Question 17
ElectrostaticsThe electric field intensity in a place where a charge of 10−10 C experiences a force of 0.4N is
- A.8.0 × 10−12NC−1.
- B.8.0 × 109 NC−1.
- C.4.0 × 109 NC−1.
- D.4.0 × 10−11 NC−1.
Show the answer and explanation
Answer: C (4.0 × 109 NC−1.)
Explanation
E = F/q = 0.4 ÷ 10−10 = 4.0 × 109 N C−1.