Question 8
Equilibrium of ForcesA uniform metre rule weighing 0.5 N is to be pivoted on a knife-edge at the 30 cm-mark. Where will a force of 2 N be placed from the pivot to balance the metre rule?
- A.95 cm
- B.25 cm
- C.20 cm
- D.5 cm
Show the answer and explanation
Answer: D (5 cm)
Explanation
The weight acts at the 50 cm mark, 20 cm from the pivot: moment = 0.5 × 20 = 10 N cm. The 2 N force must be 10 ÷ 2 = 5 cm from the pivot on the other side.