JAMB Chemistry 2004 past questions and answers

43 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Separation of Mixtures

When a solid substance disappears completely as a gas on heating, the substance is said to have undergone

  1. A.evaporation
  2. B.distillation
  3. C.crystallization
  4. D.sublimation
Show the answer and explanation

Answer: D (sublimation)

Explanation

Sublimation is a change straight from solid to gas without melting, as with iodine or ammonium chloride.

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Question 2

Separation of Mixtures

A chemical reaction is always associated with

  1. A.an increase in the composition of one of the substances.
  2. B.a change in the volume of the reactants
  3. C.a change in the nature of the reactants
  4. D.the formation of new substances
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Answer: D (the formation of new substances)

Explanation

The defining feature of a chemical change is that new substances are formed.

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Question 3

Mole Concept and Stoichiometry

If a solution contains 4.9g of tetraoxosulphate(VI) acid, calculate the amount of copper (II) oxide that will react with it. [Cu = 64, O = 16, S = 32, H = 1]

  1. A.0.8g
  2. B.4.0g
  3. C.40.0g
  4. D.80.0g
Show the answer and explanation

Answer: B (4.0g)

Explanation

H2SO4 + CuO → CuSO4 + H2O (1 : 1). 4.9 g ÷ 98 = 0.05 mol, so CuO needed = 0.05 × 80 = 4.0 g.

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Question 4

Mole Concept and Stoichiometry

What volume of gas is evolved at s.t.p. if 2g of calcium trioxocarbonate (IV) is added to a solution of hydrochloric acid? [Ca = 40, C = 12, O = 16, Cl = 35.5, H = 1, Molar volume of a gas at s.t.p. = 22.4dm3]

  1. A.112cm3
  2. B.224cm3
  3. C.448cm3
  4. D.2240cm3
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Answer: C (448cm3)

Explanation

CaCO3 (100 g/mol) gives one mole of CO2 per mole. 2 g = 0.02 mol, so CO2 = 0.02 × 22 400 = 448 cm3.

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Question 5

Gas Laws

According to Charles' law, the volume of a gas becomes zero at

  1. A.0°C
  2. B.–100°C
  3. C.–273°C
  4. D.–373°C
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Answer: C (–273°C)

Explanation

Extending Charles' law (V ∝ T) to zero volume gives absolute zero, 0 K = –273°C.

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Question 6

Kinetic Theory and States of Matter

It is difficult to achieve an orderly arrangement of the molecules of a gas because they

  1. A.have no definite shape
  2. B.have little force of attraction between them
  3. C.can collide with one another in the container
  4. D.are too small in size.
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Answer: B (have little force of attraction between them)

Explanation

Gas molecules attract each other only very weakly, so nothing holds them in fixed, orderly positions; they move freely and randomly.

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Question 7

Gas Laws

A given volume of methane diffuses in 20s. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [C = 12, H = 1, S = 32, O = 16]

  1. A.5s
  2. B.20s
  3. C.40s
  4. D.60s
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Answer: C (40s)

Explanation

By Graham's law, time ∝ √(molar mass). t = 20 × √(64/16) = 20 × 2 = 40 s.

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Question 8

Atomic Structure

An electron can be added to a halogen atom to form a halide ion with

  1. A.2 valence electrons
  2. B.3 valence electrons
  3. C.7 valence electrons
  4. D.8 valence electrons
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Answer: D (8 valence electrons)

Explanation

A halogen atom has 7 valence electrons; gaining one electron gives the halide ion a full octet of 8.

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Question 9

Atomic Structure

The shape of the s-orbital is

  1. A.spherical
  2. B.elliptical
  3. C.spiral
  4. D.circular
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Answer: A (spherical)

Explanation

An s-orbital is spherically symmetrical around the nucleus.

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Question 10

Radioactivity

22688Ra → x86Rn + α – particle
What is the value of x in the nuclear reaction above?

  1. A.220
  2. B.222
  3. C.226
  4. D.227
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Answer: B (222)

Explanation

An alpha particle is 42He, so the mass number falls by 4: 226 – 4 = 222.

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Question 11

Chemical Bonding

The property of chlorine which causes hydrogen chloride to be more ionic than the chlorine molecule is its

  1. A.electrovalency
  2. B.electron affinity
  3. C.electropositivity
  4. D.electronegativity
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Answer: D (electronegativity)

Explanation

Chlorine is much more electronegative than hydrogen, so it pulls the shared electrons towards itself, making H–Cl polar. In Cl2 both atoms pull equally.

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Question 13

Air

Which of the following mixtures of gases is likely to burn in flame?

  1. A.neon and hydrogen
  2. B.nitrogen and helium
  3. C.helium and neon
  4. D.neon and nitrogen
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Answer: A (neon and hydrogen)

Explanation

Hydrogen is flammable, so the mixture containing hydrogen can burn; the other gases are inert or do not burn.

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Question 14

Air

In the experiment above, X is a mixture of nitrogen, carbon (IV) oxide and

Diagram for this question
  1. A.water
  2. B.impurities
  3. C.inert gas
  4. D.oxygen
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Answer: C (inert gas)

Explanation

Alkaline pyrogallol absorbs oxygen and anhydrous calcium chloride absorbs water vapour, so the gas leaving at X is mainly nitrogen with the inert (noble) gases.

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Question 15

Water

Hardness of water is caused by the presence of the ions of

  1. A.magnesium and silver
  2. B.calcium and magnesium
  3. C.sodium and potassium
  4. D.calcium and sodium
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Answer: B (calcium and magnesium)

Explanation

Dissolved Ca2+ and Mg2+ ions react with soap to form scum, which is what makes water hard.

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Question 16

Environmental Pollution

Pollution of underground water by metal ions is very likely in a soil that has high

  1. A.acidity
  2. B.alkalinity
  3. C.chloride content
  4. D.nitrate content
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Answer: A (acidity)

Explanation

Acid dissolves metal compounds in the soil, releasing metal ions that seep into groundwater. In alkaline soil metals stay as insoluble hydroxides.

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Question 17

Environmental Pollution

A carcinogenic substance is

  1. A.asbestos dust
  2. B.sawdust
  3. C.nitrogen (II) oxide
  4. D.carbon (II) oxide
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Answer: A (asbestos dust)

Explanation

Breathing in asbestos fibres is known to cause lung cancer, so asbestos dust is carcinogenic.

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Question 18

Solubility and Solutions

The solubility in mol dm-3 of 20g of CuSO4 dissolved in 100g of water at 180°C is [Cu = 64, S = 32, O = 16]

  1. A.0.13
  2. B.0.25
  3. C.1.25
  4. D.2.00
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Answer: C (1.25)

Explanation

CuSO4 = 160 g/mol, so 20 g = 0.125 mol in 100 g (about 100 cm3) of water. Per 1000 cm3: 0.125 × 10 = 1.25 mol dm-3.

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Question 20

Acids, Bases and Salts

Which of these compounds is a normal salt?

  1. A.NaHS
  2. B.NaHSO4
  3. C.NaHCO3
  4. D.Na2CO3
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Answer: D (Na2CO3)

Explanation

A normal salt has all the replaceable hydrogen of the acid replaced by a metal. Na2CO3 has none left; the others are acid salts.

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Question 22

Redox Reactions

The oxidation state of chlorine in HClO4 is

  1. A.–5
  2. B.–1
  3. C.+1
  4. D.+7
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Answer: D (+7)

Explanation

+1 (H) + x + 4(–2) = 0, so x = +7.

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Question 23

Redox Reactions

ZnO(s) + CO(g) → Zn(s) + CO2(g) (heat)
In the reaction above, zinc has been

  1. A.decomposed
  2. B.displaced
  3. C.oxidized
  4. D.reduced
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Answer: D (reduced)

Explanation

Zinc goes from +2 in ZnO to 0 in Zn; it loses oxygen and gains electrons, so it is reduced.

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Question 25

Electrolysis

In the electrolysis of brine, the anode is

  1. A.platinum
  2. B.copper
  3. C.zinc
  4. D.carbon
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Answer: D (carbon)

Explanation

Chlorine attacks most metals, so an inert carbon (graphite) anode is used in the industrial electrolysis of brine.

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Question 26

Electrolysis

The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is [Ag = 108, F = 96500 C mol-1]

  1. A.108.0g
  2. B.54.0g
  3. C.27.0g
  4. D.13.5g
Show the answer and explanation

Answer: B (54.0g)

Explanation

Q = 10 × 4830 = 48 300 C = 0.5 F. Ag+ + e- → Ag, so 0.5 mol Ag = 0.5 × 108 = 54 g.

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Question 28

Energy Changes

Which of the following hydrogen halides has the highest entropy value?

  1. A.HF
  2. B.HCl
  3. C.HBr
  4. D.HI
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Answer: D (HI)

Explanation

Standard entropy rises with molar mass and number of electrons down the group (HF ≈ 174, HI ≈ 207 J K-1 mol-1), so HI has the highest.

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Question 29

Chemical Equilibrium

N2O4(g) ⇌ 2NO2(g)
In the endothermic reaction above, more product formation will be favoured by

  1. A.a constant volume
  2. B.an increase in pressure
  3. C.a decrease in pressure
  4. D.a decrease in volume
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Answer: C (a decrease in pressure)

Explanation

One gas molecule gives two, so lowering the pressure shifts the equilibrium towards the side with more molecules, NO2.

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Question 31

Carbon and its Compounds

The allotrope of carbon used in the decolourization of sugar is

  1. A.graphite
  2. B.soot
  3. C.charcoal
  4. D.lampblack
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Answer: C (charcoal)

Explanation

Animal (bone) charcoal has a huge surface area and adsorbs the coloured impurities from sugar solution.

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Question 32

Halogens

Which of the following gases can be collected by the method of downward delivery?

  1. A.chlorine
  2. B.oxygen
  3. C.ammonia
  4. D.hydrogen
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Answer: A (chlorine)

Explanation

Downward delivery suits gases denser than air. Chlorine is about 2.5 times as dense as air; ammonia and hydrogen are lighter, and oxygen is collected over water.

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Question 33

Carbon and its Compounds

When steam is passed over red-hot carbon, the substances produced are

  1. A.hydrogen and trioxocarbonate (IV) acid
  2. B.hydrogen, oxygen and carbon (IV) oxide
  3. C.hydrogen and carbon (II) oxide
  4. D.hydrogen and carbon (IV) oxide
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Answer: C (hydrogen and carbon (II) oxide)

Explanation

C + H2O → CO + H2; this mixture of carbon(II) oxide and hydrogen is water gas.

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Question 34

Sulphur and its Compounds

Sulphur (IV) oxide bleaches by

  1. A.reduction
  2. B.oxidation
  3. C.hydration
  4. D.adsorption
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Answer: A (reduction)

Explanation

In water SO2 removes oxygen from (reduces) the dye to a colourless product; that is why its bleaching can wear off as air re-oxidises the dye.

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Question 35

Atomic Structure

Carbon is tetravalent because

  1. A.the electrons in both the 2s and 2p orbitals are equivalent
  2. B.the electrons in all the orbitals of carbon are equivalent
  3. C.the 2s and 2p atomic orbitals hybridize
  4. D.all the atomic orbitals of carbon hybridize
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Answer: C (the 2s and 2p atomic orbitals hybridize)

Explanation

One 2s electron is promoted and the 2s and three 2p orbitals mix (sp3 hybridisation), giving four equivalent half-filled orbitals that form four bonds.

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Question 36

Metals and their Compounds

Aluminium hydroxide is used in the dyeing industry as a

  1. A.salt
  2. B.dye
  3. C.mordant
  4. D.dispersant
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Answer: C (mordant)

Explanation

Aluminium hydroxide is a mordant: it sticks to the fibre and binds the dye to it so the colour does not wash out.

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Question 37

Metals and their Compounds

Alloys are best prepared by

  1. A.electroplating
  2. B.arc-welding
  3. C.reducing a mixture of their metallic oxides
  4. D.cooling a molten mixture of the metals.
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Answer: D (cooling a molten mixture of the metals.)

Explanation

Alloys are made by melting the metals together, mixing them and allowing the mixture to cool and solidify.

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Question 38

Metals and their Compounds

Transition metals possess variable oxidation states because they have

  1. A.electrons in the d orbitals
  2. B.electrons in the s orbitals
  3. C.a variable number of electrons in the p orbitals
  4. D.partially filled p orbitals
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Answer: A (electrons in the d orbitals)

Explanation

The 3d and 4s electrons are close in energy, so different numbers of d electrons can be used in bonding, giving several oxidation states.

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Question 39

Metals and their Compounds

Sodium metal is always kept under oil because it

  1. A.readily reacts with water
  2. B.is reduced by atmospheric nitrogen
  3. C.reacts vigorously on exposure to air
  4. D.reacts with oxygen and carbon(IV)oxide
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Answer: C (reacts vigorously on exposure to air)

Explanation

Sodium reacts rapidly with oxygen and moisture in air, so it is stored under paraffin oil to keep air away.

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Question 40

Hydrocarbons

Oxyacetylene flame is used for iron-welding because it

  1. A.makes the iron metal solidify very quickly
  2. B.combines with oxygen to give a pop sound
  3. C.evolves a lot of heat when burnt
  4. D.dissociates to produce carbon (IV) oxide and oxygen
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Answer: C (evolves a lot of heat when burnt)

Explanation

Ethyne burning in oxygen gives a very hot flame (about 3000°C), hot enough to melt iron.

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Question 41

Introduction to Organic Chemistry

The alkyl group can be represented by the general formula

  1. A.CnH2n+1
  2. B.CnH2n
  3. C.CnH2n+2
  4. D.CnH2n–2
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Answer: A (CnH2n+1)

Explanation

An alkyl group is an alkane (CnH2n+2) with one hydrogen removed: CnH2n+1, e.g. CH3–.

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Question 42

Introduction to Organic Chemistry

An isomer of C5H12 is

  1. A.butane
  2. B.2 – methylbutane
  3. C.2 – methylpropane
  4. D.2 – ethylbutane
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Answer: B (2 – methylbutane)

Explanation

2-methylbutane has 5 carbons and 12 hydrogens. Butane and 2-methylpropane are C4H10; 2-ethylbutane is really a C6 compound (3-methylpentane).

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Question 43

Hydrocarbons

A characteristic of the alkane family is

  1. A.addition reaction
  2. B.elimination reaction
  3. C.substitution reaction
  4. D.neutralization reaction
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Answer: C (substitution reaction)

Explanation

Alkanes are saturated, so they react by substitution, e.g. methane with chlorine in sunlight.

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Question 44

Hydrocarbons

Which of these reagents can confirm the presence of a triple bond?

  1. A.Bromine water
  2. B.Acidified KMnO4
  3. C.Copper (I) chloride
  4. D.Bromine gas
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Answer: C (Copper (I) chloride)

Explanation

Bromine water and KMnO4 are decolourised by both double and triple bonds. Ammoniacal copper(I) chloride gives a red precipitate only with alkynes having a terminal triple bond.

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Question 45

Polymers

Vulcanization involves the removal of

  1. A.a monomer
  2. B.the single bond
  3. C.the double bond
  4. D.a polymer
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Answer: C (the double bond)

Explanation

In vulcanization, sulphur reacts at the C=C double bonds of rubber, forming cross-links, so the double bonds are used up.

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Question 47

Alkanoic Acids and Esters

CH3COOH(g) → CH4(g) + CO2(g)
The reaction above is

  1. A.carboxylation
  2. B.decarboxylation
  3. C.acidification
  4. D.esterification
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Answer: B (decarboxylation)

Explanation

The –COOH group is removed as CO2, leaving methane: that is decarboxylation.

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Question 48

Alkanols

C2H5OH(aq) → Y (conc. H2SO4, 180°C)
In the reaction above, Y represents

  1. A.CH4
  2. B.C2H5COOH
  3. C.C2H4
  4. D.CH3OCH3
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Answer: C (C2H4)

Explanation

Excess concentrated sulphuric acid at about 180°C removes water from ethanol (dehydration), giving ethene, C2H4.

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Question 49

Alkanoic Acids and Esters

Alkanol + Alkanoic acid ⇌ Ester + Water
The reverse reaction of the equation above is known as

  1. A.hydrolysis
  2. B.saponification
  3. C.hydration
  4. D.fermentation
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Answer: A (hydrolysis)

Explanation

The reverse of esterification is the breaking of an ester by water into the acid and alkanol, which is hydrolysis.

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Question 50

Fats, Oils and Soaps

In the production of soap, concentrated sodium chloride solution is added to

  1. A.increase the solubility of the soap
  2. B.decrease the solubility of the soap
  3. C.saponify the soap
  4. D.emulsify the soap
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Answer: B (decrease the solubility of the soap)

Explanation

Adding brine lowers the solubility of soap so it separates out as a solid on top (salting out).

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