Question 21
Solubility and SolutionsThe diagram above is the solubility curve of a solute, X. Find the amount of X deposited when 500cm3 of a solution of X is cooled from 60°C to 20°C.
- A.0.750 mole
- B.0.950 mole
- C.2.375 moles
- D.4.750 moles
Show the answer and explanation
Answer: A (0.750 mole)
Explanation
From the curve the solubility falls by about 1.5 mol dm−3 between 60°C and 20°C. In 500 cm3 (0.5 dm3), 1.5 × 0.5 = 0.75 mole is deposited.