Question 3
Mole Concept and StoichiometryIf a solution contains 4.9g of tetraoxosulphate(VI) acid, calculate the amount of copper (II) oxide that will react with it. [Cu = 64, O = 16, S = 32, H = 1]
- A.0.8g
- B.4.0g
- C.40.0g
- D.80.0g
Show the answer and explanation
Answer: B (4.0g)
Explanation
H2SO4 + CuO → CuSO4 + H2O (1 : 1). 4.9 g ÷ 98 = 0.05 mol, so CuO needed = 0.05 × 80 = 4.0 g.