Question 7
Gas LawsA given volume of methane diffuses in 20s. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [C = 12, H = 1, S = 32, O = 16]
- A.5s
- B.20s
- C.40s
- D.60s
Show the answer and explanation
Answer: C (40s)
Explanation
By Graham's law, time ∝ √(molar mass). t = 20 × √(64/16) = 20 × 2 = 40 s.