48 questions. Try each one, then open the answer to check yourself and read the explanation.
Question 1
Separation of Mixtures
The dissolution of common salt in water is a physical change because
A.the salt can be obtained by crystallization
B.the salt can be recovered by the evaporation of the water
C.heat is not generated during mixing
D.the solution will not boil at 100°C
Show the answer and explanation
Answer: B (the salt can be recovered by the evaporation of the water)
Explanation
A physical change produces no new substance and is easily reversed. Evaporating the water gives back the same salt, so dissolving salt is a physical change.
A gaseous mixture of 80.0 g of oxygen and 56.0 g of nitrogen has a total pressure of 1.8 atm. The partial pressure of oxygen in the mixture is [O = 16, N = 14]
A.0.8 atm
B.1.0 atm
C.1.2 atm
D.1.4 atm
Show the answer and explanation
Answer: B (1.0 atm)
Explanation
Moles of O2 = 80/32 = 2.5 and moles of N2 = 56/28 = 2.0. Partial pressure of O2 = (2.5/4.5) × 1.8 = 1.0 atm.
For iodine crystals to sublime on heating, the molecules must acquire energy that is
A.less than the forces of attraction in the solid
B.equal to the forces of attraction in the solid
C.necessary to melt the solid
D.greater than the forces of attraction in both the solid and the liquid phases
Show the answer and explanation
Answer: D (greater than the forces of attraction in both the solid and the liquid phases)
Explanation
In sublimation the solid goes straight to vapour, skipping the liquid. The molecules need enough energy to break free of all the attractions that would hold them as a solid or a liquid.
The phenomenon whereby sodium trioxocarbonate (IV) decahydrate loses some of its water of crystallization on exposure to the atmosphere is known as
A.deliquescence
B.hygroscopy
C.effervescence
D.efflorescence
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Answer: D (efflorescence)
Explanation
Efflorescence is when a hydrated crystal gives off some of its water of crystallization to the air and becomes powdery, as washing soda (Na2CO3·10H2O) does.
A student prepares 0.5 M solution each of hydrochloric and ethanoic acids and then measured their pH. The result would show that the
A.pH values are equal
B.HCl solution has a higher pH
C.sum of the pH values is 14
D.ethanoic acid solution has a higher pH
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Answer: D (ethanoic acid solution has a higher pH)
Explanation
HCl is a strong acid and ionizes fully, while ethanoic acid is weak and ionizes only slightly. Ethanoic acid gives fewer H+ ions at the same concentration, so its pH is higher.
During the electrolysis of a salt of a metal M, a current of 0.5 A flows for 32 minutes 10 seconds and deposits 0.325 g of M. What is the charge of the metal ion? [M = 65, 1F = 96,500 C per mole of electron]
A.1
B.2
C.3
D.4
Show the answer and explanation
Answer: B (2)
Explanation
Q = 0.5 × 1930 s = 965 C = 0.01 mol of electrons. Moles of M = 0.325/65 = 0.005 mol, so each ion took 0.01/0.005 = 2 electrons: the charge is +2.
Which of the following reactions occurs at the anode during the electrolysis of a very dilute aqueous solution of sodium chloride?
A.OH− − e → OH
B.Cl− − e− → Cl
C.OH− + Cl− → HCl + O2−
D.Na+ − e− → Na/Hg amalgam (over Hg)
Show the answer and explanation
Answer: A (OH− − e → OH)
Explanation
In very dilute NaCl, OH− ions are discharged at the anode in preference to Cl− because they are lower in the discharge series. Each OH− loses an electron, and oxygen is given off.
Half-cell reactions and E° values: Cu2+(aq) + 2e− → Cu(s): +0.34 V Fe2+(aq) + 2e− → Fe(s): −0.44 V Ba2+(aq) + 2e− → Ba(s): −2.90 V Zn2+(aq) + 2e− → Zn(s): −0.76 V From the data above, it can be deduced that the most powerful reducing agent of the four metals is
A.Cu
B.Fe
C.Ba
D.Zn
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Answer: C (Ba)
Explanation
The metal with the most negative electrode potential loses electrons most readily, so it is the strongest reducing agent. Barium (−2.90 V) is the most negative.
The standard enthalpies of formation of CO2(g), H2O(g) and CO(g) in kJ mol−1 are −394, −242 and −110 respectively. What is the standard enthalpy change for the reaction CO(g) + H2O(g) → CO2(g) + H2(g)?
In the diagram above, curve X represents the energy profile for a homogeneous gaseous reaction. Which of the following conditions would produce curve Y for the same reaction?
A.Increase in temperature
B.Increase in the concentration of a reactant
C.Addition of a catalyst
D.Increase in pressure
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Answer: C (Addition of a catalyst)
Explanation
Curve Y has a lower energy hump between the same reactants and products, meaning a lower activation energy. Only a catalyst lowers the activation energy.
Which of these gases can be dried with concentrated H2SO4?
A.HBr
B.H2S
C.NH3
D.SO2
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Answer: D (SO2)
Explanation
A drying agent must not react with the gas. Concentrated H2SO4 oxidizes HBr and H2S and reacts with alkaline NH3, but it does not react with acidic SO2.
An experiment produces a gaseous mixture of carbon (IV) oxide and carbon (II) oxide. In order to obtain pure carbon (II) oxide, the gas mixture should be
A.passed over heated copper (II) oxide
B.bubbled through concentrated tetraoxosulphate (VI) acid
C.bubbled through sodium hydroxide solution
D.bubbled through water
Show the answer and explanation
Answer: C (bubbled through sodium hydroxide solution)
Explanation
Sodium hydroxide absorbs the acidic CO2 but not the neutral CO, so the gas that passes through is CO.