Question 22
DynamicsThe distance in metres of a particle from a fixed point at time t seconds is given by s = 7 + pt3 + t2, where p is a constant. If the acceleration at t = 3 seconds is 8ms−2, find the value of p.
- A.1/3
- B.4/9
- C.5/9
- D.1
Show the answer and explanation
Answer: A (1/3)
Explanation
v = 3pt2 + 2t and a = 6pt + 2. At t = 3: 18p + 2 = 8, so p = 1/3.