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JAMB Physics 2005 Question 7

Question 7

Radioactivity and Nuclear Physics

23592U + 10n → 14456Ba + 9036Kr + 2X
In the reaction above, X is

  1. A.neutron.
  2. B.electron.
  3. C.neutrino
  4. D.proton.
Show the answer and explanation

Answer: A (neutron.)

Explanation

Mass numbers: 236 = 144 + 90 + 2A gives A = 1. Atomic numbers: 92 = 56 + 36 + 2Z gives Z = 0. So X is a neutron.