Question 5
Mole Concept and StoichiometryHow much of magnesium is required to react with 250 cm3 of 0.5 M HCl? [Mg = 24]
- A.0.3 g
- B.1.5 g
- C.2.4 g
- D.3.0 g
Show the answer and explanation
Answer: B (1.5 g)
Explanation
Moles of HCl = 0.25 × 0.5 = 0.125 mol. Mg + 2HCl → MgCl2 + H2, so Mg = 0.0625 mol × 24 = 1.5 g.