JAMB Physics 2009 past questions and answers

47 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Gravitational Field

The values of x, y and z respectively in the expression MxLyTz for the universal gravitational constant G are

  1. A.2, −3, −2.
  2. B.−1, 3, −2.
  3. C.−1, 2, −3.
  4. D.−2, −1, 3.
Show the answer and explanation

Answer: B (−1, 3, −2.)

Explanation

From F = Gm1m2/r2, G = Fr2/m2 = (MLT−2)(L2) ÷ M2 = M−1L3T−2. So x = −1, y = 3, z = −2.

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Question 2

Measurement and Units

I. Diameter of a small ball bearing.
II. Thickness of a piece of paper.
III. Diameter of a measuring cylinder.
IV. Length of a piece of wire.
Which of the above can be measured using a micrometer screw gauge?

  1. A.I, II and IV only
  2. B.I and II only
  3. C.II and III only.
  4. D.III and IV only
Show the answer and explanation

Answer: B (I and II only)

Explanation

A micrometer screw gauge measures very small lengths (to 0.01 mm), such as the diameter of a ball bearing or the thickness of paper. A measuring cylinder or a length of wire is too big for it.

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Question 3

Scalars and Vectors

An aircraft attempts to fly due north at 100 kmh−1. If the wind blows against it from east to west at 60 kmh−1, its resultant velocity is

  1. A.117kmh−1, N31°E.
  2. B.127kmh−1, N31°E.
  3. C.117kmh−1, N31°W.
  4. D.127kmh−1, N31°W.
Show the answer and explanation

Answer: C (117kmh−1, N31°W.)

Explanation

Magnitude = √(1002 + 602) ≈ 117 km h−1. The wind pushes it westward, at tan−1(60/100) ≈ 31° west of north: N31°W.

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Question 4

Motion

What is the acceleration between two points on a velocity-time graph which has coordinates (10s, 15 ms−1) and (20 s, 35 m s−1)?

  1. A.1.75 ms−2
  2. B.3.50 ms−2
  3. C.1.00 ms−2
  4. D.2.00 ms−2
Show the answer and explanation

Answer: D (2.00 ms−2)

Explanation

Acceleration is the slope of the velocity-time graph: (35 − 15) ÷ (20 − 10) = 20 ÷ 10 = 2.00 m s−2.

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Question 5

Motion

A car accelerates uniformly from rest at 4ms−2. How far will it travel in the fifth complete second?

  1. A.100 m
  2. B.50 m
  3. C.32 m
  4. D.18 m
Show the answer and explanation

Answer: D (18 m)

Explanation

Distance in 5 s = ½ × 4 × 52 = 50 m; distance in 4 s = ½ × 4 × 42 = 32 m. In the fifth second it travels 50 − 32 = 18 m.

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Question 6

Equilibrium of Forces

Which of the diagrams below shows the position at which a small ball-bearing is in neutral equilibrium?

Diagram for this question
  1. A.A
  2. B.B
  3. C.C
  4. D.D
Show the answer and explanation

Answer: D (D)

Explanation

On a flat surface (D) the ball stays at rest wherever it is moved, so it is in neutral equilibrium. At the bottom of a bowl it is stable; on top of a dome it is unstable.

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Question 7

Newton's Laws and Momentum

A body of mass 12 kg travelling at 4.2 ms−1 collides with a second body of mass 18 kg at rest. Calculate their common velocity if the two bodies coalesce after collision.

  1. A.1.5 ms−1.
  2. B.1.4 ms−1.
  3. C.2.1 ms−1.
  4. D.1.7 ms−1.
Show the answer and explanation

Answer: D (1.7 ms−1.)

Explanation

Momentum is conserved: 12 × 4.2 = (12 + 18)v, so v = 50.4 ÷ 30 = 1.68 ≈ 1.7 m s−1.

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Question 8

Motion

A bullet fired vertically upward from a gun held 2.0 m above the ground reaches its maximum height in 4.0 s. Calculate its initial velocity. [g ≈ 10 ms−2]

  1. A.10 ms−1.
  2. B.8 ms−1.
  3. C.40 ms−1.
  4. D.20 ms−1.
Show the answer and explanation

Answer: C (40 ms−1.)

Explanation

At maximum height the velocity is zero: 0 = u − gt, so u = gt = 10 × 4.0 = 40 m s−1. The 2.0 m height of the gun does not matter.

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Question 9

Motion

I. The motion of the tyres of a moving car.
II. The motion of a loaded test tube oscillating vertically.
III. The beating of the heart.
IV. A stone tied to a string and whirled round.
V. The motion of the pistons in a gasoline engine.
Which of the motions above is simple harmonic?

  1. A.III, IV and V only
  2. B.II, III and V only
  3. C.II, III and IV only
  4. D.I, II and III only
Show the answer and explanation

Answer: B (II, III and V only)

Explanation

A loaded test tube bobbing in water, the heartbeat and an engine piston all move to and fro about a fixed point, which is simple harmonic motion. Tyres and a whirled stone go round in circles (rotational/circular motion).

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Question 10

Work, Energy and Power

If a cage containing a truck of coal weighing 750 kg is raised to a height of 90 m in 1 minute, what is the total power expended? [g ≈ 10 ms−2]

  1. A.11.50 kW
  2. B.12.60 kW
  3. C.11.25 kW
  4. D.12.10 kW
Show the answer and explanation

Answer: C (11.25 kW)

Explanation

Power = mgh/t = 750 × 10 × 90 ÷ 60 = 11 250 W = 11.25 kW.

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Question 11

Friction

An object of mass 80 kg is pulled on a horizontal rough ground by a force of 500 N. Find the coefficient of static friction. [g ≈ 10 ms−2]

  1. A.0.8.
  2. B.0.4.
  3. C.1.0.
  4. D.0.6.
Show the answer and explanation

Answer: D (0.6.)

Explanation

Taking 500 N as the force needed to overcome friction, μ = F/R = 500 ÷ (80 × 10) = 0.625 ≈ 0.6.

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Question 12

Simple Machines

If a heavy barrel is rolled up a plane inclined at 30° to the horizontal, its velocity ratio will be

  1. A.3.0.
  2. B.3.1.
  3. C.3.2.
  4. D.2.0.
Show the answer and explanation

Answer: D (2.0.)

Explanation

For an inclined plane VR = 1/sin θ = 1/sin 30° = 1/0.5 = 2.0.

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Question 13

Friction

The terminal velocity of a ball-bearing falling through a viscous fluid is reached when the

  1. A.upthrust is equal to the weight of the ball.
  2. B.ball accelerates uniformly.
  3. C.upthrust is equal to the velocity of the ball.
  4. D.velocity is unform.
Show the answer and explanation

Answer: D (velocity is unform.)

Explanation

At terminal velocity the weight is balanced by upthrust plus viscous drag, so the resultant force is zero and the ball falls at a constant (uniform) velocity.

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Question 14

Pressure

I. Density of the liquid.
II. Acceleration due to gravity
III. Type of container of the liquid
IV. The constituents of the liquid.
Which of the above conditions will NOT affect the pressure of fluids?

  1. A.I and III only
  2. B.II and III only
  3. C.III and IV only
  4. D.I and II only
Show the answer and explanation

Answer: C (III and IV only)

Explanation

Fluid pressure is p = hρg, so it depends on depth, density and g. It does not depend on the shape or type of container, or on what the liquid is made of apart from its density.

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Question 15

Elasticity

The diagram above represents the graph of the force (F) applied in stretching a spiral spring against the corresponding extension(X). The force constant of the spring is

Diagram for this question
  1. A.20 Nm−1.
  2. B.40 Nm−1.
  3. C.30 Nm−1.
  4. D.10 Nm−1.
Show the answer and explanation

Answer: A (20 Nm−1.)

Explanation

The force constant is the slope of the F–X graph. The line reaches F = 120 at X = 6, so k = 120 ÷ 6 = 20 N m−1 (for example 40 at 2).

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Question 16

Elasticity

If a load of mass 10N stretches a cord by 1.2cm, what is the total work done?

  1. A.6.0 × 10−2J
  2. B.7.6 × 10−2J
  3. C.1.8 × 10−2J
  4. D.6.6 × 10−2J
Show the answer and explanation

Answer: A (6.0 × 10−2J)

Explanation

Work done in stretching = ½Fe = ½ × 10 × 0.012 = 0.06 J = 6.0 × 10−2 J.

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Question 17

Density and Upthrust

A plastic sphere floats in water with 50% of its volume submerged. If it floats in glycerine with 40% of its volume submerged, the density of the glycerine is [density of water = 1000 kgm−3]

  1. A.1400 kgm−3.
  2. B.1250 kgm−3.
  3. C.500 kgm−3.
  4. D.1000 kgm−3.
Show the answer and explanation

Answer: B (1250 kgm−3.)

Explanation

The upthrust equals the same weight in both liquids: 1000 × 0.5V = ρ × 0.4V, so ρ = 500 ÷ 0.4 = 1250 kg m−3.

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Question 18

Temperature and Thermometers

The thermometer whose reading is indicated by a change in colour of its thermometric property is the

  1. A.bi-metallic strip thermometer.
  2. B.thermocouple.
  3. C.platinum resistance thermometer.
  4. D.optical pyrometer.
Show the answer and explanation

Answer: D (optical pyrometer.)

Explanation

An optical pyrometer measures very high temperatures by matching the colour (brightness) of a hot body with a filament.

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Question 19

Thermal Expansion

At 4°C, the volume of a fixed mass of water is

  1. A.constant.
  2. B.minimum.
  3. C.maximum.
  4. D.zero.
Show the answer and explanation

Answer: B (minimum.)

Explanation

Water is densest at 4°C (anomalous expansion). Since mass is fixed, maximum density means minimum volume.

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Question 20

Gas Laws

The pressure of two moles of an ideal gas at a temperature of 27°C and volume 10−2m3 is [R = 8.313 J mol−1K−1]

  1. A.4.99 × 105 Nm−2.
  2. B.9.80 × 103 Nm−2.
  3. C.4.98 × 103 Nm−2.
  4. D.9.80 × 105 Nm−2.
Show the answer and explanation

Answer: A (4.99 × 105 Nm−2.)

Explanation

PV = nRT, so P = 2 × 8.313 × 300 ÷ 10−2 ≈ 4.99 × 105 N m−2.

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Question 21

Quantity of Heat

An electric heater rated 220 V, 1000 W is immersed into a bucket full of water. Calculate the mass of water if the temperature changes from 30°C to 100°C and the current flows for 300 seconds. [specific heat capacity of water = 4200 J kg−1 K−1]

  1. A.4.28 kg.
  2. B.42.86 kg.
  3. C.1.02 kg.
  4. D.7.14 kg.
Show the answer and explanation

Answer: C (1.02 kg.)

Explanation

Heat given = Pt = 1000 × 300 = 300 000 J = mcΔθ. m = 300 000 ÷ (4200 × 70) ≈ 1.02 kg.

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Question 22

Change of State and Vapours

If the pressure of the vapour on top of an enclosed liquid is equal to the atmospheric pressure, what will be the temperature of the liquid enclosed?

  1. A.Room temperature
  2. B.Boiling point
  3. C.Freezing point
  4. D.Standard temperature
Show the answer and explanation

Answer: B (Boiling point)

Explanation

A liquid boils when its saturated vapour pressure equals the external (atmospheric) pressure, so the liquid is at its boiling point.

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Question 23

Change of State and Vapours

A heating coil rated 1000 W is used to boil off completely 2 kg of boiling water. The time required to boil off the water is [specific latent heat of vaporization of water = 2.3 × 106 Jkg−1]

  1. A.1.15 × 104 s.
  2. B.1.15 × 103 s.
  3. C.4.6 × 104 s.
  4. D.4.6 × 103 s.
Show the answer and explanation

Answer: D (4.6 × 103 s.)

Explanation

Heat needed = mL = 2 × 2.3 × 106 = 4.6 × 106 J. Time = 4.6 × 106 ÷ 1000 = 4.6 × 103 s.

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Question 24

Structure of Matter and Kinetic Theory

It is observed that water will wet a clean glass because the

  1. A.cohesion of water to glass is stronger than the cohesion of water molecules.
  2. B.adhesion of water molecules is weaker than the cohesion of water to glass.
  3. C.cohesion of water to glass is weaker than the cohesion of water molecules.
  4. D.adhesion of water molecules is stronger than the cohesion of water molecules.
Show the answer and explanation

Answer: D (adhesion of water molecules is stronger than the cohesion of water molecules.)

Explanation

Water wets glass because the adhesion between water and glass molecules is stronger than the cohesion between water molecules, so water spreads over the glass.

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Question 25

Heat Transfer

A man standing 2 m from a charcoal fire is warmed mainly by

  1. A.convection.
  2. B.radiation.
  3. C.refraction.
  4. D.conduction.
Show the answer and explanation

Answer: B (radiation.)

Explanation

Hot air from the fire rises upwards (convection), and air conducts poorly, so the heat reaching a person standing beside the fire comes mainly by radiation.

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Question 26

Waves

The wave phenomenon demonstrated in the diagram above is

Diagram for this question
  1. A.reflection.
  2. B.deflection.
  3. C.diffraction.
  4. D.refraction.
Show the answer and explanation

Answer: C (diffraction.)

Explanation

Straight waves pass through a narrow slit and spread out as curved waves on the other side. Spreading through a gap is diffraction.

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Question 27

Waves

A progressive wave is represented by y = 10 sin (1000 t − πx/34). Two layers of the wave separated by 153cm have a phase difference of

  1. A.270°.
  2. B.45°.
  3. C.90°.
  4. D.180°.
Show the answer and explanation

Answer: C (90°.)

Explanation

Phase difference = πx/34 = π × 153/34 = 4.5π rad = 810°. Removing two whole cycles (720°) leaves 90°.

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Question 28

Sound

Metal cables are used as telephone wires because

  1. A.they are cheap.
  2. B.they are sourced locally.
  3. C.the speed of sound in them is very low.
  4. D.the speed of sound in them is very high
Show the answer and explanation

Answer: D (the speed of sound in them is very high)

Explanation

Sound (and signals) travel very fast in metals, much faster than in air, so metal wires carry messages quickly.

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Question 29

Sound

Musical instruments playing the same note can be distinguished from one another owing to the differences in their

  1. A.quality.
  2. B.pitch.
  3. C.intensity.
  4. D.loudness.
Show the answer and explanation

Answer: A (quality.)

Explanation

The same note has the same pitch, but each instrument adds different overtones, giving it a different quality (timbre).

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Question 31

Light and Reflection

I. Moon II. Sun III. Street light IV. Stars
Which of the above is a natural source of light?

  1. A.II, III and IV only
  2. B.I, II and III only
  3. C.III and IV only
  4. D.II and IV only
Show the answer and explanation

Answer: D (II and IV only)

Explanation

The sun and stars produce their own light naturally. The moon only reflects sunlight, and a street light is man-made.

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Question 32

Light and Reflection

An object is placed 5cm from the pole of a concave mirror. If the focal length of the mirror is 10 cm, what is the image distance?

  1. A.10 cm in front of the mirror
  2. B.5 cm in front of the mirror
  3. C.10 cm behind the mirror
  4. D.5 cm behind the mirror
Show the answer and explanation

Answer: C (10 cm behind the mirror)

Explanation

1/v = 1/f − 1/u = 1/10 − 1/5 = −1/10, so v = −10 cm. The negative sign means a virtual image 10 cm behind the mirror.

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Question 33

Light and Reflection

Calculate the position of an object placed in front of a convex mirror having focal length of 12cm such that an image is formed 6cm away from the mirror.

  1. A.4.0 cm.
  2. B.3.0 cm.
  3. C.12.0 cm.
  4. D.9.0 cm.
Show the answer and explanation

Answer: C (12.0 cm.)

Explanation

With real-is-positive signs, f = −12 cm and v = −6 cm (virtual). 1/u = 1/f − 1/v = −1/12 + 1/6 = 1/12, so u = 12 cm.

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Question 34

Refraction of Light

If the refractive index of crown glass is 1.51, its critical angle is

  1. A.48.6°.
  2. B.22.5°.
  3. C.41.5°.
  4. D.45.0°.
Show the answer and explanation

Answer: C (41.5°.)

Explanation

sin C = 1/n = 1/1.51 = 0.662, so C ≈ 41.5°.

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Question 35

Refraction of Light

When light passes through two media x and y of refractive indices 1.51 and 1.33 respectively, the speed of light in

  1. A.x is same as in y.
  2. B.x and y is same as in vacuum.
  3. C.x is higher than in y.
  4. D.y is higher than in x.
Show the answer and explanation

Answer: D (y is higher than in x.)

Explanation

The speed of light in a medium is c/n. The smaller refractive index (y, 1.33) gives the higher speed.

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Question 37

Lenses and Optical Instruments

The ability of the human eye to focus objects on the retina is referred to as the power of

  1. A.interference.
  2. B.diffraction.
  3. C.accommodation.
  4. D.superposition.
Show the answer and explanation

Answer: C (accommodation.)

Explanation

The ciliary muscles change the thickness of the eye lens so that near and far objects are focused on the retina. This is accommodation.

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Question 38

Dispersion of Light and Colours

Which of the following is a secondary colour?

  1. A.Blue
  2. B.Orange
  3. C.Red
  4. D.Green
Show the answer and explanation

Answer: B (Orange)

Explanation

Blue, red and green are primary colours. Orange is made by mixing primaries, so it is the secondary colour among the options.

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Question 39

Electrostatics

If negative charges are induced on an electroscope and a positively charged rod is brought near the cap of the electroscope, the leaves will

  1. A.close up.
  2. B.become positively charged.
  3. C.become negatively charged.
  4. D.open further.
Show the answer and explanation

Answer: A (close up.)

Explanation

The positive rod attracts electrons from the leaves up to the cap. The leaves lose their negative charge, so they collapse (close up).

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Question 40

Current Electricity

Calculate the e.m.f. of the cell in the above circuit if its internal resistance is negligible.

Diagram for this question
  1. A.12V.
  2. B.8V.
  3. C.2V.
  4. D.36V.
Show the answer and explanation

Answer: B (8V.)

Explanation

3 Ω and 6 Ω in parallel give (3 × 6)/(3 + 6) = 2 Ω. With 4.0 A flowing, E = IR = 4 × 2 = 8 V.

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Question 41

Electrical Energy and Power

An electric lamp marked 240V, 60W is left to operate for an hour. How much energy is generated by the filament?

  1. A.3.86 × 105 J
  2. B.3.56 × 105 J
  3. C.1.80 × 104 J
  4. D.2.16 × 105 J
Show the answer and explanation

Answer: D (2.16 × 105 J)

Explanation

Energy = power × time = 60 × 3600 = 216 000 J = 2.16 × 105 J.

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Question 42

Electromagnetic Induction

A band of 500 rectangular loops of wire of area 20 cm by 20 cm, encloses a region of magnetic field which changes from 1.0T to 0.4T within 5 seconds, calculate the induced e.m.f.

  1. A.5.60 V.
  2. B.24.00 V.
  3. C.0.24 V.
  4. D.2.40 V.
Show the answer and explanation

Answer: D (2.40 V.)

Explanation

Area = 0.2 × 0.2 = 0.04 m2. E = NAΔB/Δt = 500 × 0.04 × 0.6 ÷ 5 = 2.4 V.

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Question 44

Alternating Current Circuits

From the diagram above, if the potential difference across the resistor, capacitor and inductor are 80 V, 110 V and 40 V respectively, the effective potential difference is

Diagram for this question
  1. A.116.3 V.
  2. B.50.0 V.
  3. C.230.0 V.
  4. D.106.3 V.
Show the answer and explanation

Answer: D (106.3 V.)

Explanation

In a series a.c. circuit V = √(VR2 + (VC − VL)2) = √(802 + 702) = √11 300 ≈ 106.3 V.

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Question 45

Electromagnetic Spectrum

Cancerous cells can be destroyed by

  1. A.ultraviolet rays.
  2. B.alpha particles.
  3. C.x-rays.
  4. D.infrared rays.
Show the answer and explanation

Answer: C (x-rays.)

Explanation

High-energy X-rays (and gamma rays) penetrate the body and kill cancer cells in radiotherapy.

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Question 46

Radioactivity and Nuclear Physics

If the decay constant of a radioactive substance is 0.231s−1, the half-life is

  1. A.3.00s.
  2. B.0.12s.
  3. C.0.33s.
  4. D.1.50s.
Show the answer and explanation

Answer: A (3.00s.)

Explanation

T½ = 0.693/λ = 0.693 ÷ 0.231 = 3.00 s.

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Question 47

Radioactivity and Nuclear Physics

A piece of radioactive material contains 1020 atoms. If the half-life of the material is 20 seconds, the number of disintegrations in the first second is

  1. A.3.47 × 1018.
  2. B.6.93 × 1020.
  3. C.3.47 × 1020.
  4. D.6.93 × 1018.
Show the answer and explanation

Answer: A (3.47 × 1018.)

Explanation

Decay constant λ = 0.693 ÷ 20 = 0.0347 s−1. Activity = λN = 0.0347 × 1020 = 3.47 × 1018 per second.

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Question 48

Modern Physics

Thermionic emission is the process whereby

  1. A.β-rays are produced.
  2. B.holes are produced.
  3. C.x-rays are produced.
  4. D.electrons leave a hot element.
Show the answer and explanation

Answer: D (electrons leave a hot element.)

Explanation

In thermionic emission, heating a metal gives its free electrons enough energy to escape from its surface.

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Question 49

Electronics

Which of the following can conduct electricity owing to the presence of free mobile electrons?

  1. A.Germanium
  2. B.Silicon
  3. C.Grapefruit
  4. D.Copper
Show the answer and explanation

Answer: D (Copper)

Explanation

Copper is a metal with many free electrons, so it conducts readily. Germanium and silicon have very few free electrons at room temperature.

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Question 50

Electronics

When a pentavalent impurity is added to a pure semiconductor, it becomes

  1. A.a p-type semiconductor.
  2. B.an n-type semiconductor.
  3. C.an insulator.
  4. D.an intrinsic semiconductor.
Show the answer and explanation

Answer: B (an n-type semiconductor.)

Explanation

A pentavalent atom has five valence electrons; one is left free, giving extra negative carriers, so the material becomes n-type.

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