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JAMB Chemistry 1993 Question 21

Question 21

Mole Concept and Stoichiometry

4.0 g of sodium hydroxide in 250 cm3 of solution contains

  1. A.0.40 moles per dm3
  2. B.0.10 moles per dm3
  3. C.0.04 moles per dm3
  4. D.0.02 moles per dm3
Show the answer and explanation

Answer: A (0.40 moles per dm3)

Explanation

Moles of NaOH = 4.0/40 = 0.10 mol in 0.250 dm3. Concentration = 0.10/0.250 = 0.40 mol dm-3.