3b + c))

Explanation

4a² − 12ab + 9b² = (2a − 3b)², so the expression is (2a − 3b)² − c² = (2a − 3b − c)(2a − 3b + c).

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Question 22

Algebraic Expressions

What are K and L respectively if ½(3y − 4x)2 = (8x2 + Kxy + Ly2)?

  1. A.−12, 9/2
  2. B.−6, 9
  3. C.6, 9
  4. D.12, 9/2.
Show the answer and explanation

Answer: A (−12, 9/2)

Explanation

(3y − 4x)² = 9y² − 24xy + 16x². Half of it is 8x² − 12xy + (9/2)y², so K = −12 and L = 9/2.

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Question 23

Linear and Simultaneous Equations

Solve the pair of equation for x and y respectively
2x−1 − 3y−1 = 4
4x−1 + y−1 = 1

  1. A.−1, 2
  2. B.1, 2
  3. C.2, 1
  4. D.2, −1
Show the answer and explanation

Answer: D (2, −1)

Explanation

Let u = 1/x, v = 1/y: 2u − 3v = 4 and 4u + v = 1. Then v = 1 − 4u, so 14u − 3 = 4 and u = ½, v = −1. So x = 2 and y = −1.

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Question 24

Quadratic Equations

What value of Q will make the expression 4x2 + 5x + Q a complete square?

  1. A.25/16
  2. B.25/64
  3. C.5/8
  4. D.5/4
Show the answer and explanation

Answer: A (25/16)

Explanation

(2x + a)² = 4x² + 4ax + a², so 4a = 5 and a = 5/4. Then Q = a² = 25/16.

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Question 25

Inequalities

Find the range of values of r which satisfies the following inequality, where a, b and c are positive.
r/a + r/b + r/c > 1

  1. A.r > abc/(bc + ac + ab)
  2. B.r > abc
  3. C.r > 1/a + 1/b + 1/c
  4. D.r > 1/abc
Show the answer and explanation

Answer: A (r > abc/(bc + ac + ab))

Explanation

r(bc + ac + ab)/abc > 1. Since a, b, c are positive we can multiply out without changing the sign: r > abc/(bc + ac + ab).

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Question 26

Algebraic Expressions

Express
1/(x + 1) − 1/(x − 2)
as a single algebraic fraction

  1. A.−3/((x + 1)(2 − x))
  2. B.3/((x + 1)(2 − x))
  3. C.−1/((x + 1)(x − 2))
  4. D.1/((x + 1)(x − 2))
Show the answer and explanation

Answer: B (3/((x + 1)(2 − x)))

Explanation

The result is ((x − 2) − (x + 1))/((x + 1)(x − 2)) = −3/((x + 1)(x − 2)). Changing the sign of the factor (x − 2) gives 3/((x + 1)(2 − x)).

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Question 27

Algebraic Expressions

Simplify
(x(x + 1)−½ − (x + 1)½)/(x + 1)½

  1. A.1/(x + 1)
  2. B.−1/(x + 1)
  3. C.1/x
  4. D.−1/√(x + 1)
Show the answer and explanation

Answer: B (−1/(x + 1))

Explanation

Divide each term by (x + 1)½: x/(x + 1) − 1 = (x − x − 1)/(x + 1) = −1/(x + 1).

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Question 28

Differentiation

On the curve above, the points at which the gradient of the curve is equal to zero are

Diagram for this question
  1. A.c, d, f, i, l
  2. B.b, e, g, j, m
  3. C.a, b, c, d, f, i, j, l
  4. D.c, d, f, h, i, l.
Show the answer and explanation

Answer: B (b, e, g, j, m)

Explanation

The gradient is zero at the turning points, the tops and bottoms of the curve where the tangent is flat. These are b, e, g, j and m.

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Question 29

Progressions

The sum of the first two terms of a geometric progression is x and the sum of the last two terms is y. If there are n terms in all, then the common ratio is

  1. A.x/y
  2. B.y/x
  3. C.(x/y)1/(n−2)
  4. D.(y/x)1/(n−2)
Show the answer and explanation

Answer: D ((y/x)1/(n−2))

Explanation

x = a + ar and y = arn−2 + arn−1 = rn−2(a + ar). So y/x = rn−2 and r = (y/x)1/(n−2).

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Question 30

Progressions

If −8, m, n, 19 are in arithmetic progression, find (m, n)

  1. A.1, 10
  2. B.2, 10
  3. C.3, 13
  4. D.4, 16
Show the answer and explanation

Answer: A (1, 10)

Explanation

From −8 to 19 is three equal steps: 3d = 27, so d = 9. Then m = 1 and n = 10.

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Question 31

Circle Theorems

MN is a tangent to the given circle at M, MR and MQ are two chords. If QM̂N is 60° and MN̂Q is 40°, find RM̂Q

Diagram for this question
  1. A.120°
  2. B.110°
  3. C.60°
  4. D.20°.
Show the answer and explanation

Answer: D (20°.)

Explanation

By the alternate segment theorem angle MRQ = angle QMN = 60°. In triangle MQN, angle MQN = 180° − 60° − 40° = 80°, so angle MQR = 100°. In triangle MRQ, angle RMQ = 180° − 60° − 100° = 20°.

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Question 32

Triangles and Quadrilaterals

In the diagram above, HK is parallel to QR, PH = 4cm and HQ = 3cm. What is the ratio of KR:PR?

Diagram for this question
  1. A.7 : 3
  2. B.3 : 7
  3. C.3 : 4
  4. D.4 : 3.
Show the answer and explanation

Answer: B (3 : 7)

Explanation

A line parallel to one side divides the other two sides in the same ratio. So KR : PR = HQ : PQ = 3 : 7.

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Question 33

Angles and Polygons

A regular polygon of (2k + 1) sides has 140° as the size of each interior angle. Find k.

  1. A.4
  2. B.4½
  3. C.8
  4. D.8½.
Show the answer and explanation

Answer: A (4)

Explanation

Each exterior angle is 180° − 140° = 40°, so there are 360 ÷ 40 = 9 sides. Then 2k + 1 = 9 and k = 4.

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Question 34

Angles and Polygons

If PST is a straight line and PQ = QS = SR in the above diagram, find y.

Diagram for this question
  1. A.24°
  2. B.48°
  3. C.72°
  4. D.84°
Show the answer and explanation

Answer: C (72°)

Explanation

PQ = QS gives angle QSP = 24°, and the exterior angle SQR = 24° + 24° = 48°. SQ = SR gives angle SRQ = 48°, so angle QSR = 84°. On the straight line at S, y = 180° − 24° − 84° = 72°.

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Question 35

Angles and Polygons

In the above diagram PQ is parallel to RS and QS bisects PQ̂R. If PR̂Q is 60°, find x

Diagram for this question
  1. A.30°
  2. B.40°
  3. C.60°
  4. D.120°
Show the answer and explanation

Answer: B (40°)

Explanation

Angle PRQ = 60° means arc PQ = 120°. QS bisects angle PQR, so arcs PS and SR are equal, and the parallel chords make arc QR equal to arc PS. These three equal arcs share 240°, so each is 80°. x stands on arc QR, so x = 40°.

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Question 36

Triangles and Quadrilaterals

PQRS is a rhombus. If PR2 + QS2 = kPQ2, determine k.

  1. A.1
  2. B.2
  3. C.3
  4. D.4.
Show the answer and explanation

Answer: D (4.)

Explanation

The diagonals of a rhombus bisect each other at right angles, so PQ² = (PR/2)² + (QS/2)². Multiplying by 4, PR² + QS² = 4PQ², so k = 4.

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Question 37

Triangles and Quadrilaterals

In XYZ, Ŷ = Ẑ = 30° and XZ = 3cm. Find YZ.

  1. A.√3/2 cm
  2. B.3√3/2 cm
  3. C.3√3cm
  4. D.2√3cm
Show the answer and explanation

Answer: C (3√3cm)

Explanation

Angle X = 120°. By the sine rule YZ/sin 120° = 3/sin 30°, so YZ = 3 × (√3/2) ÷ ½ = 3√3cm.

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Question 38

Triangles and Quadrilaterals

In ΔPQR, the bisector of QP̂R meets QR at S. The line PQ is produced to V and the bisector of VQ̂S meets PS produced at T. If QP̂R = 46° and QŜT = 75°, calculate QT̂S

  1. A.41°
  2. B.52°
  3. C.64°
  4. D.82°
Show the answer and explanation

Answer: A (41°)

Explanation

Angle QPS = 23° and angle QSP = 180° − 75° = 105°, so the exterior angle VQS = 23° + 105° = 128° and angle TQS = 64°. In triangle QST, angle QTS = 180° − 75° − 64° = 41°.

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Question 39

Angles and Polygons

If PQR is a straight line with QS = QR, calculate TP̂Q, if QT||SR and TQ̂S = 3y°

Diagram for this question
  1. A.62°
  2. B.56°
  3. C.20⅔°
  4. D.18⅔°
Show the answer and explanation

Answer: C (20⅔°)

Explanation

QS = QR, so angle QRS = (180° − 56°)/2 = 62°. QT is parallel to SR, so angle TQP = 62° (corresponding angles). On the straight line at Q, 62° + 3y + 56° = 180°, so y = 20⅔°, the angle TPQ.

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Question 40

Triangles and Quadrilaterals

If x : y = 5 : 12 and z = 52cm, find the perimeter of the triangle

Diagram for this question
  1. A.68cm
  2. B.84cm
  3. C.100cm
  4. D.120cm
Show the answer and explanation

Answer: D (120cm)

Explanation

The triangle is right-angled with legs in ratio 5 : 12, so the sides are 5k, 12k, 13k. 13k = 52 gives k = 4, and the perimeter is 30k = 120cm.

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Question 41

Trigonometry

The pilot of an aeroplane, flying 10km above the ground in the direction of a landmark, views the landmark to have angles of depression of 35° and 55°. Find the distance between the two points of observation.

  1. A.10(sin35° − sin55°)
  2. B.10(cos35° − cos55°)
  3. C.10(tan35° − tan 55°)
  4. D.10(cot 35° − cot 55°)
Show the answer and explanation

Answer: D (10(cot 35° − cot 55°))

Explanation

At height 10km, the horizontal distance to the landmark is 10 cot θ for a depression angle θ. The two positions are 10 cot 35° and 10 cot 55° away, so the distance between them is 10(cot 35° − cot 55°).

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Question 42

Trigonometry

4 sin2x − 3 = 0, find x if 0 ≤ x ≤ 90°

  1. A.30°
  2. B.45°
  3. C.60°
  4. D.90°
Show the answer and explanation

Answer: C (60°)

Explanation

sin²x = 3/4, so sin x = √3/2 (positive in this range). Then x = 60°.

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Question 43

Mensuration of Plane Shapes

A square tile has side 30cm. How many of these tiles will cover a rectangular floor of length 7.2m and width 4.2m?

  1. A.336
  2. B.420
  3. C.576
  4. D.720
Show the answer and explanation

Answer: A (336)

Explanation

The floor is 720cm by 420cm. That is 24 tiles along and 14 tiles across, so 24 × 14 = 336 tiles.

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Question 44

Mensuration of Solids

A cylindrical metal pipe 1m long has an outer diameter of 7.2cm and an inner diameter of 2.8cm. Find the volume of metal used for the cylinder.

  1. A.440πcm3
  2. B.1,100πcm3
  3. C.4,400πcm3
  4. D.11,000πcm3
Show the answer and explanation

Answer: B (1,100πcm3)

Explanation

Volume of metal = π/4 × (D² − d²) × length = π/4 × (51.84 − 7.84) × 100 = π/4 × 44 × 100 = 1,100π cm³.

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Question 45

Mensuration of Solids

OXYZW is a pyramid with a square base such that OX = OY = OZ = OW = 5cm and XY = XW = YZ = WZ = 6cm. Find the height OT.

Diagram for this question
  1. A.2√5
  2. B.3
  3. C.4
  4. D.√7
Show the answer and explanation

Answer: D (√7)

Explanation

T is the centre of the base, half a diagonal from each corner: half of 6√2 = 3√2. OT² = 5² − (3√2)² = 25 − 18 = 7, so OT = √7cm.

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Question 46

Data Presentation

In preparing rice cutlets, a cook used 75g of rice, 40g of margarine, 105g of meat and 20g of bread crumbs. Find the angle of the sector which represents meat in a pie chart.

  1. A.30°
  2. B.60°
  3. C.112.5°
  4. D.157.5°
Show the answer and explanation

Answer: D (157.5°)

Explanation

The total is 240g. Meat's angle = 105/240 × 360° = 157.5°.

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Question 47

Data Presentation

In a class of 30 students, the marks scored in an examination are displayed in the following histogram: What percentage of the students scored more than 40%?

Diagram for this question
  1. A.14%
  2. B.40%
  3. C.46⅔%
  4. D.53⅓%
Show the answer and explanation

Answer: C (46⅔%)

Explanation

The bars above 40 marks show 6 + 6 + 2 = 14 students. 14/30 × 100 = 46⅔%.

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Question 48

Measures of Central Tendency

In a family of 21 people, the average age is 14 years. if the age of the grandfather is not counted, the average age drops to 12 years. What is the age of the grandfather?

  1. A.35years
  2. B.40 years
  3. C.42 years
  4. D.54 years
Show the answer and explanation

Answer: D (54 years)

Explanation

Total age = 21 × 14 = 294. Without him, 20 × 12 = 240. The grandfather is 294 − 240 = 54 years old.

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Question 49

Measures of Central Tendency

If n is the median and m is the mode of the following set of numbers, 2, 4,2.1, 1.6, 2.6, 2.6, 3.7, 2.1, 2.6, then (n, m) is

  1. A.(2.6, 2.6)
  2. B.(2.5, 2.6)
  3. C.(2.6, 2.5)
  4. D.(2.5, 2.1)
Show the answer and explanation

Answer: A ((2.6, 2.6))

Explanation

In order the nine numbers are 1.6, 2, 2.1, 2.1, 2.6, 2.6, 2.6, 3.7, 4. The middle (5th) one is 2.6 and the most common is 2.6, so (n, m) = (2.6, 2.6).

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Question 50

Probability

Two numbers are chosen at random from three numbers 1, 3, 6. Find the probability that the sum of the two is not odd.

  1. A.2/3
  2. B.1/2
  3. C.1/3
  4. D.1/6
Show the answer and explanation

Answer: C (1/3)

Explanation

The possible pairs are 1 + 3 = 4, 1 + 6 = 7 and 3 + 6 = 9. Only one of the three sums is even, so the probability is 1/3.

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