Question 18
Volumetric AnalysisUsing 50 cm3 of 1 M potassium hydroxide and 100 cm3 of 1 M tetraoxosulphate (VI) acid, calculate the respective volumes in cm3 of base and acid that would be required to produce the maximum amount of potassium tetraoxosulphate (IV). [K = 39, S = 32, O = 16, H = 1]
- A.50,50
- B.25,50
- C.50,25
- D.25,25
Show the answer and explanation
Answer: C (50,25)
Explanation
2KOH + H2SO4 → K2SO4 + 2H2O. The most salt comes from using all the base: 50 cm3 of 1 M KOH (0.05 mol) needs 0.025 mol acid, which is 25 cm3.