Question 41
CapacitorsA capacitor of 10μF is connected across a cell of 12 volts as shown above. Calculate the energy stored in the capacitor.

- A.7.2 × 10−4 J
- B.1.4 × 10−3 J
- C.1.4 × 10−4 J
- D.1.2 × 10−2 J
Show the answer and explanation
Answer: A (7.2 × 10−4 J)
Explanation
E = ½CV2 = ½ × 10 × 10−6 × 122 = 7.2 × 10−4 J.