JAMB Chemistry 1987 past questions and answers

49 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Separation of Mixtures

A brand of ink containing cobalt (II), copper (II) and iron (II) ions can best be separated into its various components by

  1. A.fractional crystallization
  2. B.fractional distillation
  3. C.sublimation
  4. D.chromatography
Show the answer and explanation

Answer: D (chromatography)

Explanation

The coloured ions in ink move at different speeds through paper or another adsorbent, so chromatography separates them. The other methods cannot separate several dissolved coloured substances present in tiny amounts.

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Question 2

Separation of Mixtures

Which of the following substances is a mixture?

  1. A.Granulated sugar
  2. B.Sea-water
  3. C.Sodium chloride
  4. D.Iron filings
Show the answer and explanation

Answer: B (Sea-water)

Explanation

Sea-water is water with many different salts dissolved in it, in no fixed proportion, so it is a mixture. Sugar and sodium chloride are compounds and iron is an element.

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Question 3

Mole Concept and Stoichiometry

The number of molecules of carbon (IV) oxide produced when 10.0 g of CaCO3 is treated with 0.2 dm3 of 1 M HCl in the equation CaCO3 + 2HCl → CaCl2 + H2O + CO2 is [Ca = 40, O = 16, C = 12, NA = 6.02 × 1023, H = 1, Cl = 35.5]

  1. A.1.00 × 1023
  2. B.6.02 × 1023
  3. C.6.02 × 1022
  4. D.6.02 × 1024
Show the answer and explanation

Answer: C (6.02 × 1022)

Explanation

10.0 g of CaCO3 (M = 100) is 0.1 mol, and 0.2 dm3 of 1 M HCl is 0.2 mol, exactly enough. So 0.1 mol of CO2 forms: 0.1 × 6.02 × 1023 = 6.02 × 1022 molecules.

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Question 4

Mole Concept and Stoichiometry

In the reaction CaC2(s) + 2H2O(l) → Ca(OH)2(s) + C2H2(g) what is the mass of solid calcium carbide needed to produce 1000 cm3 of acetylene gas at S.T.P.? [C = 12, Ca = 40, G.M.V = 22400 cm3]

  1. A.3.8 g
  2. B.2.9 g
  3. C.2.0 g
  4. D.1.0 g
Show the answer and explanation

Answer: B (2.9 g)

Explanation

1 mol CaC2 (64 g) gives 22400 cm3 of C2H2. For 1000 cm3: 64 × 1000/22400 = 2.86 g, about 2.9 g.

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Question 5

Gas Laws

If the quantity of oxygen occupying a 2.76 litre container at a pressure of 0.825 atmospheres and 300 K is reduced by one-half, what is the pressure exerted by the remaining gas?

  1. A.1.650 atm
  2. B.0.825 atm
  3. C.0.413 atm
  4. D.0.275 atm
Show the answer and explanation

Answer: C (0.413 atm)

Explanation

At fixed volume and temperature, pressure is proportional to the amount of gas. Halving the gas halves the pressure: 0.825/2 = 0.413 atm.

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Question 6

Gas Laws

Which of the following substances has the lowest vapour density? [O = 16, Cl = 35.5, H = 1, C = 12]

  1. A.Ethanoic acid
  2. B.Propanol
  3. C.Dichloromethane
  4. D.Ethanal
Show the answer and explanation

Answer: D (Ethanal)

Explanation

Vapour density is half the relative molecular mass. Ethanal CH3CHO (44) is lighter than ethanoic acid (60), propanol (60) and dichloromethane (85).

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Question 7

Gas Laws

If d represents the density of a gas and K is a constant, the rate of gaseous diffusion r is related to d by the equation

  1. A.r = k/√d
  2. B.r = kd
  3. C.r = k/d
  4. D.r = k√d
Show the answer and explanation

Answer: A (r = k/√d)

Explanation

Graham's law: the rate of diffusion is inversely proportional to the square root of the density, so r = k/√d.

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Question 8

Atomic Structure

An isotope has an atomic number of 17 and a mass number of 36. Which of the following gives the correct number of neutrons and protons in an atom of the isotope?

  1. A.Neutrons 53, Protons 17
  2. B.Neutrons 17, Protons 36
  3. C.Neutrons 19, Protons 17
  4. D.Neutrons 36, Protons 17
Show the answer and explanation

Answer: C (Neutrons 19, Protons 17)

Explanation

Protons = atomic number = 17. Neutrons = mass number − atomic number = 36 − 17 = 19.

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Question 9

Chemical Bonding

The atomic numbers of two elements X and Y are 12 and 16 respectively. The bond in the compound formed between the atoms of these two elements is

  1. A.ionic
  2. B.covalent
  3. C.neutral
  4. D.co-ordinate
Show the answer and explanation

Answer: A (ionic)

Explanation

Element 12 is magnesium, a metal that loses 2 electrons; element 16 is sulphur, a non-metal that gains 2. Electron transfer gives an ionic bond.

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Question 10

Atomic Structure

An element Z, contained 90% of 168Z and 10% of 188Z. Its relative atomic mass is

  1. A.16.0
  2. B.16.2
  3. C.17.0
  4. D.17.8
Show the answer and explanation

Answer: B (16.2)

Explanation

Relative atomic mass = (90 × 16 + 10 × 18)/100 = (1440 + 180)/100 = 16.2.

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Question 11

Chemical Bonding

The greater the difference in electronegativity between bonded atoms, the

  1. A.lower the polarity of the bond
  2. B.higher the polarity of the bond
  3. C.weaker the bond
  4. D.higher the possibility of the substance formed being a molecule.
Show the answer and explanation

Answer: B (higher the polarity of the bond)

Explanation

A bigger electronegativity difference pulls the shared electrons more towards one atom, so the bond becomes more polar (and eventually ionic).

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Question 12

Air

A stream of air was successively passed through three tubes X, Y and Z containing a concentrated aqueous solution of KOH, red hot copper powder and fused calcium chloride respectively. What was the composition of the gas emanating from tube Z?

  1. A.CO2 and the inert gases
  2. B.N2, CO2 and the inert gases
  3. C.N2 and the inert gases
  4. D.water vapour, N2 and the inert gases.
Show the answer and explanation

Answer: C (N2 and the inert gases)

Explanation

KOH absorbs carbon (IV) oxide, hot copper removes oxygen and fused calcium chloride removes water vapour. Only nitrogen and the inert gases are left.

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Question 13

Water

In the purification of town water supply, alum is used principally to

  1. A.kill bacteria
  2. B.control the pH of water
  3. C.improve the taste of the water
  4. D.coagulate small particles of mud.
Show the answer and explanation

Answer: D (coagulate small particles of mud.)

Explanation

Alum makes tiny suspended clay and mud particles clump together (coagulate) so they settle out. Chlorine, not alum, kills bacteria.

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Question 14

Water

Which of the following water samples will have the highest titre value when titrated for the Ca2+ ions using soap solution?

  1. A.Permanently hard water after boiling
  2. B.Temporarily hard water after boiling
  3. C.Rain water stored in a glass jar for two years
  4. D.Permanently hard water passed through permutit.
Show the answer and explanation

Answer: A (Permanently hard water after boiling)

Explanation

Boiling does not remove permanent hardness, so that sample still has its Ca2+ ions and needs the most soap. Boiling removes temporary hardness, permutit removes permanent hardness and rain water is soft.

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Question 15

Environmental Pollution

Oil spillage in ponds and creeks can be cleaned up by

  1. A.burning off the oil layer
  2. B.spraying with detergent
  3. C.dispersal with compressed air
  4. D.spraying with hot water.
Show the answer and explanation

Answer: B (spraying with detergent)

Explanation

Detergents emulsify oil, breaking the layer into tiny droplets that can be dispersed and broken down.

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Question 16

Solubility and Solutions

The solubility of Na3AsO4(H2O)12 is 38.9 g per 100 g H2O. What is the mass percentage of Na3AsO4 in the saturated solution? [As = 75, Na = 23, O = 16, H = 1]

  1. A.87.2%
  2. B.38.9%
  3. C.19.1%
  4. D.13.7%
Show the answer and explanation

Answer: D (13.7%)

Explanation

The hydrate has M = 424, of which Na3AsO4 is 208. So 38.9 g of hydrate holds 38.9 × 208/424 = 19.1 g of Na3AsO4 in 138.9 g of solution: 19.1/138.9 × 100 = 13.7%.

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Question 17

Alkanols

Which is the correct set of results for tests conducted respectively on fresh lime juice and ethanol?

  1. A.Add crystals of NaHCO3: fresh lime juice, gas evolved; ethanol, no gas evolved
  2. B.Test with methyl orange: fresh lime juice, turns colourless; ethanol, no change
  3. C.Taste: fresh lime juice, bitter; ethanol, sour
  4. D.Add a piece of sodium: fresh lime juice, no gas evolved; ethanol, hydrogen evolved
Show the answer and explanation

Answer: A (Add crystals of NaHCO3: fresh lime juice, gas evolved; ethanol, no gas evolved)

Explanation

Lime juice contains citric acid, which reacts with hydrogencarbonate to give carbon (IV) oxide; ethanol is not acidic enough to do this. Methyl orange turns red (not colourless) in acid, lime juice is sour, and sodium gives hydrogen with both liquids.

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Question 18

Acids, Bases and Salts

In which of the following are the aqueous solutions of each of the substances correctly arranged in order of decreasing acidity?

  1. A.Ethanoic acid, milk of magnesia, sodium chloride, hydrochloric acid and sodium hydroxide
  2. B.Ethanoic acid, hydrochloric acid, milk of magnesia, sodium chloride and sodium hydroxide
  3. C.Hydrochloric acid, ethanoic acid, sodium chloride, milk of magnesia and sodium hydroxide
  4. D.Hydrochloric acid, sodium hydroxide, sodium chloride, ethanoic acid and milk of magnesia.
Show the answer and explanation

Answer: C (Hydrochloric acid, ethanoic acid, sodium chloride, milk of magnesia and sodium hydroxide)

Explanation

Strong acid HCl is most acidic, then weak ethanoic acid, then neutral NaCl, then weakly alkaline milk of magnesia, and strongly alkaline NaOH last.

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Question 19

Acids, Bases and Salts

The basicity of tetraoxophosphate (V) acid is

  1. A.7
  2. B.5
  3. C.4
  4. D.3
Show the answer and explanation

Answer: D (3)

Explanation

H3PO4 has three replaceable hydrogen atoms, so its basicity is 3.

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Question 20

Volumetric Analysis

If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45 cm3 of HCl, what is the molarity of the HCl?

  1. A.0.094 M
  2. B.0.150 M
  3. C.0.940 M
  4. D.1.500 M
Show the answer and explanation

Answer: A (0.094 M)

Explanation

NaOH and HCl react 1 : 1, so MA × 39.45 = 0.15 × 24.83. MA = 3.72/39.45 = 0.094 M.

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Question 21

Electrolysis

A quantity of electricity liberates 3.6 g of silver from its salt. What mass of aluminium will be liberated from its salt by the same quantity of electricity? [Al = 27, Ag = 108]

  1. A.2.7 g
  2. B.1.2 g
  3. C.0.9 g
  4. D.0.3 g
Show the answer and explanation

Answer: D (0.3 g)

Explanation

3.6 g Ag is 3.6/108 = 1/30 mol, needing 1/30 F. Al3+ needs 3 F per mole, so 1/90 mol Al forms: 27/90 = 0.3 g.

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Question 22

Electrolysis

Which of the following statements is CORRECT if 1 Faraday of electricity is passed through 1 M CuSO4 solution for 1 minute?

  1. A.The pH of the solution at the cathode decreases
  2. B.The pH of the solution at the anode decreases
  3. C.1 mole of Cu will be liberated at the cathode
  4. D.60 moles of Cu will be liberated at the anode.
Show the answer and explanation

Answer: B (The pH of the solution at the anode decreases)

Explanation

At the anode OH− ions are discharged as oxygen, leaving H+ ions behind, so the solution there becomes more acidic and its pH falls. 1 F deposits only 0.5 mol Cu, at the cathode.

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Question 23

Electrolysis

What mass of magnesium would be obtained by passing a current of 2 amperes for 2 hrs. 30 mins through molten magnesium chloride? [1 Faraday = 96500 coulombs, Mg = 24]

  1. A.1.12 g
  2. B.2.00 g
  3. C.2.24 g
  4. D.4.48 g
Show the answer and explanation

Answer: C (2.24 g)

Explanation

Q = 2 × 9000 s = 18000 C. Mg2+ needs 2 × 96500 C per 24 g, so mass = 24 × 18000/193000 = 2.24 g.

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Question 24

Redox Reactions

In the reaction: 3CuO + 2NH3 → 3Cu + 3H2O + N2 how many electrons are transferred for each mole of copper produced?

  1. A.4.0 × 10−23
  2. B.3.0 × 10−23
  3. C.1.2 × 1024
  4. D.6.0 × 1024
Show the answer and explanation

Answer: C (1.2 × 1024)

Explanation

Each Cu2+ gains 2 electrons to become Cu. One mole of Cu therefore needs 2 × 6.02 × 1023 = 1.2 × 1024 electrons.

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Question 25

Alkanoic Acids and Esters

Z is a solid substance which liberates carbon (IV) oxide on treatment with concentrated H2SO4. A warm solution of Z also decolorizes acidified KMnO4. The solid substance, Z, is

  1. A.sodium hydrogen trioxocarbonate (IV)
  2. B.methanoic acid
  3. C.iron (II) trioxocarbonate (IV)
  4. D.ethanedioic acid (oxalic acid).
Show the answer and explanation

Answer: D (ethanedioic acid (oxalic acid).)

Explanation

Concentrated H2SO4 dehydrates solid oxalic acid to CO and CO2, and warm oxalic acid is oxidised by KMnO4, decolourising it. Methanoic acid is a liquid and NaHCO3 is not a reducing agent.

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Question 26

Energy Changes

5 g of ammonium trioxonitrate (V) on dissolution in water cooled its surrounding water and container by 1.6 kJ. What is the heat of solution of NH4NO3? [N = 14, O = 16, H = 1]

  1. A.+51.4 kJ mol−1
  2. B.+25.6 kJ mol−1
  3. C.+12.9 kJ mol−1
  4. D.−6.4 kJ mol−1
Show the answer and explanation

Answer: B (+25.6 kJ mol−1)

Explanation

M(NH4NO3) = 80, so 5 g is 0.0625 mol. Heat absorbed per mole = 1.6/0.0625 = 25.6 kJ; it cools the water, so it is endothermic (+25.6 kJ mol−1).

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Question 27

Energy Changes

Tetraoxosulphate (VI) acid is prepared using the chemical reaction SO3(g) + H2O(l) → H2SO4(l). Given the heats of formation for SO3(g), H2O(l) and H2SO4(l) as −395 kJ mol−1, −286 kJ mol−1 and −811 kJ mol−1 respectively, the enthalpy change accompanying this reaction is

  1. A.−1032 kJ
  2. B.−130 kJ
  3. C.+130 kJ
  4. D.+1032 kJ
Show the answer and explanation

Answer: B (−130 kJ)

Explanation

ΔH = ΣH(products) − ΣH(reactants) = −811 − (−395 − 286) = −811 + 681 = −130 kJ.

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Question 28

Rates of Reaction

The times taken for iodine to be liberated in the reaction between sodium thiosulphate and hydrochloric acid at various temperature are as follows:
Temp °C: 25, 35, 45
Time (seconds): 72, 36, 18
These results suggest that

  1. A.for a 10° rise in temperature, rate of reaction is doubled
  2. B.for a 10° rise in temperature, rate of reaction is halved
  3. C.time taken for iodine to appear does not depend on temperature
  4. D.for a 10° rise in temperature, rate of reaction is tripled.
Show the answer and explanation

Answer: A (for a 10° rise in temperature, rate of reaction is doubled)

Explanation

Each 10 °C rise halves the time (72 → 36 → 18 s). Rate is inversely proportional to time, so the rate doubles.

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Question 29

Chemical Equilibrium

The reaction between sulphur (IV) oxide and oxygen is represented by the equilibrium reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), ΔH = −196 kJ. What factor would influence increased production of SO3(g)?

  1. A.Addition of a suitable catalyst
  2. B.Increase in the temperature of the reaction
  3. C.Decrease in the temperature of the reaction
  4. D.Decrease in the concentration of SO2(g).
Show the answer and explanation

Answer: C (Decrease in the temperature of the reaction)

Explanation

The forward reaction is exothermic, so lowering the temperature shifts the equilibrium to the right, giving more SO3. A catalyst only speeds up reaching equilibrium; it does not change the yield.

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Question 30

Halogens

Which of the following equations correctly represents the action of hot concentrated alkaline solution on chlorine?

  1. A.Cl2(g) + 2OH−(aq) → OCl−(aq) + Cl−(aq) + H2O(l)
  2. B.3Cl2(g) + 6OH−(aq) → ClO3−(aq) + 5Cl−(aq) + 3H2O(l)
  3. C.3Cl2(g) + 6OH−(aq) → ClO3−(s) + 5Cl−(aq) + 3H2O(l)
  4. D.3Cl2(g) + 6OH−(aq) → 5ClO3−(aq) + Cl−(aq) + 3H2O(l)
Show the answer and explanation

Answer: B (3Cl2(g) + 6OH−(aq) → ClO3−(aq) + 5Cl−(aq) + 3H2O(l))

Explanation

Hot concentrated alkali turns chlorine into chlorate(V) and chloride in the ratio 1 : 5. The chlorate ion stays dissolved, so it is (aq), not (s). Option A is the reaction with cold dilute alkali.

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Question 31

Nitrogen and its Compounds

Magnesium ribbon was allowed to burn inside a given gas P leaving a white solid residue Q. Addition of water to Q liberated a gas which produced dense white fumes with a drop of hydrochloric acid. The gas P was

  1. A.nitrogen
  2. B.chlorine
  3. C.oxygen
  4. D.sulphur (IV) oxide
Show the answer and explanation

Answer: A (nitrogen)

Explanation

Magnesium burns in nitrogen to form magnesium nitride, Mg3N2. Water turns this into ammonia, which forms white fumes of NH4Cl with HCl.

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Question 32

Acids, Bases and Salts

The best treatment for a student who accidentally poured concentrated tetraoxosulphate (VI) acid on his skin in the laboratory is to wash the skin with

  1. A.cold water
  2. B.sodium hydroxide solution
  3. C.iodine solution
  4. D.sodium trioxocarbonate (IV) solution.
Show the answer and explanation

Answer: A (cold water)

Explanation

Washing at once with plenty of cold water dilutes and removes the acid quickly. Sodium hydroxide is itself corrosive and would cause more harm.

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Question 33

Sulphur and its Compounds

In which of the following pairs of elements is allotropy exhibited by each element?

  1. A.Phosphorus and hydrogen
  2. B.Oxygen and chlorine
  3. C.Sulphur and nitrogen
  4. D.Oxygen and sulphur
Show the answer and explanation

Answer: D (Oxygen and sulphur)

Explanation

Oxygen exists as O2 and ozone O3; sulphur exists as rhombic and monoclinic forms. Hydrogen, chlorine and nitrogen have no allotropes.

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Question 34

Halogens

Which of the following gases can best be used for demonstrating the fountain experiment?
(i) Nitrogen (ii) Ammonia (iii) Nitrogen (I) oxide (iv) Hydrogen chloride

  1. A.(ii) and (iii)
  2. B.(i) and (iii)
  3. C.(ii) and (iv)
  4. D.(ii) only.
Show the answer and explanation

Answer: C ((ii) and (iv))

Explanation

The fountain experiment needs a gas that is extremely soluble in water. Ammonia and hydrogen chloride both are; nitrogen and nitrogen (I) oxide are only slightly soluble.

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Question 35

Nitrogen and its Compounds

When calcium hydroxide is heated with ammonium tetraoxosulphate (VI), the gas given off may be collected by

  1. A.bubbling it through concentrated H2SO4
  2. B.bubbling it through water and then passing it through calcium oxide
  3. C.passing it directly through calcium oxide
  4. D.passing it directly through calcium chloride.
Show the answer and explanation

Answer: C (passing it directly through calcium oxide)

Explanation

The gas is ammonia. It is dried with calcium oxide. It reacts with concentrated H2SO4 and with calcium chloride, and it dissolves in water.

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Question 36

Metals and their Compounds

Which of the following elements will form oxide which will dissolve both in dilute HNO3 and NaOH solutions to form salts?

  1. A.Al
  2. B.Mg
  3. C.Ag
  4. D.Mn
Show the answer and explanation

Answer: A (Al)

Explanation

Aluminium oxide is amphoteric: it reacts with acids and with alkalis to form salts.

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Question 38

Metals and their Compounds

Alloys are best prepared by

  1. A.high temperature welding of the metals
  2. B.electrolysis using the major metallic component as cathode
  3. C.reducing a mixture of the oxides of the elements
  4. D.cooling a molten mixture of the necessary elements.
Show the answer and explanation

Answer: D (cooling a molten mixture of the necessary elements.)

Explanation

Alloys are made by melting the components together so they mix evenly, then letting the molten mixture cool and solidify.

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Question 39

Metals and their Compounds

Corrosion is exhibited by

  1. A.iron only
  2. B.electropositive metals
  3. C.metals below hydrogen in the electrochemical series
  4. D.all metals.
Show the answer and explanation

Answer: B (electropositive metals)

Explanation

Corrosion is the oxidation of a metal by air and water. Electropositive (reactive) metals lose electrons easily, so they corrode; unreactive metals such as gold and platinum do not.

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Question 40

Atomic Structure

Inspite of the electronic configuration, 1s22s22p2, carbon is tetravalent because

  1. A.the electrons in both 2s and 2p orbitals have equal energy
  2. B.the electrons in both 2s and 2p orbitals are equivalent
  3. C.both the 2s and 2p orbitals hydrodize
  4. D.the six orbitals hybridize to four.
Show the answer and explanation

Answer: C (both the 2s and 2p orbitals hydrodize)

Explanation

One 2s electron is promoted to 2p and the 2s and three 2p orbitals mix (hybridise) into four equal sp3 orbitals, each with one unpaired electron, so carbon forms four bonds.

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Question 41

Hydrocarbons

Which of the following compounds will give a precipitate with an aqueous ammoniacal solution of copper (I) chloride?

  1. A.CH3CH = CHCH3
  2. B.CH3C ≡ CCH3
  3. C.HC ≡ C–CH2CH3
  4. D.CH2 = CH–CH = CH2
Show the answer and explanation

Answer: C (HC ≡ C–CH2CH3)

Explanation

Only alkynes with a terminal ≡C–H (an acidic hydrogen) form a red precipitate of copper(I) acetylide. But-1-yne has one; but-2-yne and the alkenes do not.

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Question 42

Petroleum and Coal

The efficiency of petrol as a fuel in high-compression internal combustion engines improves with an increase in the amount of

  1. A.branched chain alkanes
  2. B.straight chain alkanes
  3. C.cycloalkanes
  4. D.halogenated hydrocarbons
Show the answer and explanation

Answer: A (branched chain alkanes)

Explanation

Branched-chain alkanes burn smoothly without knocking, which raises the octane rating of petrol.

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Question 43

Carbohydrates, Proteins and Amines

A palm wine seller stoppered a bottle of his palm wine in his stall and after a few hours the bottle exploded. Which of the following equations represents the reaction that occurred?

  1. A.C6H12O6 → 2C2H5OH + 2CO2(g) (enzymes)
  2. B.C2H5OH → CH2 = CH2(g) + H2O
  3. C.C2H5OH + dil H2SO4 → C2H5OSO2OH
  4. D.2C6H12O6 → C12H22O13 + H2O.
Show the answer and explanation

Answer: A (C6H12O6 → 2C2H5OH + 2CO2(g) (enzymes))

Explanation

Yeast enzymes keep fermenting the sugar in palm wine to ethanol and carbon (IV) oxide. The gas builds up pressure in the closed bottle until it bursts.

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Question 44

Alkanols

Ethanol reacts with aqueous sodium mono-oxoiodate (I) to give a bright yellow solid with a characteristic smell. The product is

  1. A.trichloromethane
  2. B.triiodomethane
  3. C.iodoethane
  4. D.ethanal.
Show the answer and explanation

Answer: B (triiodomethane)

Explanation

This is the iodoform test: ethanol is oxidised and iodinated to give yellow triiodomethane (CHI3), which has an antiseptic smell.

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Question 45

Petroleum and Coal

The most volatile fraction obtained from fractional distillation of crude petroleum contains

  1. A.butane, propane and kerosene
  2. B.butane, propane and petrol
  3. C.ethane, methane and benzene
  4. D.methane, ethane and propane.
Show the answer and explanation

Answer: D (methane, ethane and propane.)

Explanation

The most volatile fraction has the lowest boiling points: the refinery gases, made of the smallest alkanes such as methane, ethane and propane.

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Question 46

Fats, Oils and Soaps

Local black soap is made by boiling palm oil with liquid extract of ash. The function of the ash is to provide the

  1. A.acid
  2. B.ester of alkanoic acid
  3. C.alkali
  4. D.alkanol
Show the answer and explanation

Answer: C (alkali)

Explanation

Wood ash contains potassium carbonate and hydroxide, an alkali. The alkali saponifies the fat (palm oil) to form soap.

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Question 47

Polymers

Synthetic rubber is made by polymerization of

  1. A.2 methyl buta – 1, 3 – diene
  2. B.2 methyl buta – 1,2– diene
  3. C.2 methyl but–1–ene
  4. D.2 methyl but–2–ene
Show the answer and explanation

Answer: A (2 methyl buta – 1, 3 – diene)

Explanation

Rubber is a polymer of isoprene, which is 2-methylbuta-1,3-diene. Its two double bonds allow it to form the long rubber chain.

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Question 48

Alkanols

Complete oxidation of propan –1–ol gives

  1. A.propanal
  2. B.propan–2–al
  3. C.propan–1–one
  4. D.propanoic acid
Show the answer and explanation

Answer: D (propanoic acid)

Explanation

A primary alkanol is first oxidised to an alkanal, then fully to the alkanoic acid. Propan-1-ol therefore ends up as propanoic acid.

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Question 49

Hydrocarbons

When water drops are added to calcium carbide in a container and the gas produced is passed through a jet and lighted, the resultant flame is called an

  1. A.oxyethylene flame
  2. B.oxyhydrocarbon flame
  3. C.oxyacetylene flame
  4. D.oxymethane flame
Show the answer and explanation

Answer: C (oxyacetylene flame)

Explanation

Water and calcium carbide produce ethyne (acetylene). Burnt with oxygen it gives the very hot oxyacetylene flame.

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Question 50

Alkanoic Acids and Esters

The structure of benzoic acid is

Diagram for this question
  1. A.Benzene ring with –CHO (structure A in the figure)
  2. B.Cyclohexane ring with –COOH (structure B in the figure)
  3. C.Benzene ring with –CH2–COOH (structure C in the figure)
  4. D.Benzene ring with –COOH (structure D in the figure)
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Answer: D (Benzene ring with –COOH (structure D in the figure))

Explanation

Benzoic acid is C6H5COOH: a carboxyl group joined directly to a benzene ring. A is benzaldehyde, B has no benzene ring and C is phenylethanoic acid.

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