JAMB Chemistry 2023 Question 2

Question 2

Mole Concept and Stoichiometry

NH₄NO_2(s) → (heat) N_2(g) + 2H₂O_(l)
In the above reaction, calculate the volume of N_2(g) that would be produced at S.T.P from 3.20g of NH₄NO_2(s) [N=14, H=1, O = 16] Molar volume at s.t.p. = 22.4dm³

A.2.24cm³
B.2.24dm³
C.1.12dm³
D.1.12cm³

Show the answer and explanation

Answer: C (1.12dm³)

Explanation

Molar mass of NH₄NO₂ = 64 g, so 3.20 g = 0.05 mol, giving 0.05 mol of N₂. Volume = 0.05 × 22.4 = 1.12 dm³.