Question 24
Acids, Bases and SaltsThe pOH of a solution of 0.25 mol dm−3 of hydrochloric acid is
- A.12.40
- B.13.40
- C.14.40
- D.14.60
Show the answer and explanation
Answer: B (13.40)
Explanation
pH = −log 0.25 = 0.60, so pOH = 14 − 0.60 = 13.40.
The pOH of a solution of 0.25 mol dm−3 of hydrochloric acid is
Answer: B (13.40)
pH = −log 0.25 = 0.60, so pOH = 14 − 0.60 = 13.40.