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JAMB Mathematics 1984 Question 46

Question 46

Circle Theorems

In the figure above, O is the centre of circle PQRS and PS∥RT. If PRT = 135°, then PSO is

Diagram for this question
  1. A.67½°
  2. B.45°
  3. C.90°
  4. D.33¾°
  5. E.22½°.
Show the answer and explanation

Answer: B (45°)

Explanation

PS ∥ RT, so <SPR = 180° − 135° = 45° (co-interior angles). OP = OS, so <PSO = <SPO = 45°.