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Question 1 Separation of Mixtures Sodium chloride can be obtained from brine through
A. decantation B. titration C. evaporation D. distillation Show the answer and explanation Answer: C (evaporation )
Explanation Brine is salt dissolved in water; evaporating the water leaves the solid sodium chloride behind.
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Question 2 Mole Concept and Stoichiometry NH4 NO2(s) → (heat) N2(g) + 2H2 O(l) In the above reaction, calculate the volume of N2(g) that would be produced at S.T.P from 3.20g of NH4 NO2(s) [N=14, H=1, O = 16] Molar volume at s.t.p. = 22.4dm3
A. 2.24cm3 B. 2.24dm3 C. 1.12dm3 D. 1.12cm3 Show the answer and explanation Answer: C (1.12dm3 )
Explanation Molar mass of NH4 NO2 = 64 g, so 3.20 g = 0.05 mol, giving 0.05 mol of N2 . Volume = 0.05 × 22.4 = 1.12 dm3 .
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Question 5 Electrolysis In the above electrolyte cell, which species migrate to the anode?
A. K+ and SO4 2− B. SO4 2− and OH− C. H3 O+ and K+ D. OH− and H3 O+ Show the answer and explanation Answer: B (SO4 2− and OH− )
Explanation The anode is positive, so the negative ions in K2 SO4 (aq), SO4 2− and OH− , move to it.
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Question 6 Air What is the approximate volume of air containing 10cm3 of oxygen?
A. 25cm3 B. 20cm3 C. 100cm3 D. 50cm3 Show the answer and explanation Answer: D (50cm3 )
Explanation Air is about one-fifth (20%) oxygen, so 10 cm3 of oxygen is in about 5 × 10 = 50 cm3 of air.
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Question 11 Rates of Reaction The above diagram illustrates the energy profile of the catalyst and uncatalysed reaction of A(g) + B(g) → AB(g) . Calculate the activation energies in KJ of the catalysed and uncatalysed unreverse reactions.
A. 500, 300 B. 300, 500 C. −500, −300 D. −300, −500 Show the answer and explanation Answer: B (300, 500 )
Explanation Activation energy = peak energy − reactant energy. Catalysed: 400 − 100 = 300 kJ; uncatalysed: 600 − 100 = 500 kJ.
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Question 16 Solubility and Solutions A property found in a colloidal dispersion which is absent in a true solution is
A. homogeneity B. the Tyndale effect C. surface polarity D. Osmotic pressure Show the answer and explanation Answer: B (the Tyndale effect )
Explanation Colloid particles are big enough to scatter a beam of light (the Tyndall effect); a true solution does not.
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Question 17 Environmental Pollution A gas when dissolved in water vapour, produced acid rain during rainfall. The gas is
A. carbon (II) oxide B. oxygen C. sulphur (IV) oxide D. nitrogen Show the answer and explanation Answer: C (sulphur (IV) oxide )
Explanation SO2 dissolves in rainwater to form trioxosulphate(IV) acid, a major cause of acid rain.
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Question 18 Chemical Bonding The carbon atoms in H2 C=CH2 are
A. Sp hybridized B. Sp3 hybridized C. not hybridized D. Sp2 hybridized Show the answer and explanation Answer: D (Sp2 hybridized )
Explanation Each carbon in ethene forms three σ bonds and one π bond, so it uses sp2 hybrid orbitals.
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Question 20 Electrolysis Half cell reaction — Eθ Cu2+ (aq) + 2e− → Cu(s) +0.34V Zn2+ (aq) + 2e− → Zn(s) −0.76V Fe2+ (aq) + 2e− → Fe(s) −0.44V Ba2+ (aq) + 2e− → Ba(s) −2.90V From the above data, it can be deduced that the most powerful reducing agent is?
A. Fe B. Cu C. Zn D. Ba Show the answer and explanation Answer: D (Ba )
Explanation The most negative electrode potential (−2.90 V for Ba) means the metal loses electrons most easily, so barium is the strongest reducing agent.
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Question 24 Alkanoic Acids and Esters CH3 CH2 OH + CH3 COOH → (Conc H2 SO4 ) Y + Z Y and Z in the reaction above represent
A. CH3 CH2 COCH3 and H2 O B. CH3 COCH3 and H2 O C. CH3 CH2 CHO and CH4 D. CH3 COOCH2 CH3 and H2 O Show the answer and explanation Answer: D (CH3 COOCH2 CH3 and H2 O )
Explanation An alkanol and an alkanoic acid react (esterification) to give an ester, ethyl ethanoate, and water.
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Question 30 Redox Reactions Write out the increasing oxidation number of the transition metal ion for the compounds K2 Cr2 O7 , V2 O5 and KMnO4 .
A. K2 Cr2 O7 < KMnO4 < V2 O5 B. V2 O5 < K2 Cr2 O7 < KMnO4 C. KMnO4 < K2 Cr2 O7 < V2 O5 D. KMnO4 < V2 O5 < K2 Cr2 O7 Show the answer and explanation Answer: B (V2 O5 < K2 Cr2 O7 < KMnO4 )
Explanation V in V2 O5 is +5, Cr in K2 Cr2 O7 is +6 and Mn in KMnO4 is +7.
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Question 32 Periodic Table Given the distance between the nuclei of chlorine atoms in a chlorine molecule as 0.194mm, calculate its atomic radius.
A. 0.194mm B. 0.097mm C. 2.388mm D. 0.388mm Show the answer and explanation Answer: B (0.097mm )
Explanation The nucleus-to-nucleus distance is two atomic radii, so r = 0.194/2 = 0.097.
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Question 35 Energy Changes Which of these equations shows that a reaction is in equilibrium?
A. ΔG = ΔH − TΔS B. ΔG < O C. ΔG = O D. ΔG > O Show the answer and explanation Answer: C (ΔG = O )
Explanation At equilibrium there is no driving force in either direction, so the free energy change ΔG is zero.
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Question 36 Alkanoic Acids and Esters The formula CH2 O for ethanoic acid represents its
A. general formula B. molecular formula C. structural formula D. empirical formula Show the answer and explanation Answer: D (empirical formula )
Explanation Ethanoic acid is C2 H4 O2 = (CH2 O)2 ; CH2 O is the simplest whole-number ratio, the empirical formula.
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Question 38 Halogens How is Cl2(g) prepared in the laboratory? by
A. adding concentrated tetraoxosulphate (VI) acid to solid sodium chloride B. adding concentrated hydro chloric acid to solid manganese (IV) oxide C. dropping concentrated hydrochloric acid unto potassium tetraoxomanganate (VI) crystals and heating the mixture D. dropping concentrated hydrochloric acid unto potassium tetraoxomanganate(VI) crystals Show the answer and explanation Answer: D (dropping concentrated hydrochloric acid unto potassium tetraoxomanganate(VI) crystals )
Explanation Concentrated HCl is oxidised to chlorine by potassium permanganate crystals without heating (option A gives HCl gas, not chlorine).
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Question 39 Introduction to Organic Chemistry Which of the following is an isomer of C5 H12 ?
A. 2-methylbutane B. butane C. 2-ethylbutane D. 2-methylpropane Show the answer and explanation Answer: A (2-methylbutane )
Explanation 2-methylbutane has five carbons and twelve hydrogens, the same formula as pentane but a branched chain.
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Question 40 Gas Laws According to Charles's law, at what temperature does the volume of gas becomes zero?
A. −100°C B. 0°C C. 373°C D. −273°C Show the answer and explanation Answer: D (−273°C )
Explanation Extending the volume-temperature line to zero volume gives absolute zero, −273 °C (0 K).
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