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JAMB Chemistry 1986 Question 4

Question 4

Mole Concept and Stoichiometry

The number of atoms of chlorine present in 5.85 g of NaCl is [Na = 23, Cl = 35.5] [Avogadro's Number = 6.02 × 1023].

  1. A.6.02 × 1022
  2. B.5.85 × 1023
  3. C.6.02 × 1023
  4. D.5.85 × 1024
Show the answer and explanation

Answer: A (6.02 × 1022)

Explanation

Molar mass of NaCl = 58.5 g, so 5.85 g is 0.1 mol, containing 0.1 mol of chlorine. 0.1 × 6.02 × 1023 = 6.02 × 1022 atoms.