Question 20
ElectrolysisHalf cell reaction — Eθ
Cu2+(aq) + 2e− → Cu(s) +0.34V
Zn2+(aq) + 2e− → Zn(s) −0.76V
Fe2+(aq) + 2e− → Fe(s) −0.44V
Ba2+(aq) + 2e− → Ba(s) −2.90V
From the above data, it can be deduced that the most powerful reducing agent is?
- A.Fe
- B.Cu
- C.Zn
- D.Ba
Show the answer and explanation
Answer: D (Ba)
Explanation
The most negative electrode potential (−2.90 V for Ba) means the metal loses electrons most easily, so barium is the strongest reducing agent.