Question 23
ElectrostaticsIf the distance between two point charges is increased by a factor of four, the magnitude of the electrostatic force between them will be
- A.½ of its former value.
- B.1/16 of its former value.
- C.1/4 of its former value.
- D.4 times its former value.
Show the answer and explanation
Answer: B (1/16 of its former value.)
Explanation
Coulomb's law: F ∝ 1/r2, so making r four times bigger makes F (1/4)2 = 1/16 of its former value.