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JAMB Physics 2009 Question 16

Question 16

Elasticity

If a load of mass 10N stretches a cord by 1.2cm, what is the total work done?

  1. A.6.0 × 10−2J
  2. B.7.6 × 10−2J
  3. C.1.8 × 10−2J
  4. D.6.6 × 10−2J
Show the answer and explanation

Answer: A (6.0 × 10−2J)

Explanation

Work done in stretching = ½Fe = ½ × 10 × 0.012 = 0.06 J = 6.0 × 10−2 J.