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JAMB Chemistry 1987 Question 20

Question 20

Volumetric Analysis

If 24.83 cm3 of 0.15 M NaOH is titrated to its end point with 39.45 cm3 of HCl, what is the molarity of the HCl?

  1. A.0.094 M
  2. B.0.150 M
  3. C.0.940 M
  4. D.1.500 M
Show the answer and explanation

Answer: A (0.094 M)

Explanation

NaOH and HCl react 1 : 1, so MA × 39.45 = 0.15 × 24.83. MA = 3.72/39.45 = 0.094 M.