Question 39
Permutations and CombinationsIf nC3/nP2 = 1, find the value of n.
- A.8
- B.7
- C.6
- D.5
Show the answer and explanation
Answer: A (8)
Explanation
ⁿC₃ ÷ ⁿP₂ = [n!/(3!(n − 3)!)] × [(n − 2)!/n!] = (n − 2)/6 = 1, so n = 8.
If nC3/nP2 = 1, find the value of n.
Answer: A (8)
ⁿC₃ ÷ ⁿP₂ = [n!/(3!(n − 3)!)] × [(n − 2)!/n!] = (n − 2)/6 = 1, so n = 8.