Question 46
Measures of DispersionFind the value of t if the standard deviation of 2t, 3t, 4t, 5t and 6t is √2.
- A.1
- B.2
- C.3
- D.4
Show the answer and explanation
Answer: A (1)
Explanation
The mean is 4t and the deviations are −2t, −t, 0, t, 2t. Variance = 10t2/5 = 2t2, so SD = t√2 = √2 and t = 1.