Question 17
Gravitational FieldIf the radius of the earth is 6.4 × 106m, the escape velocity of a satellite from the earth is [g = 10ms−2]
- A.8.00 × 103ms−1.
- B.9.00 × 103ms−1.
- C.1.13 × 104ms−1.
- D.1.27 × 104ms−1.
Show the answer and explanation
Answer: C (1.13 × 104ms−1.)
Explanation
Escape velocity v = √(2gR) = √(2 × 10 × 6.4 × 106) = √(1.28 × 108) ≈ 1.13 × 104 m s−1.