Question 23
Linear and Simultaneous EquationsSolve the pair of equation for x and y respectively
2x−1 − 3y−1 = 4
4x−1 + y−1 = 1
- A.−1, 2
- B.1, 2
- C.2, 1
- D.2, −1
Show the answer and explanation
Answer: D (2, −1)
Explanation
Let u = 1/x, v = 1/y: 2u − 3v = 4 and 4u + v = 1. Then v = 1 − 4u, so 14u − 3 = 4 and u = ½, v = −1. So x = 2 and y = −1.