Question 33
Circle TheoremsIn the diagram below; O is the centre of the circle and |BD| = |DC|. If ∠DCB = 35°, find ∠BAO.

- A.20°
- B.25°
- C.30°
- D.35°
- E.40°
Show the answer and explanation
Answer: A (20°)
Explanation
∠DBC = 35° (isosceles triangle), so the exterior angle ∠BDA = 35° + 35° = 70°. AD is a diameter, so ∠ABD = 90°. Then ∠BAO = 180° − 90° − 70° = 20°.