Question 16
Work, Energy and PowerAn engine of a car of power 80 kW moves on a rough road with a velocity of 32 ms−1. The force required to bring it to rest is
- A.2.50 × 105 N.
- B.2.50 × 103 N.
- C.2.56 × 106 N.
- D.2.80 × 103 N.
Show the answer and explanation
Answer: B (2.50 × 103 N.)
Explanation
Power = force × velocity, so F = P/v = 80 000 ÷ 32 = 2500 N = 2.50 × 103 N.