A proton moving with a speed of 1.0 × 106ms−1 through a magnetic field of 1.0 T experiences a magnetic force of magnitude 8.0 × 10−14 N. The angle between the proton's velocity and the field is [Proton charge = 1.6 × 10−19C]
A.45°.
B.30°.
C.60°.
D.90°.
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Answer: B (30°.)
Explanation
F = qvB sin θ: sin θ = 8.0 × 10−14 ÷ (1.6 × 10−19 × 106 × 1.0) = 0.5, so θ = 30°.
In photoelectric effect, which of the following graphs correctly represents the graph of stopping potential V0 against frequency f of incident light?
A.Graph A
B.Graph B
C.Graph C
D.Graph D
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Answer: B (Graph B)
Explanation
eV0 = hf − W, so V0 against f is a straight line of positive slope that cuts the f-axis at the threshold frequency and, extended, has a negative intercept on the V0 axis (graph B).
The figure above shows three capacitors, 2μF, 3μF and 6μF connected in series. If the p.d. across the system is 12V, the p.d. across the 6μF capacitor is
A.4V.
B.6V.
C.12 V.
D.2V.
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Answer: D (2V.)
Explanation
1/C = 1/2 + 1/3 + 1/6 = 1, so C = 1 μF and Q = 12 μC. V across 6 μF = 12 μC ÷ 6 μF = 2 V.
Two charged particles are projected into a region where there is a magnetic field perpendicular to their velocities. If the charges are deflected in opposite directions, which of the following statements is true of the charges?
A.The charges are of the same sign
B.Positive charges are more in number
C.The charges must be of opposite sign
D.The charges are electrically neutral.
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Answer: C (The charges must be of opposite sign)
Explanation
The magnetic force direction depends on the sign of the charge; opposite deflections in the same field mean opposite charges.
In the figure above, the coefficient of static friction is 0.5. If the tension in the string is T, the acceleration of the system in motion is [g = 10 ms−2]
A.15 ms−2.
B.3 ms−2.
C.5 ms−2.
D.9 ms−2.
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Answer: C (5 ms−2.)
Explanation
Friction on the 3 kg block = 0.5 × 30 = 15 N. Net force = 60 − 15 = 45 N on a total mass of 9 kg, so a = 5 m s−2.
A motorcyclist travelling at 30 ms−1 starts to apply his brakes when he is 50 m from the traffic light that has just turned red. If he just reached the traffic light, his deceleration is
In the figure above, the work done by the force of 100 N inclined at an angle of 60° to the object dragged horizontally to a distance of 8 m is [Neglect frictional effect]
A.800 J.
B.800 J.
C.400 J.
D.100 J.
Show the answer and explanation
Answer: C (400 J.)
Explanation
Only the horizontal part does work: W = F cos 60° × s = 100 × 0.5 × 8 = 400 J.
The figure above shows a plot of angles of deviation through a glass prism when light is incident at θ degrees on the prism. The incident angle that produces the minimum deviation is
A.25°.
B.18°.
C.35°.
D.20°.
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Answer: A (25°.)
Explanation
Minimum deviation is the lowest point of the curve, which is at an incident angle of about 25°.
Two liquids L1 and L2 are contained in a U-tube. The height and the density of L1 are 8 cm and 103 kgm−3 respectively. If the density of L2 is 800 kgm−3, its height measured from the same level is
A.8 cm.
B.16 cm.
C.12 cm.
D.10 cm.
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Answer: D (10 cm.)
Explanation
Pressures balance: h1ρ1 = h2ρ2, so h2 = 8 × 1000/800 = 10 cm.
An elastic material has a length of 36cm when a load of 40 N is hung on it and a length of 45 cm when a load of 60 N is hung on it. The original length of the string is
A.18cm.
B.12cm.
C.20cm.
D.15cm.
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Answer: A (18cm.)
Explanation
An extra 20 N gives 9 cm more, so 40 N gives 18 cm extension. Original length = 36 − 18 = 18 cm.
I. Reproducibility II. Sensitivity III. High thermal capacity IV. High accuracy The qualities of a good thermometer include
A.I, III and IV only.
B.I, II and IV only.
C.II, III and IV only.
D.I, II and III only.
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Answer: B (I, II and IV only.)
Explanation
A good thermometer gives repeatable, sensitive and accurate readings; a high thermal capacity is a drawback because it takes heat from what it measures and responds slowly.
106J of heat is required to boil off completely 2 kg of a certain liquid. Neglecting heat lost to the surroundings, the latent heat of vaporization of the liquid is
A body of mass 36 kg falls through a viscous liquid which offers a drag force of 260 N on the body. The upthrust on the body at terminal velocity is [g = 10ms−2]
A.310 N.
B.50 N.
C.620 N.
D.100 N.
Show the answer and explanation
Answer: D (100 N.)
Explanation
At terminal velocity weight = drag + upthrust: 360 = 260 + U, so U = 100 N.