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JAMB Chemistry 2004 Question 26

Question 26

Electrolysis

The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is [Ag = 108, F = 96500 C mol-1]

  1. A.108.0g
  2. B.54.0g
  3. C.27.0g
  4. D.13.5g
Show the answer and explanation

Answer: B (54.0g)

Explanation

Q = 10 × 4830 = 48 300 C = 0.5 F. Ag+ + e- → Ag, so 0.5 mol Ag = 0.5 × 108 = 54 g.