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JAMB Chemistry 2008 Question 25

Question 25

Electrolysis

If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current? [Zn = 65, Hg = 201]

  1. A.1.00g
  2. B.2.01g
  3. C.4.02 g
  4. D.8.04 g
Show the answer and explanation

Answer: B (2.01g)

Explanation

Both ions carry a 2+ charge, so equal charge discharges equal moles. 0.65/65 = 0.01 mol, so 0.01 × 201 = 2.01 g of mercury.