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WAEC Further Mathematics 2013 Question 38

Question 38

Coordinate Geometry

Find the equation of the straight line that passes through (2, −3) and perpendicular to the line 3x − 2y + 4 = 0.

  1. A.2y − 3x = 0
  2. B.3y − 2x + 5 = 0
  3. C.3y + 2x + 5 = 0
  4. D.2y − 3x − 5 = 0
Show the answer and explanation

Answer: C (3y + 2x + 5 = 0)

Explanation

The given line has gradient 3/2, so the perpendicular has gradient −2/3: 3(y + 3) = −2(x − 2), i.e. 3y + 2x + 5 = 0.