JAMB Chemistry 1989 past questions and answers

46 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Separation of Mixtures

Which of the following would support the conclusion that a solid sample is a mixture?

  1. A.The solid can be ground to a fine powder.
  2. B.The density of the solid is 2.25 g dm3.
  3. C.The solid has a melting range of 300°C to 375°C.
  4. D.The solid absorbs moisture from the atmosphere
Show the answer and explanation

Answer: C (The solid has a melting range of 300°C to 375°C.)

Explanation

A pure substance melts sharply at one temperature. Melting over a wide range (300–375 °C) shows the solid is a mixture.

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Question 2

Chemical Formulae and Equations

The molar ratio of carbon to hydrogen of a volatile liquid compound is 1:2. 0.12 g of the liquid on evaporation at s.t.p. gave 32 cm3 of vapour. The molecular formula of the liquid is [G.M.V = 22.4 dm3, C = 12, H = 1]

  1. A.C3H6
  2. B.C4H8
  3. C.C5C10
  4. D.C6H12
Show the answer and explanation

Answer: D (C6H12)

Explanation

Molar mass = 0.12 × 22400/32 = 84 g. The empirical formula CH2 has mass 14, and 84/14 = 6, so the formula is C6H12.

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Question 3

Kinetic Theory and States of Matter

From the vapour pressure curves of liquids I, II and III shown, it can be deduced that

Diagram for this question
  1. A.liquid I has the highest boiling point
  2. B.liquid II has the highest boiling point
  3. C.liquid III has the highest boiling point
  4. D.liquid III has the lowest boiling point.
Show the answer and explanation

Answer: C (liquid III has the highest boiling point)

Explanation

A liquid boils when its vapour pressure reaches the external pressure (the horizontal line). Liquid III reaches it at the highest temperature, so it has the highest boiling point.

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Question 4

Volumetric Analysis

20.00 cm3 of a solution containing 0.53 g of anhydrous Na2CO3 in 100 cm3 requires 25.00 cm3 of H2SO4 for complete neutralisation. The concentration of the acid solution in moles per dm3 is [H = 1, C = 12, O = 16, Na = 23, S = 32]

  1. A.0.02
  2. B.0.04
  3. C.0.06
  4. D.0.08
Show the answer and explanation

Answer: B (0.04)

Explanation

Na2CO3 concentration = 5.3 g dm−3 ÷ 106 = 0.05 M. The reaction is 1 : 1, so MA × 25 = 0.05 × 20, giving MA = 0.04 mol dm−3.

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Question 5

Gas Laws

The minimum volume of oxygen required for the complete combustion of a mixture of 10 cm3 of CO and 15 cm3 of H2 is

  1. A.25.0 cm3
  2. B.12.5 cm3
  3. C.10.0 cm3
  4. D.5.0 cm3.
Show the answer and explanation

Answer: B (12.5 cm3)

Explanation

2CO + O2 → 2CO2, so 10 cm3 CO needs 5 cm3 O2. 2H2 + O2 → 2H2O, so 15 cm3 H2 needs 7.5 cm3. Total = 12.5 cm3.

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Question 6

Gas Laws

What is the partial pressure of hydrogen gas collected over water at standard atmospheric pressure and 25°C if the saturation vapour pressure of water is 23 mm Hg at that temperature?

  1. A.737 mm Hg
  2. B.763 mm Hg
  3. C.777 mm Hg
  4. D.783 mm Hg.
Show the answer and explanation

Answer: A (737 mm Hg)

Explanation

By Dalton's law the total pressure is the sum of the partial pressures: p(H2) = 760 − 23 = 737 mm Hg.

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Question 7

Periodic Table

The atomic radius of Li, Na and K are 1.33A, 1.54A and 1.96A respectively. Which of the following explains this gradation in atomic radius?

  1. A.Electropositivity decreases from Li to Na to K
  2. B.Electronegativity decreases from Li to Na to K.
  3. C.The number of electron shells increases from Li to Na to K.
  4. D.The elements are in the same period.
Show the answer and explanation

Answer: C (The number of electron shells increases from Li to Na to K.)

Explanation

Going down group 1, each element has one more shell of electrons (Li 2 shells, Na 3, K 4), so the atoms get bigger.

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Question 8

Gas Laws

Which of the curves W, X, Y and Z in the graph of PV/RT against P illustrates the behaviour of an ideal gas?

Diagram for this question
  1. A.W
  2. B.X
  3. C.Y
  4. D.Z
Show the answer and explanation

Answer: C (Y)

Explanation

For one mole of an ideal gas PV = RT, so PV/RT = 1 at every pressure. That is the horizontal line Y.

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Question 9

Atomic Structure

Elements X and Y have electronic configurations 1s22s22p4 and 1s22s22p63s23p1 respectively. When they combine, the formula of the compound formed is

  1. A.XY
  2. B.YX
  3. C.X2Y3
  4. D.Y2X3.
Show the answer and explanation

Answer: D (Y2X3.)

Explanation

X (oxygen) has valency 2 and Y (aluminium) has valency 3. Exchanging valencies gives Y2X3, like Al2O3.

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Question 10

Atomic Structure

The atomic number of caesium is 55 and its atomic mass is 133. The nucleus of caesium atom therefore contains

  1. A.78 protons and 55 electrons
  2. B.55 protons and 78 neutrons
  3. C.55 protons and 78 electrons
  4. D.78 protons and 55 neutrons.
Show the answer and explanation

Answer: B (55 protons and 78 neutrons)

Explanation

Protons = atomic number = 55; neutrons = 133 − 55 = 78. Electrons are outside the nucleus.

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Question 11

Atomic Structure

Four elements P, Q, R and S have atomic numbers of 4, 10, 12 and 14 respectively. Which of these elements is a noble gas?

  1. A.P
  2. B.Q
  3. C.R
  4. D.S
Show the answer and explanation

Answer: B (Q)

Explanation

Element 10 (neon) has the configuration 2, 8, a full outer shell, so it is a noble gas.

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Question 12

Atomic Structure

How many valence electrons are contained in the element represented by 3115P?

  1. A.3
  2. B.5
  3. C.15
  4. D.31
Show the answer and explanation

Answer: B (5)

Explanation

Phosphorus has 15 electrons arranged 2, 8, 5, so it has 5 electrons in its outer (valence) shell.

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Question 14

Environmental Pollution

The gaseous pollutant sulphur (IV) oxide is most likely to be detected in fairly reasonable quantities in the area around a plant for the

  1. A.extraction of aluminium from bauxite
  2. B.production of margarine
  3. C.smelting of copper
  4. D.production of chlorine from brine.
Show the answer and explanation

Answer: C (smelting of copper)

Explanation

Copper ores are often sulphides. Roasting and smelting them gives off large amounts of sulphur (IV) oxide.

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Question 16

Mole Concept and Stoichiometry

A hydrated salt of formula MSO4.xH2O contains 45.3% by mass of water of crystallisation. Calculate the value of x. [M = 56, S = 32, O = 16, H = 1]

  1. A.3
  2. B.5
  3. C.7
  4. D.10
Show the answer and explanation

Answer: C (7)

Explanation

MSO4 = 152. 18x/(152 + 18x) = 0.453, so 18x × 0.547 = 68.9 and x ≈ 7.

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Question 18

Volumetric Analysis

Using 50 cm3 of 1 M potassium hydroxide and 100 cm3 of 1 M tetraoxosulphate (VI) acid, calculate the respective volumes in cm3 of base and acid that would be required to produce the maximum amount of potassium tetraoxosulphate (IV). [K = 39, S = 32, O = 16, H = 1]

  1. A.50,50
  2. B.25,50
  3. C.50,25
  4. D.25,25
Show the answer and explanation

Answer: C (50,25)

Explanation

2KOH + H2SO4 → K2SO4 + 2H2O. The most salt comes from using all the base: 50 cm3 of 1 M KOH (0.05 mol) needs 0.025 mol acid, which is 25 cm3.

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Question 19

Mole Concept and Stoichiometry

A solution of calcium bromide contains 20 g dm−3. What is the molarity of the solution with respect to calcium bromide and bromide ions? [Ca = 40, Br = 80]

  1. A.0.1, 0.1
  2. B.0.1, 0.2
  3. C.0.1, 0.05
  4. D.0.05, 0.1
Show the answer and explanation

Answer: B (0.1, 0.2)

Explanation

CaBr2 has M = 200, so 20 g dm−3 is 0.1 M. Each formula unit gives 2 Br− ions, so [Br−] = 0.2 M.

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Question 20

Hydrogen, Oxygen and Oxides

The substance ZnO dissolves in sodium hydroxide solution and mineral acid solution to give soluble products in each case. ZnO is therefore referred to as

  1. A.an allotropic oxide
  2. B.an amphoteric oxide
  3. C.a peroxide
  4. D.a dioxide
Show the answer and explanation

Answer: B (an amphoteric oxide)

Explanation

An oxide that reacts with both acids and alkalis to form salts is amphoteric.

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Question 21

Acids, Bases and Salts

An acid and its conjugate base

  1. A.can neutralise each other to form a salt
  2. B.differ only by a proton
  3. C.differ only by the opposite charges they carry
  4. D.are always neutral substances
Show the answer and explanation

Answer: B (differ only by a proton)

Explanation

In the Brønsted–Lowry theory a conjugate base is what is left when an acid loses one proton (H+), e.g. HCl and Cl−.

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Question 22

Electrolysis

The same current is passed for the same time through solutions of AgNO3 and CuSO4 connected in series. How much silver will be deposited if 1.0 g of copper is produced? [Cu = 63.5, S = 32, O = 16, Ag = 108, N = 14]

  1. A.1.7 g
  2. B.3.4 g
  3. C.6.8 g
  4. D.13.6 g
Show the answer and explanation

Answer: B (3.4 g)

Explanation

1.0 g Cu = 1/63.5 mol, which needs 2/63.5 F. The same charge deposits 2/63.5 mol of Ag: 108 × 2/63.5 = 3.4 g.

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Question 23

Electrolysis

What is discharged at the cathode during the electrolysis of copper (II) tetraoxosulphate (VI) solution?

  1. A.Cu2+ only
  2. B.H+ only
  3. C.Cu2+ and H+
  4. D.Cu2+ and SO42−
Show the answer and explanation

Answer: A (Cu2+ only)

Explanation

Both Cu2+ and H+ move to the cathode, but copper is lower in the electrochemical series, so only Cu2+ is discharged as copper metal.

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Question 24

Redox Reactions

An element, Z forms an anion whose formula is [Z(CN)6]y. If Z has an oxidation number of +2, what is the value of y?

  1. A.−2
  2. B.−3
  3. C.−4
  4. D.−5
Show the answer and explanation

Answer: C (−4)

Explanation

Each CN− contributes −1, so y = +2 + 6(−1) = −4.

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Question 25

Redox Reactions

Which of the reactions below is NOT an example of a redox reaction?
I Fe + 2Ag+ → Fe2+ + 2Ag
II 2H2S + SO2 → 2H2O + 3S
III N2 + O2 ⇌ 2NO
IV CaCO3 → CaO + CO2

  1. A.I, II and III
  2. B.II and III
  3. C.III and IV
  4. D.IV only
Show the answer and explanation

Answer: D (IV only)

Explanation

In I, II and III oxidation numbers change. In the decomposition of CaCO3 every element keeps its oxidation number (Ca +2, C +4, O −2), so IV is not redox.

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Question 27

Energy Changes

The combustion of ethene, C2H4, is given by the equation C2H4 + 3O2 → 2CO2 + 2H2O; ΔH = −1428 kJ. If the molar heats of formation of water and carbon (IV) oxide are −286 kJ and −396 kJ respectively, calculate the molar heat of formation of ethene in kJ

  1. A.−2792
  2. B.+2792
  3. C.−64
  4. D.+64
Show the answer and explanation

Answer: D (+64)

Explanation

ΔH = ΣH(products) − ΣH(reactants): −1428 = 2(−396) + 2(−286) − H(C2H4) = −1364 − H(C2H4). So H(C2H4) = +64 kJ.

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Question 28

Chemical Equilibrium

CO(g) + H2O(g) ⇌ CO2(g) + H2(g), ΔH = −41000 J. Which of the following factors favour the formation of hydrogen in the above reaction?
I. high pressure II. low pressure III. High temperature IV. Use of excess steam

  1. A.I, III and IV
  2. B.III only
  3. C.II, III and I
  4. D.IV only
Show the answer and explanation

Answer: D (IV only)

Explanation

There are 2 moles of gas on each side, so pressure has no effect. The forward reaction is exothermic, so high temperature works against it. Excess steam pushes the equilibrium to the right.

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Question 29

Kinetic Theory and States of Matter

The graph shows a typical heating curve from the solid phase through the liquid phase to the gaseous phase of a substance. Which part of the curve shows solid and liquid in equilibrium?

Diagram for this question
  1. A.T
  2. B.U
  3. C.X
  4. D.Y
Show the answer and explanation

Answer: A (T)

Explanation

While a solid melts, its temperature stays constant, giving the first flat part of the curve (T). There, solid and liquid exist together.

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Question 30

Nitrogen and its Compounds

Which of the following represents the balanced equation for the reaction of copper with concentrated trioxonitrate (V) acid?

  1. A.Cu(s) + 2HNO3(aq) → Cu(NO3)2(aq) + H2(g)
  2. B.Cu(s) + 4HNO3(aq) → Cu(NO3)2(aq) + 2H2O(l) + 2NO2(g)
  3. C.3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(aq) + 4H2O(l) + 2NO(g)
  4. D.3Cu(s) + 4HNO3(aq) → 3Cu(NO3)2(aq) + 2H2O(l) + 2NO(g).
Show the answer and explanation

Answer: B (Cu(s) + 4HNO3(aq) → Cu(NO3)2(aq) + 2H2O(l) + 2NO2(g))

Explanation

Concentrated HNO3 is reduced to brown nitrogen (IV) oxide: Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2. Option C is for dilute acid, and D is not balanced.

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Question 31

Sulphur and its Compounds

The catalyst used in the contact process for the manufacture of tetraoxosulphate (VI) acid is

  1. A.manganese (IV) oxide
  2. B.manganese (II) tetraoxosulphate (VI)
  3. C.vanadium (V) oxide
  4. D.iron metal.
Show the answer and explanation

Answer: C (vanadium (V) oxide)

Explanation

In the contact process SO2 is oxidised to SO3 over a vanadium (V) oxide catalyst. Iron is the catalyst for the Haber process.

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Question 32

Petroleum and Coal

Some products of destructive distillation of coal are

  1. A.carbon (IV) oxide and ethanoic acid
  2. B.trioxocarbonate (IV) acid and methanoic acid
  3. C.producer gas and water gas
  4. D.coke and ammonia liquor.
Show the answer and explanation

Answer: D (coke and ammonia liquor.)

Explanation

Heating coal without air gives coke, coal tar, ammoniacal liquor and coal gas. Producer gas and water gas are made from coke afterwards.

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Question 33

Redox Reactions

Gunpowder is made from charcoal, sulphur and potassium trioxonitrate (V). The salt in the mixture performs the function of

  1. A.an oxidant
  2. B.a reductant
  3. C.a solvent
  4. D.a catalyst
Show the answer and explanation

Answer: A (an oxidant)

Explanation

Potassium trioxonitrate (V) releases oxygen on heating, so it oxidises the charcoal and sulphur very quickly.

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Question 34

Redox Reactions

Which of the following reactions is (are) feasible?
I Br2(l) + 2Cl−(aq) → 2Br−(aq) + Cl2(g)
II 2I−(aq) + Br2(l) → 2Br−(aq) + I2(s)
III 2F−(aq) + Cl2(g) → 2Cl−(aq) + F2(g)
IV 2F−(aq) + Br2(l) → 2Br−(aq) + F2(g)

  1. A.I
  2. B.II
  3. C.I and III
  4. D.III and IV
Show the answer and explanation

Answer: B (II)

Explanation

A halogen can only displace a halogen below it in the group. Bromine is more reactive than iodine, so II works; bromine and chlorine cannot displace chlorine or fluorine.

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Question 35

Halogens

Bleaching powder, CaOCl2.H2O, deteriorates on exposure to air because

  1. A.it loses its water of crystallization
  2. B.atmospheric nitrogen displaces chlorine from it
  3. C.carbon (IV) oxide of the atmosphere displaces chlorine from it
  4. D.bleaching agents should be stored in solution.
Show the answer and explanation

Answer: C (carbon (IV) oxide of the atmosphere displaces chlorine from it)

Explanation

Carbon (IV) oxide in air reacts with bleaching powder to form calcium carbonate and release chlorine, so the powder slowly loses its available chlorine.

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Question 36

Nitrogen and its Compounds

The products of the thermal decomposition of ammonium trioxonitrate (V) are

  1. A.NO2 and oxygen
  2. B.NH3 and oxygen
  3. C.nitrogen and water
  4. D.N2O and water.
Show the answer and explanation

Answer: D (N2O and water.)

Explanation

NH4NO3 → N2O + 2H2O on gentle heating; this is how nitrogen (I) oxide is prepared.

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Question 37

Metals and their Compounds

The scale of a chemical balance is made of iron plate and coated with copper electrolytically because

  1. A.iron is less susceptible to corrosion than copper
  2. B.copper is twice as susceptible to corrosion as iron
  3. C.copper is less susceptible to corrosion than iron
  4. D.copper and iron are equally susceptible to corrosion
Show the answer and explanation

Answer: C (copper is less susceptible to corrosion than iron)

Explanation

Copper is less reactive than iron and corrodes much less, so a copper coating protects the iron from rusting.

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Question 38

Metals and their Compounds

A metal is extracted from its ore by the electrolysis of its molten chloride and it displaces lead from lead (II) trioxonitrate (V) solution. The metal is

  1. A.copper
  2. B.aluminium
  3. C.zinc
  4. D.sodium
Show the answer and explanation

Answer: D (sodium)

Explanation

Sodium is extracted by electrolysing molten sodium chloride, and being far above lead in the activity series it can displace lead. Aluminium is extracted from its oxide, and copper and zinc are not made from molten chlorides.

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Question 39

Chemistry and Industry

Mortar is NOT used for under-water construction because

  1. A.it hardens by loss of water
  2. B.its hardening does not depend upon evaporation
  3. C.it requires concrete to harden
  4. D.it will be washed away by the flow of water.
Show the answer and explanation

Answer: A (it hardens by loss of water)

Explanation

Mortar sets as its water evaporates (and it absorbs CO2 from the air). Under water it cannot dry out, so it does not harden.

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Question 40

Metals and their Compounds

Which of the following is NOT involved in the extraction of metals from their ores?

  1. A.Reduction with carbon
  2. B.Reduction with other metals
  3. C.Reduction by electrolysis
  4. D.Oxidation with oxidizing agents
Show the answer and explanation

Answer: D (Oxidation with oxidizing agents)

Explanation

Metals occur as compounds in which they are positively charged, so extraction always reduces them. Oxidising agents would do the opposite.

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Question 41

Introduction to Organic Chemistry

Which of the following compounds is an isomer of the compound CH3–CH2–CH(CH3)–CH2–CH3?

  1. A.CH3–CH2–CH(CH2CH3)–CH2–CH3
  2. B.CH3–CH2–CH(CH2CH3)–CH3
  3. C.CH3–CH2–CH(CH3)–CH3
  4. D.CH3–CH(CH3)–CH2–CH2–CH3
Show the answer and explanation

Answer: D (CH3–CH(CH3)–CH2–CH2–CH3)

Explanation

The compound is 3-methylpentane, C6H14. Option D (2-methylpentane) has the same formula but a different structure. A has 7 carbons, C has 5, and B is the same compound drawn differently.

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Question 42

Hydrocarbons

When excess chlorine is mixed with ethene at room temperature, the product is

  1. A.1,2–dichloroethane
  2. B.1,2–dichloroethene
  3. C.1,1–dichloroethane
  4. D.1, 1–dichloroethene.
Show the answer and explanation

Answer: A (1,2–dichloroethane)

Explanation

Chlorine adds across the C=C double bond, one Cl on each carbon: CH2=CH2 + Cl2 → CH2Cl–CH2Cl, 1,2-dichloroethane.

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Question 43

Polymers

Vulcanization of rubber is a process by which

  1. A.isoprene units are joined to produce rubber
  2. B.rubber latex is coagulated
  3. C.sulphur is chemically combined in the rubber
  4. D.water is removed from the rubber.
Show the answer and explanation

Answer: C (sulphur is chemically combined in the rubber)

Explanation

In vulcanisation rubber is heated with sulphur, which forms cross-links between the chains, making the rubber harder and more elastic.

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Question 44

Acids, Bases and Salts

The reaction between ethanoic acid and sodium hydroxide is an example of

  1. A.esterification
  2. B.neutralization
  3. C.hydroxylation
  4. D.hydrolysis
Show the answer and explanation

Answer: B (neutralization)

Explanation

An acid reacting with a base to form a salt (sodium ethanoate) and water is neutralisation.

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Question 45

Chemical Bonding

The bond which joins two ethanoic acid molecules in the liquid state is

  1. A.a covalent bond
  2. B.an ionic bond
  3. C.a dative covalent bond
  4. D.a hydrogen bond.
Show the answer and explanation

Answer: D (a hydrogen bond.)

Explanation

The –OH hydrogen of one ethanoic acid molecule is attracted to the C=O oxygen of another, forming hydrogen bonds (the molecules pair up as dimers).

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Question 46

Fats, Oils and Soaps

The alkaline hydrolysis of fats and oils produces soap and

  1. A.propane 1, 1, 3-triol
  2. B.propane-1,3,3-triol
  3. C.propane-1,2,2-triol
  4. D.propane-1,2,3-triol
Show the answer and explanation

Answer: D (propane-1,2,3-triol)

Explanation

Saponification of a fat gives soap and glycerol, which is propane-1,2,3-triol.

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Question 47

Polymers

Which of the following is NOT a monomer?

  1. A.C6H6 (benzene)
  2. B.CH2 = CH2
  3. C.CH2 = CHCl
  4. D.C6H5CH = CH2 (phenylethene)
Show the answer and explanation

Answer: A (C6H6 (benzene))

Explanation

Ethene, chloroethene and phenylethene (styrene) have a C=C double bond and polymerise. Benzene's stable ring does not undergo addition polymerisation.

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Question 48

Introduction to Organic Chemistry

What is the IUPAC name for the compound CH2 = C(CH3)CH2Cl?

  1. A.1-chloro-2-methylprop-2, 3-ene
  2. B.1-chloro-2-methylprop-2-ene
  3. C.3-chloro-2-methylprop-1-ene
  4. D.3-chloro-2-methylprop-1, 2-ene.
Show the answer and explanation

Answer: C (3-chloro-2-methylprop-1-ene)

Explanation

The double bond gets the lowest number, so it is between C1 and C2 (prop-1-ene). The methyl group is on C2 and the chlorine on C3.

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Question 49

Hydrocarbons

The gas responsible for most of the fatal explosions in coal mines is

  1. A.butane
  2. B.ethene
  3. C.ethane
  4. D.methane
Show the answer and explanation

Answer: D (methane)

Explanation

Methane (firedamp) collects in coal mines and forms explosive mixtures with air.

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Question 50

Hydrocarbons

Three liquids X, Y and Z containing only hydrogen and carbon were burnt on a spoon. X and Y burnt with sooty flames while Z did not. Y is able to discharge the colour of bromine water whereas X and Z cannot. Which of the liquids would be aromatic in nature?

  1. A.X and Z
  2. B.Y
  3. C.X
  4. D.Z
Show the answer and explanation

Answer: C (X)

Explanation

Aromatic hydrocarbons have a high carbon content and burn with a sooty flame, but they do not decolourise bromine water. Y decolourises it, so it is an alkene or alkyne; X is the aromatic one.

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