Question 26
FrictionIn the figure above, the coefficient of static friction is 0.5. If the tension in the string is T, the acceleration of the system in motion is [g = 10 ms−2]

- A.15 ms−2.
- B.3 ms−2.
- C.5 ms−2.
- D.9 ms−2.
Show the answer and explanation
Answer: C (5 ms−2.)
Explanation
Friction on the 3 kg block = 0.5 × 30 = 15 N. Net force = 60 − 15 = 45 N on a total mass of 9 kg, so a = 5 m s−2.