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JAMB Physics 1992 Question 33

Question 33

Electrostatics

Calculate the force acting on an electron of charge 1.6 × 10−19 C placed in an electric field of intensity 108 V m−1

  1. A.1.6 × 10−11 N
  2. B.1.6 × 10−14 N
  3. C.1.6 × 10−16 N
  4. D.1.0 × 10−16 N
Show the answer and explanation

Answer: A (1.6 × 10−11 N)

Explanation

F = qE = 1.6 × 10−19 × 108 = 1.6 × 10−11 N.