JAMB Mathematics 2005 past questions and answers

45 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Number Bases

Find the value of m if 13m + 24m = 41m.

  1. A.8
  2. B.6
  3. C.5
  4. D.2
Show the answer and explanation

Answer: B (6)

Explanation

(m + 3) + (2m + 4) = 4m + 1, so 3m + 7 = 4m + 1 and m = 6.

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Question 2

Number Bases

If 3214 is divided by 234 and leaves a remainder r, what is the value of r?

  1. A.0
  2. B.1
  3. C.2
  4. D.3
Show the answer and explanation

Answer: C (2)

Explanation

3214 = 57 and 234 = 11 in base ten. 57 = 5 × 11 + 2, so r = 2.

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Question 3

Fractions, Decimals and Approximation

Simplify 3½ − (2⅓ × 1¼) + 3/5

  1. A.2 11/60
  2. B.2 1/60
  3. C.1 11/60
  4. D.1 1/60
Show the answer and explanation

Answer: C (1 11/60)

Explanation

2⅓ × 1¼ = 35/12. Then 7/2 − 35/12 + 3/5 = (210 − 175 + 36)/60 = 71/60 = 1 11/60.

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Question 4

Commercial Arithmetic

A father decided to give 20% of his monthly income to his three children as their monthly allowance. The eldest child got 45% of the allowance and the youngest got 25%. How much was the father's monthly income if the second child got N3,000?

  1. A.N33,000
  2. B.N45,000
  3. C.N50,000
  4. D.N60,000
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Answer: C (N50,000)

Explanation

The second child got 100 − 45 − 25 = 30% of the allowance, so the allowance is N10,000. That is 20% of income, so income = N50,000.

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Question 5

Commercial Arithmetic

If the interest on N150.00 for 2½ years is N4.50, find the interest on N250.00 for 6 months at the same rate.

  1. A.N1.50
  2. B.N7.50
  3. C.N15.00
  4. D.N18.00
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Answer: A (N1.50)

Explanation

Rate = 100 × 4.50/(150 × 2.5) = 1.2% a year. Interest = 250 × 1.2 × ½/100 = N1.50.

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Question 7

Indices

Evaluate (813/4 − 271/3)/(3 × 23).

  1. A.3
  2. B.1
  3. C.1/3
  4. D.1/8
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Answer: B (1)

Explanation

813/4 = 27 and 271/3 = 3, so the value is (27 − 3)/24 = 1.

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Question 8

Logarithms

If log102 = 0.3010 and log103 = 0.4771, evaluate log104.5

  1. A.0.9542
  2. B.0.6532
  3. C.0.4771
  4. D.0.3010
Show the answer and explanation

Answer: B (0.6532)

Explanation

4.5 = 9/2, so log 4.5 = 2 log 3 − log 2 = 0.9542 − 0.3010 = 0.6532.

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Question 9

Surds

Simplify (√12 − √3)/(√12 + √3)

  1. A.0
  2. B.1/3
  3. C.3/5
  4. D.1
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Answer: B (1/3)

Explanation

√12 = 2√3, so the expression is (2√3 − √3)/(2√3 + √3) = √3/(3√3) = 1/3.

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Question 10

Sets

If U = {x/x is a positive integer less than 10} and P = {x/ x is a prime factor of 30}, find the complement of P.

  1. A.{1, 2, 4, 7, 8, 9}
  2. B.{1, 2, 4, 6, 7, 8, 9}
  3. C.{1, 4, 6, 7, 8, 9}
  4. D.{1, 4, 7, 8, 9}
Show the answer and explanation

Answer: C ({1, 4, 6, 7, 8, 9})

Explanation

The prime factors of 30 are 2, 3 and 5. Removing them from {1, ..., 9} leaves {1, 4, 6, 7, 8, 9}.

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Question 11

Sets

The Venn diagram above shows a class of 40 students with the games they play. How many of the students play two games only?

Diagram for this question
  1. A.19
  2. B.16
  3. C.15
  4. D.4
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Answer: C (15)

Explanation

The regions in exactly two circles hold 5, 7 and 3 students, so 5 + 7 + 3 = 15 play two games only.

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Question 12

Fractions, Decimals and Approximation

If m = 3, p = −3, q = 7 and r = 5/2, evaluate m(p + q + r).

  1. A.19.50
  2. B.19.15
  3. C.18.95
  4. D.18.05
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Answer: A (19.50)

Explanation

p + q + r = −3 + 7 + 2.5 = 6.5, and 3 × 6.5 = 19.5.

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Question 13

Polynomials

Divide 6x2 − 13x + 5 by 2x − 1

  1. A.3x + 5
  2. B.3x − 5
  3. C.5x − 3
  4. D.5x + 3
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Answer: B (3x − 5)

Explanation

6x2 − 13x + 5 = (2x − 1)(3x − 5), so the quotient is 3x − 5.

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Question 14

Polynomials

A polynomial in x whose zeros are −2, −1 and 3 is

  1. A.x3 − 7x + 6
  2. B.x3 + 7x − 6
  3. C.x3 + 7x + 6
  4. D.x3 − 7x − 6
Show the answer and explanation

Answer: D (x3 − 7x − 6)

Explanation

(x + 2)(x + 1)(x − 3) = (x2 + 3x + 2)(x − 3) = x3 − 7x − 6.

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Question 15

Variation

The time taken to do a piece of work is inversely proportional to the number of men employed. If it takes 30 men to do a piece of work in 6 days, how many men are required to do the work in 4 days?

  1. A.20
  2. B.35
  3. C.45
  4. D.60
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Answer: C (45)

Explanation

Men × days is constant: 30 × 6 = 180, so 180 ÷ 4 = 45 men.

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Question 16

Variation

The weight W kg of a metal bar varies jointly as its length L metres and the square of its diameter d metres. If W = 140 when d = 4⅔ and L = 54, find d in terms of W and L.

  1. A.√(42W/5L)
  2. B.√(5L/42W)
  3. C.42W/5L
  4. D.5L/42W
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Answer: A (√(42W/5L))

Explanation

W = kLd2: 140 = k × 54 × 196/9 = 1176k, so k = 5/42. Then d2 = W/(kL) = 42W/(5L).

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Question 17

Inequalities

Find the range of values of x for which 7x − 3 > 25 + 3x.

  1. A.x > 7
  2. B.x < 7
  3. C.x > −7
  4. D.x < −7
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Answer: A (x > 7)

Explanation

7x − 3x > 25 + 3, so 4x > 28 and x > 7.

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Question 18

Inequalities

The diagram above is the graph of the function f(x). Determine the range of values of x for which f(x) ≤ 0.

Diagram for this question
  1. A.x ≤ 2
  2. B.0 ≤ x ≤ 2
  3. C.−2 ≤ x ≤ 0, x ≥ 2
  4. D.x ≤ −2, 0 ≤ x ≤ 2
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Answer: D (x ≤ −2, 0 ≤ x ≤ 2)

Explanation

The curve is on or below the x-axis to the left of −2 and between 0 and 2, so f(x) ≤ 0 for x ≤ −2 and 0 ≤ x ≤ 2.

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Question 19

Progressions

If the 7th term of an AP is twice the third term and the sum of the first four terms is 42, find the common difference.

  1. A.6
  2. B.3
  3. C.2
  4. D.1
Show the answer and explanation

Answer: B (3)

Explanation

a + 6d = 2(a + 2d) gives a = 2d. Then 4a + 6d = 42 becomes 14d = 42, so d = 3.

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Question 20

Progressions

Find the sum of the first 20 terms of the series 8, 12, 16, ......., 96.

  1. A.1400
  2. B.1040
  3. C.960
  4. D.920
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Answer: D (920)

Explanation

a = 8, d = 4: S20 = 20/2 × (16 + 19 × 4) = 10 × 92 = 920.

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Question 21

Binary Operations

An operation * is defined on the set of real numbers by a * b = ab + 2(a + b + 1). Find the identity element.

  1. A.2
  2. B.1
  3. C.−1
  4. D.−2
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Answer: C (−1)

Explanation

a * e = a gives ae + 2a + 2e + 2 = a, so e(a + 2) = −(a + 2) and e = −1.

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Question 22

Matrices and Determinants

If M and N are two matrices defined by M = (1 3 2; 4 5 −1; −3 2 0) and N = (1 −2 3; 4 −1 5; 2 −3 −1), evaluate 2M − 3N. (Matrices written row by row.)

  1. A.(−1 12 5; 4 7 13; 0 −5 −3)
  2. B.(−1 0 −5; −4 7 −17; 0 −5 3)
  3. C.(−1 12 −5; −4 13 −17; −12 13 3)
  4. D.(−1 12 −5; 4 13 13; −12 13 3)
Show the answer and explanation

Answer: C ((−1 12 −5; −4 13 −17; −12 13 3))

Explanation

2M = (2 6 4; 8 10 −2; −6 4 0) and 3N = (3 −6 9; 12 −3 15; 6 −9 −3). Subtracting entry by entry gives (−1 12 −5; −4 13 −17; −12 13 3).

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Question 23

Matrices and Determinants

If P = (1 3 2; 4 5 −1; −3 2 0), find the determinant of matrix P. (Matrix written row by row.)

  1. A.75
  2. B.57
  3. C.−57
  4. D.−75
Show the answer and explanation

Answer: B (57)

Explanation

Expanding along the first row: 1(0 + 2) − 3(0 − 3) + 2(8 + 15) = 2 + 9 + 46 = 57.

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Question 24

Triangles and Quadrilaterals

In the diagram above, calculate the value of x.

Diagram for this question
  1. A.60°
  2. B.100°
  3. C.120°
  4. D.140°
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Answer: C (120°)

Explanation

The triangle's angle at the left line is 180° − 100° = 80°, so its angle at P is 180° − 40° − 80° = 60°. Using the parallel lines, the angle between the slanting line and the lower line is 60°, so x = 180° − 60° = 120°.

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Question 25

Angles and Polygons

Three straight lines EF, GH and LK intersect at O as shown above. If ∠KOF = 52° and ∠LOH = 85°, calculate the size of ∠EOG.

Diagram for this question
  1. A.26°
  2. B.43°
  3. C.52°
  4. D.85°
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Answer: B (43°)

Explanation

KOL is a straight line, so ∠FOH = 180° − 52° − 85° = 43°. ∠EOG is vertically opposite ∠FOH, so it is 43°.

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Question 26

Angles and Polygons

The sum of the interior angles of a regular polygon is 1800°. Calculate the size of one exterior angle of the polygon.

  1. A.30°
  2. B.24°
  3. C.18°
  4. D.12°
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Answer: A (30°)

Explanation

(n − 2) × 180 = 1800 gives n = 12, so each exterior angle is 360° ÷ 12 = 30°.

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Question 27

Circle Theorems

In the diagram above, O is the centre of the circle, ∠UOT = 70° and ∠RST = 100°. Calculate ∠RUO.

Diagram for this question
  1. A.20°
  2. B.25°
  3. C.50°
  4. D.80°
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Answer: B (25°)

Explanation

OU = OT, so ∠OUT = (180° − 70°)/2 = 55°. RSTU is cyclic, so ∠RUT = 180° − 100° = 80°. Then ∠RUO = 80° − 55° = 25°.

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Question 28

Circle Theorems

A chord of a circle subtends an angle of 60° at the centre of a circle of radius 14cm. Find the length of the chord.

  1. A.7cm
  2. B.14cm
  3. C.21cm
  4. D.28cm
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Answer: B (14cm)

Explanation

The two radii and the chord form a triangle with a 60° angle between equal sides, so it is equilateral and the chord is 14cm.

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Question 29

Mensuration of Plane Shapes

A sector of a circle has an area of 55 cm2. If the radius of the circle is 10 cm, calculate the angle of the sector. [π = 22/7]

  1. A.45°
  2. B.63°
  3. C.75°
  4. D.90°
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Answer: B (63°)

Explanation

θ/360 × 22/7 × 100 = 55, so θ = 55 × 360 × 7/2200 = 63°.

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Question 30

Mensuration of Solids

Find the curved surface area of a cone with circular base diameter 10 cm and height 12 cm.

  1. A.25πcm2
  2. B.65πcm2
  3. C.120πcm2
  4. D.156πcm2
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Answer: B (65πcm2)

Explanation

r = 5 and the slant height l = √(122 + 52) = 13. Curved surface = πrl = 65π cm2.

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Question 31

Loci

Two lines PQ and ST intersect at 75°. The locus of points equidistant from PQ and ST lies on the

  1. A.perpendicular bisector of PQ
  2. B.perpendicular bisector of ST
  3. C.bisector of the angles between lines PQ and ST
  4. D.bisector of the angles between lines PT and QS.
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Answer: C (bisector of the angles between lines PQ and ST)

Explanation

Points equidistant from two intersecting lines lie on the bisectors of the angles between those lines.

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Question 32

Coordinate Geometry

Find the equation of the perpendicular at point (4, 3) to the line y + 2x = 5.

  1. A.2y − x = 4
  2. B.y + 2x = 3
  3. C.y + 2x = 5
  4. D.2y − x = 2
Show the answer and explanation

Answer: D (2y − x = 2)

Explanation

The line has gradient −2, so the perpendicular has gradient ½: y − 3 = ½(x − 4), which gives 2y − x = 2.

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Question 33

Coordinate Geometry

Find the coordinates of the midpoint of the line joining (3, −4) and (−1, 10).

  1. A.(1, 3)
  2. B.(1, 2)
  3. C.(2, 3)
  4. D.(3, 2)
Show the answer and explanation

Answer: A ((1, 3))

Explanation

Midpoint = ((3 − 1)/2, (−4 + 10)/2) = (1, 3).

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Question 34

Trigonometry

If sin θ = −½ for 0 < θ < 360°, the value of θ is

  1. A.30° and 150°
  2. B.150° and 210°
  3. C.210° and 330°
  4. D.150° and 330°
Show the answer and explanation

Answer: C (210° and 330°)

Explanation

Sine is negative in the third and fourth quadrants. With reference angle 30°, θ = 180° + 30° = 210° or 360° − 30° = 330°.

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Question 35

Bearings

From the diagram above, find the bearing of R from S.

Diagram for this question
  1. A.226°
  2. B.224°
  3. C.136°
  4. D.134°
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Answer: B (224°)

Explanation

In the right-angled triangle ORS, ∠OSR = 90° − 44° = 46°. R lies 46° south of due west from S, so the bearing is 270° − 46° = 224°.

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Question 36

Differentiation

If y = (1 − 2x)3, find the value of dy/dx at x = −1.

  1. A.57
  2. B.27
  3. C.−6
  4. D.−54
Show the answer and explanation

Answer: D (−54)

Explanation

dy/dx = 3(1 − 2x)2 × (−2) = −6(1 − 2x)2. At x = −1 this is −6 × 9 = −54.

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Question 37

Differentiation

Find the derivative of y = sin(2x3 + 3x − 4).

  1. A.cos(2x3 + 3x − 4)
  2. B.−cos(2x3 + 3x − 4)
  3. C.(6x2 + 3) cos(2x3 + 3x − 4)
  4. D.−(6x2 + 3) cos(2x3 + 3x − 4)
Show the answer and explanation

Answer: C ((6x2 + 3) cos(2x3 + 3x − 4))

Explanation

By the chain rule, differentiate the sine to cosine and multiply by the derivative of the inside, 6x2 + 3.

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Question 38

Differentiation

The radius r of a circular disc is increasing at the rate of 0.5cm/sec. At what rate is the area of the disc increasing when its radius is 6cm?

  1. A.36π cm2/sec.
  2. B.18π cm2/sec.
  3. C.6π cm2/sec.
  4. D.3π cm2/sec.
Show the answer and explanation

Answer: C (6π cm2/sec.)

Explanation

A = πr2, so dA/dt = 2πr × dr/dt = 2π × 6 × 0.5 = 6π cm2/sec.

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Question 41

Integration

Evaluate ∫0π/2 sin 2x dx.

  1. A.1
  2. B.0
  3. C.−½
  4. D.−1
Show the answer and explanation

Answer: A (1)

Explanation

∫ sin 2x dx = −½ cos 2x. From 0 to π/2: −½(cos π − cos 0) = −½(−1 − 1) = 1.

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Question 44

Measures of Central Tendency

Scores: 1, 2, 3, 4, 5, 6
No. of students: 1, 4, 5, 6, x, 2
The table above shows the scores of a group of students in a test. If the average score is 3.5, find the value of x.

  1. A.1
  2. B.2
  3. C.3
  4. D.4
Show the answer and explanation

Answer: B (2)

Explanation

Σfx = 1 + 8 + 15 + 24 + 5x + 12 = 60 + 5x and Σf = 18 + x. (60 + 5x)/(18 + x) = 3.5 gives 1.5x = 3, so x = 2.

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Question 45

Measures of Dispersion

The modal height and range of heights 1.35, 1.25, 1.35, 1.40, 1.35, 1.45, 1.50, 1.35, 1.50 and 1.20 are m and r respectively. Find m + 2r.

  1. A.1.35
  2. B.1.65
  3. C.1.95
  4. D.3.00
Show the answer and explanation

Answer: C (1.95)

Explanation

1.35 appears most often, so m = 1.35. r = 1.50 − 1.20 = 0.30. m + 2r = 1.95.

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Question 46

Measures of Dispersion

Find the value of t if the standard deviation of 2t, 3t, 4t, 5t and 6t is √2.

  1. A.1
  2. B.2
  3. C.3
  4. D.4
Show the answer and explanation

Answer: A (1)

Explanation

The mean is 4t and the deviations are −2t, −t, 0, t, 2t. Variance = 10t2/5 = 2t2, so SD = t√2 = √2 and t = 1.

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Question 47

Permutation and Combination

In how many ways can 6 coloured chalks be arranged if 2 are of the same colour?

  1. A.60
  2. B.120
  3. C.240
  4. D.360
Show the answer and explanation

Answer: D (360)

Explanation

Arrange 6 items with 2 identical: 6!/2! = 720/2 = 360.

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Question 48

Permutation and Combination

How many possible ways are there of seating seven people P, Q, R, S, T, U and V at a circular table?

  1. A.360
  2. B.720
  3. C.2520
  4. D.5040
Show the answer and explanation

Answer: B (720)

Explanation

Around a circle, n people can be seated in (n − 1)! ways: 6! = 720.

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Question 49

Probability

A box contains 5 blue balls, 3 red balls and 2 white balls. Two balls are selected from the box with replacement. Find the probability of obtaining two blue or two red balls.

  1. A.17/50
  2. B.3/25
  3. C.1/50
  4. D.3/250
Show the answer and explanation

Answer: A (17/50)

Explanation

P(two blue) = (5/10)2 = 1/4 and P(two red) = (3/10)2 = 9/100. Total = 25/100 + 9/100 = 34/100 = 17/50.

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Question 50

Probability

What is the probability that an integer x, (1 ≤ x ≤ 20) chosen at random is divisible by both 2 and 3?

  1. A.1/20
  2. B.1/3
  3. C.3/20
  4. D.7/10
Show the answer and explanation

Answer: C (3/20)

Explanation

Numbers divisible by both 2 and 3 are multiples of 6: 6, 12 and 18. So the probability is 3/20.

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