JAMB Chemistry 2008 past questions and answers

46 questions. Try each one, then open the answer to check yourself and read the explanation.

Question 1

Separation of Mixtures

Chlorophyll obtained from given leaves of plant can be shown to be composed of more than one coloured component by the technique of

  1. A.crystallization
  2. B.hydrolysis
  3. C.chromatography
  4. D.sublimation.
Show the answer and explanation

Answer: C (chromatography)

Explanation

Chromatography separates the pigments in a leaf extract because each travels at a different speed through the paper or column, showing several coloured bands.

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Question 2

Solubility and Solutions

In countries where the temperature falls below 273K, salt is always sprinkled on the icy roads in order to

  1. A.lower the melting point of the ice
  2. B.increase the density of the ice
  3. C.make the ice impure
  4. D.raise the melting point of the ice.
Show the answer and explanation

Answer: A (lower the melting point of the ice)

Explanation

Dissolved salt lowers the freezing (melting) point of water, so the ice melts even below 0°C (273 K).

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Question 3

Mole Concept and Stoichiometry

2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
From the equation above, calculate the mass of sodium hydroxide produced by 2.3g of sodium. [H = 1, O = 16, Na = 23]

  1. A.0.40g
  2. B.0.80g
  3. C.4.00g
  4. D.8.00g.
Show the answer and explanation

Answer: C (4.00g)

Explanation

2.3 g Na = 0.1 mol, which gives 0.1 mol NaOH (1 : 1). Mass = 0.1 × 40 = 4.00 g.

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Question 4

Mole Concept and Stoichiometry

16.8g of sodium hydrogen trioxocarbonate (IV) is completely decomposed by heat. Calculate the volume of carbon (IV) oxide given off at s.t.p [Na = 23, C = 12, O = 16, H = 1, Molar volume of a gas at s.t.p. = 22.4 dm3]

  1. A.22.40 dm3
  2. B.11.20 dm3
  3. C.2.24 dm3
  4. D.1.12 dm3.
Show the answer and explanation

Answer: C (2.24 dm3)

Explanation

2NaHCO3 → Na2CO3 + H2O + CO2. 16.8 g ÷ 84 = 0.2 mol NaHCO3, giving 0.1 mol CO2 = 0.1 × 22.4 = 2.24 dm3.

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Question 5

Gas Laws

300 cm3 of a gas has a pressure of 800 mm Hg. If the pressure is reduced to 650 mm Hg, find its volume.

  1. A.243.75 cm3
  2. B.369.23 cm3
  3. C.738.46 cm3
  4. D.1733.36 cm3.
Show the answer and explanation

Answer: B (369.23 cm3)

Explanation

Boyle's law: V2 = P1V1/P2 = 800 × 300/650 = 369.23 cm3.

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Question 6

Kinetic Theory and States of Matter

Diffusion is slowest in solid particles than in particles of liquids and gases because

  1. A.solid particles have more kinetic energy than the particles of liquids and gases
  2. B.solid particles have less kinetic energy than the particles of liquids and gases
  3. C.solid particles have less restrictions in their movement than liquid and gas particles
  4. D.the particles in solids are far apart and the cohesive forces between them are negligible.
Show the answer and explanation

Answer: B (solid particles have less kinetic energy than the particles of liquids and gases)

Explanation

Particles in a solid have the least kinetic energy and only vibrate about fixed positions, so they mix (diffuse) most slowly.

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Question 7

Atomic Structure

The experiment that showed that atoms have tiny positively charged nucleus was first carried out by

  1. A.Moseley
  2. B.Rutherford
  3. C.Millikan
  4. D.Dalton.
Show the answer and explanation

Answer: B (Rutherford)

Explanation

Rutherford's alpha-particle scattering experiment showed that an atom's positive charge and most of its mass are in a tiny nucleus.

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Question 8

Atomic Structure

The atom of an element X is represented as YZX. The basic chemical properties of X depend on the value of

  1. A.Y
  2. B.Z
  3. C.Y − Z
  4. D.Z − Y
Show the answer and explanation

Answer: B (Z)

Explanation

Z is the atomic number, which fixes the number of electrons and so how the atom reacts. Y (mass number) and Y − Z (neutrons) do not affect chemical properties.

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Question 9

Atomic Structure

The diagram above represents the electron sub-level for

Diagram for this question
  1. A.carbon
  2. B.nitrogen
  3. C.oxygen
  4. D.fluorine.
Show the answer and explanation

Answer: C (oxygen)

Explanation

The boxes show 1s2 2s2 2p4 (one paired and two single electrons in 2p): 8 electrons, which is oxygen.

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Question 10

Periodic Table

In the periodic table, electrical and thermal conductivities are properties of elements that

  1. A.decrease across the period and increase down the group
  2. B.increase across the period and decrease down the group
  3. C.decrease across the period and down the group
  4. D.increase across the period and down the group.
Show the answer and explanation

Answer: A (decrease across the period and increase down the group)

Explanation

Conductivity follows metallic character, which falls across a period (metals to non-metals) and rises down a group.

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Question 11

Radioactivity

2311Na + 10n → 2411Na
The reaction above is an example of

  1. A.nuclear fission
  2. B.nuclear fusion
  3. C.artificial transmutation
  4. D.beta decay.
Show the answer and explanation

Answer: C (artificial transmutation)

Explanation

A nucleus is bombarded with a particle (a neutron) to make a new isotope. Changing a nucleus artificially this way is artificial transmutation.

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Question 12

Air

Air boiled out of water as steam is richer in

  1. A.nitrogen and oxygen
  2. B.carbon (IV) oxide and oxygen
  3. C.noble gases and carbon (IV) oxide
  4. D.oxygen and noble gases.
Show the answer and explanation

Answer: B (carbon (IV) oxide and oxygen)

Explanation

CO2 and O2 are more soluble in water than nitrogen, so air dissolved in water (and boiled out of it) contains a higher share of them than ordinary air.

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Question 13

Water

In the course of purifying water for town supply, the water is passed through large settling tanks containing sodium aluminate (III) to remove

  1. A.large particles
  2. B.germs
  3. C.fine particles
  4. D.odour.
Show the answer and explanation

Answer: C (fine particles)

Explanation

Sodium aluminate forms a sticky aluminium hydroxide floc that traps tiny suspended particles so they settle out (coagulation). Germs are killed later by chlorination.

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Question 14

Water

When a few drops of water is added to a blue anhydrous cobalt (II) chloride, the colour changes to

  1. A.white
  2. B.pink
  3. C.red
  4. D.blue.
Show the answer and explanation

Answer: B (pink)

Explanation

Anhydrous cobalt(II) chloride is blue and turns pink when it takes up water; this is a test for water.

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Question 16

Solubility and Solutions

117.0g of sodium chloride was dissolved in 1.0dm3 of distilled water at 25°C. Determine the solubility in mol dm−3 of sodium chloride at that temperature. [Na = 23, Cl = 35.5]

  1. A.1.0
  2. B.2.0
  3. C.3.0
  4. D.4.0
Show the answer and explanation

Answer: B (2.0)

Explanation

Molar mass of NaCl = 58.5 g. 117.0 ÷ 58.5 = 2.0 mol in 1.0 dm3, so 2.0 mol dm−3.

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Question 17

Environmental Pollution

The uncovered raw food that is sold along major roads is likely to contain some amounts of

  1. A.Pb
  2. B.Cu
  3. C.Ag
  4. D.Na
Show the answer and explanation

Answer: A (Pb)

Explanation

Vehicle exhaust (especially from leaded petrol) releases lead compounds that settle on food sold by the roadside.

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Question 18

Acids, Bases and Salts

What is the pH of a 0.001 mol dm−3 solution of sodium hydroxide?

  1. A.14
  2. B.13
  3. C.12
  4. D.11
Show the answer and explanation

Answer: D (11)

Explanation

[OH−] = 10−3, so pOH = 3 and pH = 14 − 3 = 11.

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Question 19

Acids, Bases and Salts

The basicity of CH3COOH is

  1. A.1
  2. B.2
  3. C.3
  4. D.4
Show the answer and explanation

Answer: A (1)

Explanation

Only the hydrogen in the −COOH group can ionise, so ethanoic acid has one replaceable hydrogen: basicity 1.

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Question 20

Volumetric Analysis

0.05 mol dm−3 HCl is neutralized by 25cm3 NaOH. If the volume of acid used is 32.00cm3, what is the concentration of the base?

  1. A.0.016 mol dm−3
  2. B.0.032 mol dm−3
  3. C.0.0… mol dm−3
  4. D.0.064 mol dm−3.
Show the answer and explanation

Answer: D (0.064 mol dm−3.)

Explanation

HCl and NaOH react 1 : 1, so CB = 0.05 × 32/25 = 0.064 mol dm−3.

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Question 21

Acids, Bases and Salts

Insoluble salts can be prepared by

  1. A.titrating an alkali against an appropriate acid
  2. B.reacting an acid with trioxocarbonate (IV) salt
  3. C.direct combination of the elements which make up the salt.
  4. D.mixing two soluble compounds containing the metallic radical and the acidic radical.
Show the answer and explanation

Answer: D (mixing two soluble compounds containing the metallic radical and the acidic radical.)

Explanation

Insoluble salts are made by double decomposition (precipitation): mixing two soluble salts, e.g. AgNO3 + NaCl → AgCl↓ + NaNO3.

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Question 22

Redox Reactions

The oxidation state of carbon in HCOOH is

  1. A.−1
  2. B.+2
  3. C.+3
  4. D.0
Show the answer and explanation

Answer: B (+2)

Explanation

2 H at +1 and 2 O at −2: 2 + x − 4 = 0, so carbon is +2.

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Question 23

Chemical Formulae and Equations

What is the IUPAC nomenclature of the compound NaClO?

  1. A.Sodium oxochlorate(I)
  2. B.Sodium chloro(I) oxide
  3. C.Sodium monooxochlorate(II)
  4. D.sodium chloro(I) monoxide
Show the answer and explanation

Answer: A (Sodium oxochlorate(I))

Explanation

ClO− has one oxygen (oxo) and chlorine at +1, so NaClO is sodium oxochlorate(I).

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Question 24

Electrolysis

In recharging a lead-acid accumulator, the reaction at the cathode can be represented as

  1. A.Pb2+(aq) + SO4(aq)2− → PbSO4(s)
  2. B.Pb2+(aq) + 2e− → Pb(s)
  3. C.Pb2+(aq) + 2H2O(l) → PbO2(s) + 4H+(aq) + 4e−
  4. D.Pb(s) → Pb2+(aq) + 2e−
Show the answer and explanation

Answer: B (Pb2+(aq) + 2e− → Pb(s))

Explanation

During recharging the cathode is where reduction takes place: Pb2+ ions (from PbSO4) gain electrons and become lead metal again.

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Question 25

Electrolysis

If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current? [Zn = 65, Hg = 201]

  1. A.1.00g
  2. B.2.01g
  3. C.4.02 g
  4. D.8.04 g
Show the answer and explanation

Answer: B (2.01g)

Explanation

Both ions carry a 2+ charge, so equal charge discharges equal moles. 0.65/65 = 0.01 mol, so 0.01 × 201 = 2.01 g of mercury.

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Question 27

Energy Changes

Which of the following reactions is endothermic?

  1. A.C(s) + O2(g) → CO2(g)
  2. B.CaO(s) + H2O(l) → Ca(OH)2(s)
  3. C.C(s) + H2O(g) → CO(g) + H2(g)
  4. D.HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)
Show the answer and explanation

Answer: C (C(s) + H2O(g) → CO(g) + H2(g))

Explanation

Making water gas from steam and red-hot coke absorbs heat (the coke cools down). Burning carbon, slaking lime and neutralisation all release heat.

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Question 28

Rates of Reaction

A catalyst speeds up the rate of a chemical reaction by

  1. A.taking part in the reaction
  2. B.increasing the activation energy of the reaction
  3. C.lowering the activation energy of the reaction
  4. D.increasing the heat content.
Show the answer and explanation

Answer: C (lowering the activation energy of the reaction)

Explanation

A catalyst provides an alternative pathway with a lower activation energy, so more collisions are successful.

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Question 29

Rates of Reaction

The rate of a reaction usually decreases with a decrease in the concentration of reactants because

  1. A.kinetic energy decreases
  2. B.temperature increases
  3. C.speed increases
  4. D.reactants collision decreases.
Show the answer and explanation

Answer: D (reactants collision decreases.)

Explanation

With fewer reactant particles in a given volume, they collide less often, so the reaction slows down.

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Question 30

Chemical Equilibrium

N2O4(g) ⇌ 2NO2(g)
In the reaction above, the equilibrium constant is

  1. A.[NO2]/[N2O4]
  2. B.[2NO2]/[N2O4]
  3. C.[N2O4]/[NO2]2
  4. D.[NO2]2/[N2O4]
Show the answer and explanation

Answer: D ([NO2]2/[N2O4])

Explanation

K = [products]/[reactants], each raised to the power of its coefficient: [NO2]2/[N2O4].

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Question 31

Metals and their Compounds

The substance that is used in the steel industry for the removal of carbon, sulphur and phosphorus impurities from pig iron is

  1. A.oxygen
  2. B.chlorine
  3. C.nitrogen
  4. D.hydrogen
Show the answer and explanation

Answer: A (oxygen)

Explanation

In steel making, oxygen is blown through molten pig iron to oxidise carbon, sulphur and phosphorus into oxides that escape as gas or go into the slag.

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Question 32

Nitrogen and its Compounds

Which of the following compounds of trioxonitrate(V) will decompose to give dinitrogen(I) oxide and water when heated?

  1. A.NaNO3
  2. B.Zn(NO3)2
  3. C.Cu(NO3)2
  4. D.NH4NO3
Show the answer and explanation

Answer: D (NH4NO3)

Explanation

Ammonium trioxonitrate(V) decomposes on gentle heating: NH4NO3 → N2O + 2H2O.

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Question 33

Halogens

Use the diagram to answer questions 33 and 34.
The gas that can be used to demonstrate the experiment is

Diagram for this question
  1. A.hydrogen chloride
  2. B.hydrogen sulphide
  3. C.nitrogen(II) oxide
  4. D.dinitrogen(I) oxide.
Show the answer and explanation

Answer: A (hydrogen chloride)

Explanation

The fountain experiment needs a gas that is extremely soluble in water. Hydrogen chloride dissolves so fast that water rushes up into the flask.

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Question 34

Halogens

Use the diagram to answer questions 33 and 34.
The colour of the fountain water is

Diagram for this question
  1. A.blue
  2. B.orange
  3. C.red
  4. D.yellow.
Show the answer and explanation

Answer: C (red)

Explanation

Hydrogen chloride dissolves to form hydrochloric acid, which turns the blue litmus in the water red.

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Question 35

Qualitative Analysis

When a solution of ammonium trioxocarbonate(IV) is added to a solution of an unknown salt, a white precipitate which is soluble in dilute hydrochloric acid but insoluble in ethanoic acid is formed. This indicates the presence of

  1. A.Ca2+
  2. B.Na+
  3. C.Zn2+
  4. D.K+
Show the answer and explanation

Answer: A (Ca2+)

Explanation

Ammonium carbonate precipitates calcium as white CaCO3, which dissolves in dilute HCl. Na+ and K+ carbonates are soluble, and the zinc precipitate redissolves in excess ammonium salt.

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Question 36

Metals and their Compounds

Lead is used for making bullets and lead shots because of its

  1. A.resistance to corrosion
  2. B.low melting point
  3. C.high density
  4. D.flexibility.
Show the answer and explanation

Answer: C (high density)

Explanation

Lead is very dense, so a small bullet or shot is heavy and carries a lot of momentum.

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Question 38

Metals and their Compounds

The most common ores of iron include

  1. A.haematite, malachite and limonite
  2. B.chalcocite, calamine and bornite
  3. C.magnetite, haematite and limonite
  4. D.malachite, chalcocite and bornite
Show the answer and explanation

Answer: C (magnetite, haematite and limonite)

Explanation

Magnetite (Fe3O4), haematite (Fe2O3) and limonite (hydrated iron oxide) are iron ores. Malachite, chalcocite and bornite are copper ores; calamine is a zinc ore.

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Question 39

Introduction to Organic Chemistry

The type of isomerism shown by cis- and trans- isomers is

  1. A.optical isomerism
  2. B.positional isomerism
  3. C.functional isomerism
  4. D.geometrical isomerism.
Show the answer and explanation

Answer: D (geometrical isomerism.)

Explanation

Cis and trans isomers differ only in the arrangement of groups in space around a C=C bond; this is geometrical isomerism.

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Question 40

Alkanals and Alkanones

If the silver mirror test is positive, it indicates the presence of an

  1. A.alkyne
  2. B.alkanol
  3. C.alkanone
  4. D.alkanal.
Show the answer and explanation

Answer: D (alkanal.)

Explanation

Alkanals (aldehydes) reduce Tollens' reagent to metallic silver, forming a mirror; alkanones do not.

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Question 41

Introduction to Organic Chemistry

The IUPAC nomenclature for the structure above is

Diagram for this question
  1. A.2, 3 − dichloro − 4, 4, 5 − trimethyl pent - 2- ene
  2. B.4, 5 − dichloro − 2, 3 − dimethyl hex − 2 − ene
  3. C.2, 3 − dichloro − 4, 4 − dimethyl hex − 2 − ene
  4. D.2, 3 dichloro − 2, 2 − dimethyl hex − 2 − ene
Show the answer and explanation

Answer: C (2, 3 − dichloro − 4, 4 − dimethyl hex − 2 − ene)

Explanation

The structure is CH3CH2C(CH3)2C(Cl)=C(Cl)CH3. The longest chain has 6 carbons; numbering from the right puts the double bond at C2, both Cl on C2 and C3 and two methyls on C4.

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Question 42

Carbohydrates, Proteins and Amines

If glucose is heated with concentrated tetraoxosulphate(VI) acid, it will be dehydrated to

  1. A.carbon
  2. B.carbon(IV) oxide
  3. C.ethene
  4. D.ethanol.
Show the answer and explanation

Answer: A (carbon)

Explanation

Concentrated H2SO4 removes the elements of water from glucose (C6H12O6 → 6C + 6H2O), leaving black carbon.

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Question 43

Chemical Formulae and Equations

A hydrocarbon X with a molar mass of 26 consists of 92.3% carbon. What is its molecular formula?

  1. A.C2H2
  2. B.C3H3
  3. C.C4H4
  4. D.C5H5.
Show the answer and explanation

Answer: A (C2H2)

Explanation

C : H = 92.3/12 : 7.7/1 = 7.7 : 7.7 = 1 : 1, so the empirical formula is CH (13). 26 ÷ 13 = 2, giving C2H2.

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Question 45

Carbohydrates, Proteins and Amines

Reduction of nitroalkanes, nitrites and amides is a route for the preparation of

  1. A.amines
  2. B.alkenes
  3. C.polymers
  4. D.detergents
Show the answer and explanation

Answer: A (amines)

Explanation

Reducing nitro compounds, nitriles or amides adds hydrogen to the nitrogen-containing group and produces amines (−NH2).

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Question 46

Alkanols

CH3 − C(OH)(CH3) − CH2 − CH3
The major product of the dehydration of the above compound is

  1. A.CH3 − C(=CH2) − CH2 − CH3
  2. B.CH3 − CH(CH3) − CH = CH2
  3. C.CH3 − C(CH3) = CH − CH3
  4. D.CH3 − CH(CH3) − CH2 − CH3
Show the answer and explanation

Answer: C (CH3 − C(CH3) = CH − CH3)

Explanation

Removing water from 2-methylbutan-2-ol mostly forms the more substituted alkene (Saytzeff's rule): 2-methylbut-2-ene, CH3C(CH3)=CHCH3.

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Question 47

Alkanals and Alkanones

Reduction of alkanonoes with LiAlH4 produces

  1. A.primary alkanols
  2. B.secondary alkanols
  3. C.tertiary alkanols
  4. D.polyhydric alkanols
Show the answer and explanation

Answer: B (secondary alkanols)

Explanation

In an alkanone the C=O carbon is joined to two carbon groups; adding hydrogen to it gives a secondary alkanol, e.g. propanone → propan-2-ol.

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Question 48

Hydrocarbons

The product obtained when a mixture of benzene vapour and hydrogen are passed over a nickel catalyst at 180°C is

  1. A.cyclohexane
  2. B.cyclopentane
  3. C.n-hexane
  4. D.n-pentane.
Show the answer and explanation

Answer: A (cyclohexane)

Explanation

Benzene adds three molecules of hydrogen across its ring: C6H6 + 3H2 → C6H12 (cyclohexane). The ring stays intact.

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Question 49

Polymers

Polyvinyl chloride is used in the production of

  1. A.glass
  2. B.alloy
  3. C.pipes
  4. D.ceramics.
Show the answer and explanation

Answer: C (pipes)

Explanation

PVC is a tough, water-resistant plastic, widely used for water and drainage pipes.

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Question 50

Fats, Oils and Soaps

Detergents are manufactured with straight hydrocarbon chains so as to make them

  1. A.soluble
  2. B.biodegradable
  3. C.cheaper
  4. D.foamy.
Show the answer and explanation

Answer: B (biodegradable)

Explanation

Bacteria can easily break down unbranched hydrocarbon chains, so straight-chain detergents are biodegradable and do not build up as foam in rivers.

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