Question 40
Current ElectricityThree electric cells each of e.m.f. 1.5 V and internal resistance 1.0 Ω are connected in parallel across an external resistance of 2/3 Ω. Calculate the value of the current in the resistor.
- A.0.5 A
- B.0.9 A
- C.1.5 A
- D.4.5 A
Show the answer and explanation
Answer: C (1.5 A)
Explanation
Identical cells in parallel give e.m.f. 1.5 V and internal resistance 1/3 Ω. I = 1.5 ÷ (2/3 + 1/3) = 1.5 A.