Question 13
Algebraic ExpressionsMake R the subject of the formula S = √((2R + T)/2RT)
- A.R = T/(TS2 − 1)
- B.R = T/(2(TS2 − 1))
- C.R = T/(TS2 + 1)
- D.R = T/(2(TS2 + 1))
Show the answer and explanation
Answer: B (R = T/(2(TS2 − 1)))
Explanation
Square both sides: 2RTS² = 2R + T. Collect R: R(2S²T − 2) = T, so R = T/(2(TS² − 1)).