Question 30
Redox ReactionsWrite out the increasing oxidation number of the transition metal ion for the compounds K2Cr2O7, V2O5 and KMnO4.
- A.K2Cr2O7 < KMnO4 < V2O5
- B.V2O5 < K2Cr2O7 < KMnO4
- C.KMnO4 < K2Cr2O7 < V2O5
- D.KMnO4 < V2O5 < K2Cr2O7
Show the answer and explanation
Answer: B (V2O5 < K2Cr2O7 < KMnO4)
Explanation
V in V2O5 is +5, Cr in K2Cr2O7 is +6 and Mn in KMnO4 is +7.