Two forces whose resultant is 100 N, are at right angles to each other. If one of them makes an angle of 30° with the resultant, determine its magnitude.
A.8.66 N
B.50.0 N
C.57.7 N
D.86.6 N
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Answer: D (86.6 N)
Explanation
The component of the resultant along that force is 100 cos 30° = 86.6 N.
When taking a penalty kick, a footballer applies a force of 30.0 N for a period of 0.05 s. If the mass of the ball is 0.075 kg, calculate the speed with which the ball moves off.
A.4.50 m s−1
B.11.25 m s−1
C.20.00 m s−1
D.45.00 m s−1.
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Answer: C (20.00 m s−1)
Explanation
Impulse = change in momentum: 30 × 0.05 = 0.075 × v, so v = 1.5/0.075 = 20 m s−1.
A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s−1, the angular speed of the larger wheel is
A.3 rev s−1
B.40 rev s−1
C.360 rev s−1
D.2400 rev s−1
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Answer: B (40 rev s−1)
Explanation
The same number of teeth pass the contact point on each wheel, so speed × teeth is equal: 120 × 20 = ω × 60, giving ω = 40 rev s−1. The bigger wheel turns more slowly.
The figure above shows the displacement – time graphs for three different motions. Which of the following statements is correct?
A.Graph 2 corresponds to the highest velocity
B.Graph 1 corresponds to zero velocity
C.Graph 3 corresponds to a particle moving in the negative x direction
D.Graph 2 corresponds to a particle moving in the positive x direction.
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Answer: B (Graph 1 corresponds to zero velocity)
Explanation
Velocity is the slope of a displacement–time graph. Graph 1 is horizontal, so its velocity is zero; graph 2 slopes down (negative direction) and graph 3 is steepest and positive.
The figures above show three different ways of hanging a heavy picture from a hook. The tension in the string would be
A.greatest in X
B.greatest in Y
C.greatest in Z
D.same in each one.
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Answer: B (greatest in Y)
Explanation
Each string's vertical pulls must add up to the weight. The flatter the strings, the smaller their vertical share, so the tension must be larger. The strings in Y are the flattest.
A force, 10 N, drags a mass 10 kg on a horizontal table with an acceleration of 0.2 m s−2. If the acceleration due to gravity is 10 m s−2, the coefficient of friction between the moving mass and the table is
A.0.02
B.0.08
C.0.20
D.0.80.
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Answer: B (0.08)
Explanation
Net force = 10 × 0.2 = 2 N, so friction = 10 − 2 = 8 N. μ = 8/(10 × 10) = 0.08.
Which of the following graphs correctly describes the variation of the mechanical advantage with load for a simple machine whose velocity ratio is 3?
A.A
B.B
C.C
D.D
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Answer: B (B)
Explanation
As the load grows, friction and the weight of moving parts matter less, so the MA rises quickly at first and then levels off below the velocity ratio, as in B.
When one arm of a U-tube manometer is connected to a gas supply, the levels of mercury in the two arms of the U-tube are as shown in the diagram above. If the atmospheric pressure is 76.0 cm Hg, the gas pressure is
A.62.6 cm Hg
B.72.5 cm Hg
C.79.5 cm Hg
D.85.9 cm Hg
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Answer: D (85.9 cm Hg)
Explanation
The mercury in the open arm stands 13.4 − 3.5 = 9.9 cm higher, so the gas pressure is 76.0 + 9.9 = 85.9 cm Hg.
A tap supplies water at 25°C while another supplies water at 75°C. If a man wishes to bathe with water at 40°C, the ratio of the mass of cold water to the mass of hot water required is
A.1 : 3
B.15 : 8
C.7 : 3
D.3 : 1
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Answer: C (7 : 3)
Explanation
Heat lost by hot = heat gained by cold: mh × 35 = mc × 15, so mc : mh = 35 : 15 = 7 : 3.
When heat is applied to one end of a metal rod, the molecules at the other end soon begin to vibrate with greater amplitude than before because heat has been transferred by
A.radiation
B.convection
C.conduction
D.evaporation.
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Answer: C (conduction)
Explanation
In a solid, heat passes from molecule to molecule by their vibrations (and by free electrons in metals): conduction.
A piano wire 0.5 m long has a total mass of 0.01 kg and is stretched with a tension of 800 N. Calculate the frequency of the wire when it sounds its fundamental note.
A.200 Hz
B.100 Hz
C.4 Hz
D.2 Hz
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Answer: A (200 Hz)
Explanation
Mass per unit length μ = 0.01/0.5 = 0.02 kg m−1. f = (1/2L)√(T/μ) = (1/1) × √(800/0.02) = 200 Hz.
The speed of sound in air at sea-level is 340 m s−1 while that of light is 300 000 km s−1. How far (to the nearest metre) from the centre of a thunderstorm is an observer who hears a thunder 2 s after a lightening flash?
A.170 m
B.340 m
C.600 m
D.680 m
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Answer: D (680 m)
Explanation
Light arrives almost instantly, so the 2 s delay is the sound's travel time: 340 × 2 = 680 m.
Two strings of the same length and under the same tension give notes of frequencies in the ratio 4 : 1. The masses of the strings are in the corresponding ratio of
A.2 : 1
B.1 : 2
C.1 : 4
D.1 : 16.
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Answer: D (1 : 16.)
Explanation
f ∝ 1/√m at fixed length and tension, so m ∝ 1/f². A frequency ratio 4 : 1 gives a mass ratio 1 : 16.
In the figure above, what is the angle of reflection of the ray of light at mirror M2?
A.90°
B.60°
C.45°
D.30°
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Answer: B (60°)
Explanation
The ray strikes M1 at 30° to its normal and leaves at 30° below the horizontal. M2 is horizontal, so the ray meets it at 60° to its (vertical) normal and reflects at 60°.
Which of the following phenomena explain the formation of a mirage? I. Reflection II. Refraction III. Diffraction
A.I and II only
B.II and III only
C.I and III only
D.I, II and III.
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Answer: A (I and II only)
Explanation
Light from the sky is refracted through layers of air of different temperature and finally totally reflected near the hot ground, so refraction and (total internal) reflection cause a mirage.
E, F and G are yellow, red and cyan transparent light filters respectively. The colour of a white opaque object when viewed through the arrangement of the filters above is
A.yellow
B.red
C.black
D.blue
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Answer: C (black)
Explanation
The yellow filter passes red and green, the red filter then passes only red, and the cyan filter (green + blue) absorbs red. No light gets through, so the object looks black.
The wire X in the figure above is at right angles to the plane of the paper and carries a current into the paper. At which of the points labelled 1 - 4 will the magnetic flux density due to this current be in the same direction as that of the horizontal component of the earth's magnetic field?
A.1
B.2
C.3
D.4
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Answer: C (3)
Explanation
A current into the paper makes clockwise field lines. Going clockwise, the field at point 3 (to the left of the wire) points up the page, towards magnetic north, like the earth's horizontal field.
In the circuit diagram above, the ammeter reads a current of 3 amps, when R is 5 ohms and reads 6 amps when R is 2 ohms. The value of the unknown resistance X is
A.1
B.2
C.3
D.4
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Answer: A (1)
Explanation
E = 3(5 + X) = 6(2 + X). So 15 + 3X = 12 + 6X, giving X = 1 Ω.
Which of the following instruments consumes the highest current? (A. Electric iron: 250 V, 1 kW; B. Television set: 220 V, 110 W; C. Torchlight: 6 V, 30 W; D. Immersion heater: 110 V, 500 W)
A.Electric iron
B.Television set
C.Torchlight
D.Immersion heater
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Answer: C (Torchlight)
Explanation
I = P/V: iron 4 A, television 0.5 A, torch 5 A, heater 4.55 A. The torchlight draws the most.
Which of the following ammeters may be used to measure alternating currents? I. Moving-coil ammeter II. Moving-iron ammeter III. Hot-wire ammeter
A.I and II only
B.II and III only
C.I and III only
D.I, II and III.
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Answer: B (II and III only)
Explanation
Moving-iron and hot-wire meters respond the same way whichever way the current flows. A moving-coil meter's pointer reverses with the current, so it only measures d.c.
In a certain fusion reaction, a deuteron (21H) interacts with a triton (31H) and produces an α-particle (42He) and a second product. The second product is
A.a proton
B.an electron
C.a neutron
D.a gamma ray
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Answer: C (a neutron)
Explanation
Mass numbers: 2 + 3 = 4 + 1, and charges: 1 + 1 = 2 + 0. The missing particle has mass number 1 and charge 0: a neutron.