Question 12
FrictionA force, 10 N, drags a mass 10 kg on a horizontal table with an acceleration of 0.2 m s−2. If the acceleration due to gravity is 10 m s−2, the coefficient of friction between the moving mass and the table is
- A.0.02
- B.0.08
- C.0.20
- D.0.80.
Show the answer and explanation
Answer: B (0.08)
Explanation
Net force = 10 × 0.2 = 2 N, so friction = 10 − 2 = 8 N. μ = 8/(10 × 10) = 0.08.