JAMB Chemistry 2000 past questions and answers

48 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 2

Separation of Mixtures

Sieving is a technique used to separate mixtures containing solid particles of

  1. A.small sizes
  2. B.large sizes
  3. C.different sizes
  4. D.the same size
Show the answer and explanation

Answer: C (different sizes)

Explanation

A sieve lets small particles through and holds back bigger ones, so it can only separate solids whose particle sizes are different.

Open this question

Question 3

Chemistry and Industry

Which of the following compounds is composed of Al, Si, O and H?

  1. A.Epsom salt
  2. B.Limestone
  3. C.Clay
  4. D.Urea
Show the answer and explanation

Answer: C (Clay)

Explanation

Clay is hydrated aluminium silicate, e.g. Al2Si2O5(OH)4, which contains Al, Si, O and H. Epsom salt is MgSO4·7H2O, limestone is CaCO3 and urea is CO(NH2)2.

Open this question

Question 4

Gas Laws

50 cm3 of carbon (II) oxide was exploded with 150 cm3 of air containing 20% oxygen by volume. Which of the reactants was in excess?

  1. A.Carbon (II) oxide
  2. B.Carbon (IV) oxide
  3. C.Oxygen
  4. D.Nitrogen
Show the answer and explanation

Answer: C (Oxygen)

Explanation

2CO + O2 → 2CO2, so 50 cm3 of CO needs only 25 cm3 of O2. The air holds 20% × 150 = 30 cm3 of O2, so oxygen is in excess.

Open this question

Question 5

Mole Concept and Stoichiometry

How many moles of HCl will be required to react with potassium heptaoxodichromate (VI) to produce 3 moles of chlorine?

  1. A.14
  2. B.12
  3. C.11
  4. D.10
Show the answer and explanation

Answer: A (14)

Explanation

K2Cr2O7 + 14HCl → 2KCl + 2CrCl3 + 7H2O + 3Cl2, so 14 moles of HCl give 3 moles of chlorine.

Open this question

Question 6

Gas Laws

The ratio of the initial to the final pressure of a given mass of gas is 1:1.5. Calculate the final volume of the gas if the initial volume was 300 cm3 at the same temperature.

  1. A.120 cm3
  2. B.200 cm3
  3. C.450 cm3
  4. D.750 cm3
Show the answer and explanation

Answer: B (200 cm3)

Explanation

Boyle's law: P1V1 = P2V2, so 1 × 300 = 1.5 × V2 and V2 = 200 cm3.

Open this question

Question 7

Gas Laws

The partial pressure of oxygen in a sample of air is 452 mm Hg and the total pressure is 780 mm Hg. What is the mole fraction of oxygen?

  1. A.0.203
  2. B.0.579
  3. C.2.030
  4. D.5.790
Show the answer and explanation

Answer: B (0.579)

Explanation

Mole fraction = partial pressure ÷ total pressure = 452 ÷ 780 = 0.579.

Open this question

Question 8

Kinetic Theory and States of Matter

The fundamental difference between the three states of matter is the

  1. A.shape of their particles
  2. B.number of particles in each state
  3. C.shape of the container they occupy
  4. D.degree of movement of their particles
Show the answer and explanation

Answer: D (degree of movement of their particles)

Explanation

Solids, liquids and gases are made of the same kind of particles; they differ in how freely the particles move (and how strongly they are held).

Open this question

Question 9

Atomic Structure

Which of the following statements is correct about the periodic table?

  1. A.Elements in the same period have the same number of valence electrons
  2. B.The valence electrons of the elements in the same period increase progressively across the period
  3. C.Elements in the same group have the same number of electron shells
  4. D.The non-metallic properties of the elements tend to decrease across each period
Show the answer and explanation

Answer: B (The valence electrons of the elements in the same period increase progressively across the period)

Explanation

Across a period one electron is added to the outer shell at each step, so the number of valence electrons rises. Non-metallic character increases, not decreases, across a period.

Open this question

Question 10

Atomic Structure

The electron configuration of 22X2+ ion is

  1. A.1s22s22p63s23p64s23d2
  2. B.1s22s22p63s23p64s23d1
  3. C.1s22s22p63s23p6
  4. D.1s22s22p63s23p64s2
Show the answer and explanation

Answer: D (1s22s22p63s23p64s2)

Explanation

The ion X2+ has 22 − 2 = 20 electrons, and D is the only option with 20 electrons. (Strictly, a transition metal loses its 4s electrons first, giving 1s22s22p63s23p63d2, but that is not offered.)

Open this question

Question 11

Chemical Bonding

Which of the following types of bonding does not involve the formation of new substance?

  1. A.Metallic
  2. B.Covalent
  3. C.Co-ordinate
  4. D.Electrovalent
Show the answer and explanation

Answer: A (Metallic)

Explanation

Metallic bonding holds atoms of the same metal together; no new compound is formed. Covalent, co-ordinate and electrovalent bonds join atoms into new substances.

Open this question

Question 12

Radioactivity

The knowledge of half-life can be used to

  1. A.create an element
  2. B.detect an element
  3. C.split an element
  4. D.irradiate an element
Show the answer and explanation

Answer: B (detect an element)

Explanation

Each radioactive isotope has its own fixed half-life, so measuring the half-life helps to identify (detect) the element.

Open this question

Question 13

Chemical Bonding

The shapes of CO2, H2O and CH4 respectively are

  1. A.bent, linear and tetrahedral
  2. B.bent, tetrahedral and linear
  3. C.linear, bent and tetrahedral
  4. D.tetrahedral, linear and bent
Show the answer and explanation

Answer: C (linear, bent and tetrahedral)

Explanation

CO2 has no lone pairs on carbon, so it is linear; the two lone pairs on oxygen make H2O bent; CH4 has four bond pairs, so it is tetrahedral.

Open this question

Question 14

Periodic Table

The distance between the nuclei of chlorine atoms in a chlorine molecule is 0.194 mm. The atomic radius of chlorine atom is

  1. A.0.097 mm
  2. B.0.194 mm
  3. C.0.388 mm
  4. D.2.388 mm
Show the answer and explanation

Answer: A (0.097 mm)

Explanation

The atomic (covalent) radius is half the distance between the two nuclei: 0.194 ÷ 2 = 0.097.

Open this question

Question 15

Periodic Table

The noble gas, argon, is used for

  1. A.electric arc welding
  2. B.welding brass
  3. C.underwater welding
  4. D.steel welding
Show the answer and explanation

Answer: A (electric arc welding)

Explanation

Argon is unreactive, so it is blown around the electric arc during welding to keep air away from the hot metal and stop it being oxidised.

Open this question

Question 16

Water

A side effect of soft water is that

  1. A.it gives offensive taste
  2. B.excess calcium is precipitated
  3. C.it attacks lead contained in pipes
  4. D.it encourages the growth of bacteria
Show the answer and explanation

Answer: C (it attacks lead contained in pipes)

Explanation

Soft water lacks the dissolved calcium salts that coat pipes, so it can dissolve poisonous lead from lead pipes (plumbosolvency).

Open this question

Question 17

Metals and their Compounds

Water molecules can be ligands especially when they are bonded to

  1. A.alkaline earth metals
  2. B.alkali metals
  3. C.transition metals
  4. D.group VII elements
Show the answer and explanation

Answer: C (transition metals)

Explanation

Transition metal ions have empty d-orbitals that accept lone pairs from water molecules, forming complex ions such as [Cu(H2O)6]2+.

Open this question

Question 18

Environmental Pollution

The air pollutant unknown in nature is

  1. A.NO
  2. B.CO
  3. C.HCHO
  4. D.DDT
Show the answer and explanation

Answer: D (DDT)

Explanation

NO, CO and methanal (HCHO) are all produced by natural processes, but DDT is a synthetic insecticide made only by man.

Open this question

Question 19

Solubility and Solutions

1.0 dm3 of distilled water was used to wash 2.0 g of a precipitate of AgCl. If the solubility product of AgCl is 2.0 × 10−10 mol2dm−6, what quantity of silver was lost in the process?

  1. A.2.029 × 10−3 mol dm−3
  2. B.1.414 × 10−3 mol dm−3
  3. C.2.029 × 10−5 mol dm−3
  4. D.1.414 × 10−5 mol dm−3
Show the answer and explanation

Answer: D (1.414 × 10−5 mol dm−3)

Explanation

Solubility = √Ksp = √(2.0 × 10−10) = 1.414 × 10−5 mol dm−3, so that much silver dissolves in the wash water.

Open this question

Question 20

Energy Changes

Hydration of ions in solution is associated with

  1. A.absorption of heat
  2. B.reduction of heat
  3. C.conduction of heat
  4. D.liberation of heat
Show the answer and explanation

Answer: D (liberation of heat)

Explanation

When water molecules surround and attract ions, energy is given out, so hydration is exothermic (heat is liberated).

Open this question

Question 21

Solubility and Solutions

The diagram above is the solubility curve of a solute, X. Find the amount of X deposited when 500cm3 of a solution of X is cooled from 60°C to 20°C.

Diagram for this question
  1. A.0.750 mole
  2. B.0.950 mole
  3. C.2.375 moles
  4. D.4.750 moles
Show the answer and explanation

Answer: A (0.750 mole)

Explanation

From the curve the solubility falls by about 1.5 mol dm−3 between 60°C and 20°C. In 500 cm3 (0.5 dm3), 1.5 × 0.5 = 0.75 mole is deposited.

Open this question

Question 22

Acids, Bases and Salts

HCl(aq) + H2O(l) ⇌ H3O+(aq) + Cl−(aq)
In the reaction above, Cl−(aq) is the

  1. A.conjugate acid
  2. B.acid
  3. C.conjugate base
  4. D.base
Show the answer and explanation

Answer: C (conjugate base)

Explanation

HCl gives away a proton and becomes Cl−, so Cl− is the conjugate base of the acid HCl.

Open this question

Question 24

Acids, Bases and Salts

The pOH of a solution of 0.25 mol dm−3 of hydrochloric acid is

  1. A.12.40
  2. B.13.40
  3. C.14.40
  4. D.14.60
Show the answer and explanation

Answer: B (13.40)

Explanation

pH = −log 0.25 = 0.60, so pOH = 14 − 0.60 = 13.40.

Open this question

Question 25

Redox Reactions

MnO4−(aq) + 8H+(aq) + Y → Mn2+(aq) + 4H2O(l)
Y in the equation above represents

  1. A.2e−
  2. B.3e−
  3. C.5e−
  4. D.7e−
Show the answer and explanation

Answer: C (5e−)

Explanation

Manganese goes from +7 in MnO4− to +2, so it gains 5 electrons. (Charge check: −1 + 8 − 5 = +2.)

Open this question

Question 26

Electrolysis

½Zn2+(aq) + e− → ½Zn(s)
In the reaction above, calculate the quantity of electricity required to discharge zinc. [F = 96 500 C mol−1]

  1. A.0.965 × 104 C
  2. B.4.820 × 104 C
  3. C.9.650 × 104 C
  4. D.48.200 × 104 C
Show the answer and explanation

Answer: C (9.650 × 104 C)

Explanation

The equation as written uses one mole of electrons, which is 1 faraday = 96 500 C = 9.650 × 104 C.

Open this question

Question 27

Electrolysis

Given that M is the mass of substance deposited in an electrolysis and Q the quantity of electricity consumed, then Faraday's law can be written as

  1. A.M = Z/Q
  2. B.M = Q/Z
  3. C.M = Z/2Q
  4. D.M = QZ
Show the answer and explanation

Answer: D (M = QZ)

Explanation

Faraday's first law says the mass deposited is proportional to the charge passed: M = ZQ, where Z is the electrochemical equivalent.

Open this question

Question 28

Energy Changes

0.46g of ethanol when burned raised the temperature of 50 g of water by 14.3 K. Calculate the heat of combustion of ethanol.
[C = 12, O = 16, H = 1, Specific heat capacity of water = 4.2 Jg−1K−1]

  1. A.+3000 kJ mol−1
  2. B.+300 kJ mol−1
  3. C.−300 kJ mol−1
  4. D.−3000 kJ mol−1
Show the answer and explanation

Answer: C (−300 kJ mol−1)

Explanation

Heat = 50 × 4.2 × 14.3 ≈ 3003 J. 0.46 g of ethanol (M = 46) is 0.01 mol, so 3003 ÷ 0.01 ≈ 300 kJ mol−1; combustion gives out heat, so ΔH = −300 kJ mol−1.

Open this question

Question 29

Rates of Reaction

Powdered marble reacts faster with hydrochloric acid solution than the granular form because the powdered form has

  1. A.more molecules
  2. B.more atoms
  3. C.larger surface area
  4. D.relatively large mass
Show the answer and explanation

Answer: C (larger surface area)

Explanation

Powder exposes much more surface to the acid, so more particles collide per second and the reaction is faster.

Open this question

Question 30

Rates of Reaction

The graph that describes a zero order reaction is

Diagram for this question
  1. A.A
  2. B.B
  3. C.C
  4. D.D
Show the answer and explanation

Answer: B (B)

Explanation

In a zero order reaction the rate does not depend on concentration, so the graph of rate against concentration is a horizontal line (graph B).

Open this question

Question 31

Chemical Equilibrium

N2(g) + O2(g) ⇌ 2NO(g); ΔH = + 180.6kJ mol−1
In the reaction above, increase in temperature will

  1. A.increase the quantity of N2
  2. B.increase the yield of NO
  3. C.decrease the yield of NO
  4. D.decrease the quantity of O2
Show the answer and explanation

Answer: B (increase the yield of NO)

Explanation

The forward reaction is endothermic (ΔH positive), so raising the temperature shifts the equilibrium to the right and more NO is formed.

Open this question

Question 32

Chemical Equilibrium

For a reaction in equilibrium, the species involved in the equilibrium constant expression are

  1. A.gaseous and solid species
  2. B.liquid and solid species
  3. C.solid and dissolved species
  4. D.gaseous and dissolved species
Show the answer and explanation

Answer: D (gaseous and dissolved species)

Explanation

Pure solids and pure liquids have constant concentrations, so only gases and dissolved species appear in the equilibrium constant expression.

Open this question

Question 33

Carbon and its Compounds

A phenomenon where an element exists in different forms in the same physical state is known as

  1. A.isomerism
  2. B.amorphism
  3. C.allotropy
  4. D.isotopy
Show the answer and explanation

Answer: C (allotropy)

Explanation

Allotropy is the existence of an element in two or more forms in the same physical state, e.g. diamond and graphite.

Open this question

Question 34

Polymers

The substance often use for vulcanization of rubber is

  1. A.chlorine
  2. B.hydrogen peroxide
  3. C.sulphur
  4. D.tetraoxosulphate (VI) acid.
Show the answer and explanation

Answer: C (sulphur)

Explanation

Vulcanization is heating rubber with sulphur, which forms cross-links and makes the rubber harder and more elastic.

Open this question

Question 35

Environmental Pollution

A gas that is not associated with global warming is

  1. A.CO2
  2. B.SO3
  3. C.CH4
  4. D.H2
Show the answer and explanation

Answer: D (H2)

Explanation

CO2 and CH4 are greenhouse gases and sulphur oxides are atmospheric pollutants; hydrogen does not trap heat in the atmosphere.

Open this question

Question 36

Carbon and its Compounds

The refreshing and characteristic taste of soda water and other soft drinks is as a result of the presence in them of

  1. A.carbon (IV) oxide
  2. B.carbon (II) oxide
  3. C.soda
  4. D.glucose
Show the answer and explanation

Answer: A (carbon (IV) oxide)

Explanation

Soft drinks are carbonated: carbon (IV) oxide is dissolved in them under pressure, giving the fizz and slightly sharp taste.

Open this question

Question 37

Carbon and its Compounds

A form of carbon used for absorbing poisonous gases and purification of noble gases is

  1. A.wood charcoal
  2. B.animal charcoal
  3. C.carbon fibres
  4. D.carbon black
Show the answer and explanation

Answer: A (wood charcoal)

Explanation

Wood charcoal (activated) has a huge porous surface that adsorbs gases, so it is used in gas masks and to purify gases.

Open this question

Question 38

Petroleum and Coal

Synthesis gas is a mixture of

  1. A.CH4 and H2O
  2. B.CH4 and H2
  3. C.CO2 and H2
  4. D.CO and H2
Show the answer and explanation

Answer: D (CO and H2)

Explanation

Synthesis gas (syngas) is a mixture of carbon (II) oxide and hydrogen, made by passing steam over hot methane or coke.

Open this question

Question 39

Qualitative Analysis

Potassium vapour burns with a

  1. A.blue flame
  2. B.brick-red flame
  3. C.violet flame
  4. D.golden-yellow flame
Show the answer and explanation

Answer: C (violet flame)

Explanation

Potassium compounds and vapour give a lilac (violet) flame; sodium gives golden-yellow and calcium brick-red.

Open this question

Question 40

Metals and their Compounds

A common characteristics of copper and silver in their usage as coinage metals is that they

  1. A.have high metallic lustre
  2. B.are not easily oxidized
  3. C.are easily oxidized
  4. D.are not easily reduced.
Show the answer and explanation

Answer: B (are not easily oxidized)

Explanation

Coins must last a long time, and copper and silver are low in the activity series, so they do not corrode (get oxidized) easily.

Open this question

Question 41

Metals and their Compounds

Haematite is an ore of

  1. A.zinc
  2. B.lead
  3. C.iron
  4. D.copper
Show the answer and explanation

Answer: C (iron)

Explanation

Haematite is Fe2O3, the main ore of iron.

Open this question

Question 42

Metals and their Compounds

The least easily oxidized of the metals below is

  1. A.Ca
  2. B.Na
  3. C.Zn
  4. D.Al
Show the answer and explanation

Answer: C (Zn)

Explanation

Of these metals zinc is lowest in the activity series, so it loses electrons least readily.

Open this question

Question 43

Polymers

The repeating unit in natural rubber is

  1. A.alkyne
  2. B.isoprene
  3. C.n-propene
  4. D.neoprene
Show the answer and explanation

Answer: B (isoprene)

Explanation

Natural rubber is a polymer of isoprene (2-methylbuta-1,3-diene). Neoprene is a synthetic rubber.

Open this question

Question 44

Hydrocarbons

Unsaturated organic compounds are identified by decolourization of

  1. A.silver bromine and potassium tetraoxomanganate (VII) solutions
  2. B.bromine water and acidified potassium tetraoxomanganate (VII) solution
  3. C.silver bromide solution and bromine water
  4. D.bromine water and alkaline potassium tetraoxomanganate (VII) solution.
Show the answer and explanation

Answer: B (bromine water and acidified potassium tetraoxomanganate (VII) solution)

Explanation

A C=C or C≡C bond decolourises reddish-brown bromine water and purple acidified potassium tetraoxomanganate (VII) solution.

Open this question

Question 45

Alkanols

The conditions necessary for the extraction of a water molecule from two molecules of ethanol are

  1. A.less acid and a lower temperature
  2. B.excess acid and a lower temperature
  3. C.excess acid and a higher temperature
  4. D.less acid and a higher temperature
Show the answer and explanation

Answer: A (less acid and a lower temperature)

Explanation

Removing one water molecule from two ethanol molecules gives ethoxyethane (ether); this needs excess ethanol (less acid) at a lower temperature (about 140°C). Excess acid at 170°C gives ethene.

Open this question

Question 46

Hydrocarbons

The chlorinated alkane often used industrially to remove grease is

  1. A.tetrachloromethane
  2. B.chloromethane
  3. C.trichloromethane
  4. D.dichloromethane
Show the answer and explanation

Answer: A (tetrachloromethane)

Explanation

Tetrachloromethane (CCl4) is a good non-polar solvent for oils and grease and was widely used in dry cleaning.

Open this question

Question 47

Hydrocarbons

The reaction of carbide with water gives

  1. A.ethyne
  2. B.ethene
  3. C.ethane
  4. D.ethanal
Show the answer and explanation

Answer: A (ethyne)

Explanation

Calcium carbide reacts with water: CaC2 + 2H2O → Ca(OH)2 + C2H2 (ethyne).

Open this question

Question 48

Alkanoic Acids and Esters

CH3—CH2—C(=O)—OCH2CH3
The compound above is an

  1. A.ether
  2. B.ester
  3. C.alkanal
  4. D.alkanol
Show the answer and explanation

Answer: B (ester)

Explanation

The —COO— group joining two alkyl groups is the ester linkage; this is ethyl propanoate.

Open this question

Question 49

Alkanals and Alkanones

Alkanones are generally obtained by the oxidation of

  1. A.primary alkanols
  2. B.secondary alkanols
  3. C.tertiary alkanols
  4. D.alkanoic acid.
Show the answer and explanation

Answer: B (secondary alkanols)

Explanation

Oxidising a secondary alkanol gives an alkanone (ketone); primary alkanols give alkanals and acids, and tertiary alkanols resist oxidation.

Open this question

Question 50

Carbohydrates, Proteins and Amines

Sucrose is made up of

  1. A.glucose and glucose
  2. B.glucose and fructose
  3. C.fructose and fructose
  4. D.galactose and glucose.
Show the answer and explanation

Answer: B (glucose and fructose)

Explanation

Sucrose is a disaccharide; hydrolysis splits it into one glucose and one fructose unit.

Open this question