Question 25
Angles and PolygonsThree straight lines EF, GH and LK intersect at O as shown above. If ∠KOF = 52° and ∠LOH = 85°, calculate the size of ∠EOG.

- A.26°
- B.43°
- C.52°
- D.85°
Show the answer and explanation
Answer: B (43°)
Explanation
KOL is a straight line, so ∠FOH = 180° − 52° − 85° = 43°. ∠EOG is vertically opposite ∠FOH, so it is 43°.