Question 26
Electrolysis½Zn2+(aq) + e− → ½Zn(s)
In the reaction above, calculate the quantity of electricity required to discharge zinc. [F = 96 500 C mol−1]
- A.0.965 × 104 C
- B.4.820 × 104 C
- C.9.650 × 104 C
- D.48.200 × 104 C
Show the answer and explanation
Answer: C (9.650 × 104 C)
Explanation
The equation as written uses one mole of electrons, which is 1 faraday = 96 500 C = 9.650 × 104 C.