JAMB Physics 1992 past questions and answers

49 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Measurement and Units

What is the least possible error in using a rule graduated in centimeters?

  1. A.0.1cm
  2. B.0.5cm
  3. C.1.0cm
  4. D.2.0cm
Show the answer and explanation

Answer: B (0.5cm)

Explanation

The least possible error of a scale is half its smallest division; a rule marked in 1 cm steps gives ±0.5 cm.

Open this question

Question 2

Simple Harmonic Motion

Which of the following affects the period of a simple pendulum? I. Mass of the pendulum bob II. Length of the pendulum III. Acceleration due to gravity

  1. A.I, II and III
  2. B.II and III only
  3. C.I and III only
  4. D.I and II only
Show the answer and explanation

Answer: B (II and III only)

Explanation

T = 2π√(l/g), so the period depends on the length l and on g, but not on the mass of the bob.

Open this question

Question 3

Motion

A boy sits in a train moving with uniform speed on a straight track. If from his outstretched palm he gently tosses a coin vertically upwards, the coin will fall

  1. A.in front of his palm
  2. B.behind his palm
  3. C.beside his palm
  4. D.into his palm
Show the answer and explanation

Answer: D (into his palm)

Explanation

The coin already shares the train's horizontal velocity, and nothing changes it while it is in the air, so it keeps pace with the boy and lands back in his palm.

Open this question

Question 4

Motion

A body starts from rest and moves with uniform acceleration of 6 m s−2. What distance does it cover in the third second?

  1. A.15m
  2. B.18m
  3. C.27m
  4. D.30m
Show the answer and explanation

Answer: A (15m)

Explanation

Distance in 3 s = ½ × 6 × 3² = 27 m; in 2 s = ½ × 6 × 2² = 12 m. In the third second it covers 27 − 12 = 15 m.

Open this question

Question 5

Motion

A stone, Q is thrown with velocity u at an angle of 75° to the horizontal. Another stone R is thrown with the same velocity u but at an angle of 15° to the horizontal. The ranges covered by the stones will be

  1. A.greater for Q
  2. B.greater for R
  3. C.the same for Q and R
  4. D.greater for the heavier of the two stones
Show the answer and explanation

Answer: C (the same for Q and R)

Explanation

Range = u² sin 2θ / g. sin 150° = sin 30°, so angles of 75° and 15° (which add up to 90°) give the same range.

Open this question

Question 6

Work, Energy and Power

A man weighing 800N climbs up a flight of stairs to a height of 15m in 12.5s. What is the man's average power output?

  1. A.667W
  2. B.810W
  3. C.960W
  4. D.15000W
Show the answer and explanation

Answer: C (960W)

Explanation

Work done = 800 × 15 = 12 000 J. Power = 12 000 ÷ 12.5 = 960 W.

Open this question

Question 7

Equilibrium of Forces

A uniform light rod is kept in horizontal equilibrium under the influence of four forces as shown above. Which of the following equations correctly represents the condition of equilibrium for the rod?

Diagram for this question
  1. A.F1 + F2 = F3 + F4
  2. B.F1 + F2 − F3 + F4 = 0
  3. C.(F1 + F2)ab = (F3 + F4)cd
  4. D.F1a + F2b − F3c − F4d = 0
Show the answer and explanation

Answer: D (F1a + F2b − F3c − F4d = 0)

Explanation

Take moments about the pivot: F1 and F2 turn the rod one way, F3 and F4 the other way. Balance means F1a + F2b = F3c + F4d.

Open this question

Question 8

Friction

In the diagram above, the hanging mass m2 is adjusted until m1 is on the verge of sliding. The coefficient of static friction between the mass m1 and the table is

Diagram for this question
  1. A.m1/m2
  2. B.m1g/m2
  3. C.m2/m1
  4. D.m2g/m1
Show the answer and explanation

Answer: C (m2/m1)

Explanation

At the point of sliding, the pull m2g equals the limiting friction μm1g, so μ = m2/m1.

Open this question

Question 9

Simple Machines

A machine requires 1000 J of work to raise a load of 500N through a vertical distance of 1.5m. Calculate the efficiency of the machine.

  1. A.80%
  2. B.75%
  3. C.50%
  4. D.33%
Show the answer and explanation

Answer: B (75%)

Explanation

Useful work output = 500 × 1.5 = 750 J. Efficiency = 750/1000 × 100% = 75%.

Open this question

Question 10

Elasticity

In an experiment to determine Young's Modulus for a wire, several loads are attached to the wire and the corresponding extensions measured. The tensile stress in each case depends on the

  1. A.load and the extension
  2. B.load and the radius of the wire
  3. C.radius of the wire and the extension
  4. D.extension and the original length of the wire
Show the answer and explanation

Answer: B (load and the radius of the wire)

Explanation

Tensile stress = force ÷ cross-sectional area = load ÷ πr², so it depends on the load and the radius of the wire.

Open this question

Question 11

Density and Upthrust

The figure above shows the heights of two liquids X and Y when some air is sucked out of the apparatus through the pump P. The diameter of the table in X is twice that of the tube in Y. What is the relative density of liquid X with respect to liquid Y?

Diagram for this question
  1. A.1/3
  2. B.2/3
  3. C.3
  4. D.6
Show the answer and explanation

Answer: C (3)

Explanation

Both columns are held up by the same pressure difference, so ρX × 7.5 = ρY × 22.5, giving ρX/ρY = 3. The tube diameter does not matter.

Open this question

Question 12

Density and Upthrust

If a plastic sphere floats in water (density = 1000 kg m−3) with 0.5 of its volume submerged and floats on oil with 0.4 of its volume submerged, the density of the oil is

  1. A.800 kg m−3
  2. B.1200 kg m−3
  3. C.1250 kg m−3
  4. D.2000 kg m−3
Show the answer and explanation

Answer: C (1250 kg m−3)

Explanation

A floating body displaces its own weight in both liquids: 0.5V × 1000 = 0.4V × ρ, so ρ = 500/0.4 = 1250 kg m−3.

Open this question

Question 13

Temperature and Thermometers

A platinum resistance thermometer wire has a resistance of 5 ohms at 0°C and 5.5 ohms at 100°C. Calculate the temperature of the wire when the resistance is 5.2 ohms.

  1. A.80°C
  2. B.60°C
  3. C.40°C
  4. D.10°C
Show the answer and explanation

Answer: C (40°C)

Explanation

θ = (5.2 − 5.0)/(5.5 − 5.0) × 100 = 0.2/0.5 × 100 = 40°C.

Open this question

Question 14

Thermal Expansion

A bridge made of steel is 600m long. What is the daily variation in its length if the night-time and day-time temperatures are 10°C and 35°C respectively. The linear expansivity of steel is 0.000012 C−1

  1. A.0.18cm
  2. B.1.80cm
  3. C.18.00cm
  4. D.1800cm
Show the answer and explanation

Answer: C (18.00cm)

Explanation

Change in length = 600 × 0.000012 × (35 − 10) = 0.18 m, which is 18.00 cm.

Open this question

Question 15

Thermal Expansion

One of the most important applications of bi-metallic strip is found in the construction of

  1. A.a thermostat
  2. B.an altimeter
  3. C.a thermocouple
  4. D.a hygrometer
Show the answer and explanation

Answer: A (a thermostat)

Explanation

A bimetallic strip bends when heated because its two metals expand differently; a thermostat uses this bending to switch a circuit on and off.

Open this question

Question 16

Gas Laws

At constant pressure, the density of a fixed mass of gas is

  1. A.constant with temperature
  2. B.proportional to its volume
  3. C.inversely proportional to its temperature
  4. D.independent of its volume.
Show the answer and explanation

Answer: C (inversely proportional to its temperature)

Explanation

At constant pressure V ∝ T (Charles's law). Density = mass/volume, so density ∝ 1/T.

Open this question

Question 17

Quantity of Heat

How much heat is absorbed when a block of copper of mass 0.05kg and specific heat capacity 390 J kg−1 K−1 is heated from 20°C to 70°C?

  1. A.3.98 × 10−1 J
  2. B.9.75 × 102 J
  3. C.3.98 × 103 J
  4. D.9.75 × 103 J
Show the answer and explanation

Answer: B (9.75 × 102 J)

Explanation

Q = mcθ = 0.05 × 390 × 50 = 975 J = 9.75 × 102 J.

Open this question

Question 18

Density and Upthrust

A block of ice floats on water inside a container. If the block of ice gets completely melted, the level of water in the container will

  1. A.increase
  2. B.remain the same
  3. C.decrease
  4. D.first decrease and then increase
Show the answer and explanation

Answer: B (remain the same)

Explanation

Floating ice displaces its own weight of water. When it melts it becomes exactly that much water, which fills the space it displaced, so the level does not change.

Open this question

Question 19

Heat Transfer

The space between the double glass walls of a thermos flask is evacuated and the two surfaces facing the evacuated space are silvered. The residual source of heat loss takes place by

  1. A.convection
  2. B.radiation from the surfaces
  3. C.conduction through the stopper and the glass
  4. D.conduction across the walls.
Show the answer and explanation

Answer: C (conduction through the stopper and the glass)

Explanation

The vacuum stops conduction and convection across the walls and the silvering cuts radiation, so the heat that still escapes leaks by conduction through the stopper and along the glass.

Open this question

Question 20

Waves

The equation of a wave is y = 0.005 sin [π(0.5x − 200t)] where x and y are in metres and t is in seconds. What is the velocity of the wave?

  1. A.4000 m s−1
  2. B.400 m s−1
  3. C.250 m s−1
  4. D.40 m s−1
Show the answer and explanation

Answer: B (400 m s−1)

Explanation

For y = A sin(kx − ωt) the wave speed is v = ω/k. Here v = 200/0.5 = 400 m s−1 (a common factor π cancels).

Open this question

Question 21

Waves

Which of the following characteristics of a wave is used in the measurement of the depth of the sea?

  1. A.Diffraction
  2. B.Interference
  3. C.Refraction
  4. D.Reflection
Show the answer and explanation

Answer: D (Reflection)

Explanation

Echo sounding sends a sound pulse down and times its echo, which is the pulse reflected from the sea bed.

Open this question

Question 22

Sound

A note is the octave of another note if it has

  1. A.a frequency twice that of the first note
  2. B.frequency half that of the first note
  3. C.the same fundamental frequency as the first one
  4. D.a frequency eight times that of the first note.
Show the answer and explanation

Answer: A (a frequency twice that of the first note)

Explanation

A note one octave above another has exactly twice its frequency.

Open this question

Question 23

Sound

What is the frequency of the sound made by a siren having a disc with 32 holes and making 25 revolutions per second?

  1. A.80 Hz
  2. B.600 Hz
  3. C.800 Hz
  4. D.1600 Hz
Show the answer and explanation

Answer: C (800 Hz)

Explanation

Each hole gives one puff of air per revolution: f = 32 × 25 = 800 Hz.

Open this question

Question 24

Light and Reflection

Which of the following properties make the convex mirror useful as a driving mirror? I. The image is real II. The image is erect III. It has a wide field of view IV. The image is magnified.

  1. A.I, II and IV
  2. B.I, II and III
  3. C.II and III
  4. D.I and III.
Show the answer and explanation

Answer: C (II and III)

Explanation

A convex mirror always gives an upright (erect), diminished, virtual image and covers a wide field of view, which is what a driver needs.

Open this question

Question 25

Light and Reflection

When an object is placed very close to the pole of a concave mirror, the virtual image obtained is

  1. A.dimished and upright
  2. B.diminished and inverted
  3. C.enlarged and inverted
  4. D.enlarged and upright
Show the answer and explanation

Answer: D (enlarged and upright)

Explanation

An object inside the focal length of a concave mirror gives a virtual image that is upright and magnified (as in a shaving mirror).

Open this question

Question 26

Light and Reflection

A concave mirror has a radius of curvature of 36cm. At what distance from the mirror should an object be placed to give a real image three times the size of the object?

  1. A.12cm
  2. B.24cm
  3. C.48cm
  4. D.108cm
Show the answer and explanation

Answer: B (24cm)

Explanation

f = 36/2 = 18 cm and v = 3u. 1/u + 1/(3u) = 1/18 gives 4/(3u) = 1/18, so u = 24 cm.

Open this question

Question 27

Lenses and Optical Instruments

Which of the following statements is CORRECT about a long-sighted boy who does not put on glasses?

  1. A.He cannot see distant objects clearly
  2. B.Rays of light from a close object are focused in front of his retina
  3. C.His eyeball is too long
  4. D.Parallel rays of light are focused behind his retina.
Show the answer and explanation

Answer: D (Parallel rays of light are focused behind his retina.)

Explanation

A long-sighted eye is too short (or its lens too weak), so with the eye relaxed even parallel rays would meet behind the retina; near objects are the ones he cannot see clearly.

Open this question

Question 28

Refraction of Light

The speed of light in air is 3 × 108 m s−1. What is the speed in glass with a refractive index of 1.50?

  1. A.1.5 × 108 m s−1
  2. B.3.0 × 108 m s−1
  3. C.2.0 × 108 m s−1
  4. D.6.0 × 108 m s−1
Show the answer and explanation

Answer: C (2.0 × 108 m s−1)

Explanation

n = speed in air ÷ speed in glass, so v = 3 × 108 ÷ 1.5 = 2.0 × 108 m s−1.

Open this question

Question 29

Refraction of Light

If the refractive index of a medium in air is 2.0, what is the critical angle for this medium?

  1. A.30°
  2. B.42°
  3. C.45°
  4. D.50°
Show the answer and explanation

Answer: A (30°)

Explanation

sin c = 1/n = 1/2, so c = 30°.

Open this question

Question 30

Electromagnetic Spectrum

Which of the following arrangements of the components of electromagnetic spectrum is in ascending order of wavelengths?

  1. A.Gamma rays, ultraviolet rays, x-rays, infra-red rays
  2. B.Gamma rays, x-rays, ultraviolet rays, infra-red rays
  3. C.infra-red rays, ultraviolet rays, x-rays, gamma rays
  4. D.Gamma rays, ultraviolet rays, infra-red rays, x-rays.
Show the answer and explanation

Answer: B (Gamma rays, x-rays, ultraviolet rays, infra-red rays)

Explanation

From shortest to longest wavelength: gamma rays, X-rays, ultraviolet, visible light, infra-red, radio waves.

Open this question

Question 31

Magnetism

The diagram above represents the field pattern obtained by bringing the poles of two magnets near each other. The poles must be

Diagram for this question
  1. A.N-N poles
  2. B.S-S poles
  3. C.S-N poles
  4. D.N-S poles
Show the answer and explanation

Answer: B (S-S poles)

Explanation

The lines push away from each other and leave a neutral point between the poles, so the poles are alike; the arrows point into both poles, and field lines enter at south poles.

Open this question

Question 32

Magnetism

The angle between the direction of the earth's magnetic field and the horizontal is called the

  1. A.angle of deviation
  2. B.magnetic declination
  3. C.magnetic meridian
  4. D.angle of dip.
Show the answer and explanation

Answer: D (angle of dip.)

Explanation

The angle the earth's field makes with the horizontal is the angle of dip (inclination); declination is the angle between magnetic and geographic north.

Open this question

Question 33

Electrostatics

Calculate the force acting on an electron of charge 1.6 × 10−19 C placed in an electric field of intensity 108 V m−1

  1. A.1.6 × 10−11 N
  2. B.1.6 × 10−14 N
  3. C.1.6 × 10−16 N
  4. D.1.0 × 10−16 N
Show the answer and explanation

Answer: A (1.6 × 10−11 N)

Explanation

F = qE = 1.6 × 10−19 × 108 = 1.6 × 10−11 N.

Open this question

Question 34

Electrostatics

When an ebonite rod is rubbed with fur, it has

  1. A.no charge at all
  2. B.a negative charge
  3. C.a positive charge
  4. D.negative and positive charges.
Show the answer and explanation

Answer: B (a negative charge)

Explanation

Rubbing moves electrons from the fur to the ebonite, so the ebonite becomes negatively charged.

Open this question

Question 35

Current Electricity

Which of the following factors has no effect on the e.m.f. of a primary cell?

  1. A.temperature
  2. B.size of the cell
  3. C.Nature of the plates
  4. D.Nature of the electrolyte.
Show the answer and explanation

Answer: B (size of the cell)

Explanation

The e.m.f. of a cell is set by the chemicals (plates and electrolyte) used; a bigger cell of the same type has the same e.m.f., only more capacity.

Open this question

Question 36

Current Electricity

A wire of length 15m made of a material of resistivity 1.8 × 10−6 Ω m has a resistance of 0.27Ω. Determine the area of the wire

  1. A.1.5 × 10−4 m2
  2. B.1.0 × 10−4 m2
  3. C.2.7 × 10−5 m2
  4. D.7.3 × 10−6 m2.
Show the answer and explanation

Answer: B (1.0 × 10−4 m2)

Explanation

R = ρL/A, so A = ρL/R = 1.8 × 10−6 × 15 ÷ 0.27 = 1.0 × 10−4 m2.

Open this question

Question 37

Current Electricity

The diagram above shows a meter bridge in which two of the arms contain resistances R and 2Ω. A balance point is obtained at 60cm from the left end. Calculate the value of R.

Diagram for this question
  1. A.1.2Ω
  2. B.1.3Ω
  3. C.3.0Ω
  4. D.6.0Ω
Show the answer and explanation

Answer: C (3.0Ω)

Explanation

At balance R/2 = 60/40, so R = 2 × 1.5 = 3.0 Ω.

Open this question

Question 38

Current Electricity

The circuit diagram above contains four ammeters W, X, Y and Z. Which of the following statements about the ammeter reading is correct?

Diagram for this question
  1. A.The reading of W is equal to that of Y and twice that of X
  2. B.The reading of Y is greater than that of Z.
  3. C.The readings of W and Y are equal and each is greater than that of X
  4. D.The reading of Z is equal to the sum of the readings of W and Y.
Show the answer and explanation

Answer: C (The readings of W and Y are equal and each is greater than that of X)

Explanation

W, Z and Y are all in the main line, so they carry the full current. X is in only one of the two parallel branches, so it carries less.

Open this question

Question 39

Capacitors

A 5-V battery is connected across the plates of a 2.0μF uncharged parallel plate capacitor. The charge on the capacitor after a long time is

  1. A.2.5μC
  2. B.10.0μC
  3. C.20.0μC
  4. D.50.0μC
Show the answer and explanation

Answer: B (10.0μC)

Explanation

Q = CV = 2.0 μF × 5 V = 10.0 μC.

Open this question

Question 40

Electrical Energy and Power

Which of the following apparatus will require the smallest fuse rating for its protection?

  1. A.60W, 240V
  2. B.60W, 40V
  3. C.40W, 12V
  4. D.40W, 5V
Show the answer and explanation

Answer: A (60W, 240V)

Explanation

Current I = P/V: 60/240 = 0.25 A, 60/40 = 1.5 A, 40/12 ≈ 3.3 A, 40/5 = 8 A. The smallest current needs the smallest fuse.

Open this question

Question 41

Capacitors

A capacitor of 10μF is connected across a cell of 12 volts as shown above. Calculate the energy stored in the capacitor.

Diagram for this question
  1. A.7.2 × 10−4 J
  2. B.1.4 × 10−3 J
  3. C.1.4 × 10−4 J
  4. D.1.2 × 10−2 J
Show the answer and explanation

Answer: A (7.2 × 10−4 J)

Explanation

E = ½CV2 = ½ × 10 × 10−6 × 122 = 7.2 × 10−4 J.

Open this question

Question 42

Current Electricity

The heat produced in a conductor carrying an electric current is

  1. A.inversely proportional to the current and the resistance
  2. B.directly proportional to the current, resistance and the time
  3. C.inversely proportional to the square of the resistance, current and the time
  4. D.directly proportional to the square of the current, the resistance and the time.
Show the answer and explanation

Answer: D (directly proportional to the square of the current, the resistance and the time.)

Explanation

Joule's law: heat H = I2Rt.

Open this question

Question 44

Current Electricity

The maximum permissible current through a galvanometer G of internal resistance 10Ω is 0.05A. A resistance R is used to convert G into a voltmeter with a maximum reading of 100V. Find the value of R and how it is connected to G.

  1. A.20,000 ohms in parallel
  2. B.19,990 ohms in series
  3. C.1990 ohms in series
  4. D.100 ohms in series.
Show the answer and explanation

Answer: C (1990 ohms in series)

Explanation

A voltmeter needs a large resistance in series. Total resistance = 100/0.05 = 2000 Ω, so R = 2000 − 10 = 1990 Ω in series.

Open this question

Question 45

Alternating Current Circuits

In alternating current theory, the units of impedance, r.m.s. voltage and resonance frequency are respectively equal to

  1. A.volt, ampere and hertz
  2. B.ohm, volt and hertz
  3. C.watt, ohm and radian
  4. D.ohm, hertz and joule
Show the answer and explanation

Answer: B (ohm, volt and hertz)

Explanation

Impedance is a kind of resistance (ohm), r.m.s. voltage is a voltage (volt) and frequency is in hertz.

Open this question

Question 46

Alternating Current Circuits

In A.C. circuit theory, the root mean square (r.m.s) current, Irms, and the peak (maximum) current Io are related by

  1. A.Io = Irms/√2
  2. B.Irms = Io/√2
  3. C.Irms = 1/Io √2
  4. D.Io = 1/Irms √2.
Show the answer and explanation

Answer: B (Irms = Io/√2)

Explanation

For a sinusoidal current the r.m.s. value is the peak value divided by √2 (about 0.707 Io).

Open this question

Question 47

Radioactivity and Nuclear Physics

Which of the following graphs correctly illustrates the number of remaining atoms during a radioactive decay?

Diagram for this question
  1. A.Graph A
  2. B.Graph B
  3. C.Graph C
  4. D.Graph D
Show the answer and explanation

Answer: B (Graph B)

Explanation

The number of undecayed atoms starts at its largest value and falls exponentially, halving every half-life and approaching zero; graph B shows this curve starting from the initial number.

Open this question

Question 48

Modern Physics

The threshold frequency for photoelectric effect depends on the

  1. A.intensity of incident light
  2. B.frequency of incident light
  3. C.material of the photocathode
  4. D.potential difference between the cathode and the anode.
Show the answer and explanation

Answer: C (material of the photocathode)

Explanation

Threshold frequency f0 = work function ÷ h, and the work function is a property of the metal (the photocathode material).

Open this question

Question 49

Radioactivity and Nuclear Physics

After three half lifes, the fraction of a radioactive material that has decayed is

  1. A.1/8
  2. B.1/3
  3. C.2/3
  4. D.7/8
Show the answer and explanation

Answer: D (7/8)

Explanation

After three half-lives ½ × ½ × ½ = 1/8 remains, so 1 − 1/8 = 7/8 has decayed.

Open this question

Question 50

Radioactivity and Nuclear Physics

2713Al + 10n → 2411Na + X
In the nuclear reaction above, the product denoted by X is

  1. A.a proton
  2. B.a gamma ray
  3. C.a helium particle
  4. D.an alpha particle.
Show the answer and explanation

Answer: D (an alpha particle.)

Explanation

Mass numbers: 27 + 1 = 24 + 4; atomic numbers: 13 + 0 = 11 + 2. X has A = 4 and Z = 2, which is an alpha particle (42He).

Open this question