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JAMB Mathematics 1989 Question 39

Question 39

Angles and Polygons

If PQR is a straight line with QS = QR, calculate TP̂Q, if QT||SR and TQ̂S = 3y°

Diagram for this question
  1. A.62°
  2. B.56°
  3. C.20⅔°
  4. D.18⅔°
Show the answer and explanation

Answer: C (20⅔°)

Explanation

QS = QR, so angle QRS = (180° − 56°)/2 = 62°. QT is parallel to SR, so angle TQP = 62° (corresponding angles). On the straight line at Q, 62° + 3y + 56° = 180°, so y = 20⅔°, the angle TPQ.